\(7^5:7^3-x=23\)

\(7^2-x=23\)

\(49-x=23\)

\(x=49-23\)

\(x=26\)

\(\left(2x-7\right).5^8=5^{10}\)

\(\left(2x-7\right)=5^{10}:5^8\)

\(2x-7=5^{10-8}\)

\(2x-7=5^2\)

\(2x-7=25\)

\(2x=32\)

\(x=32:2\)

\(x=16\)

* Mình nghĩ câu a sửa đề như vậy sẽ đúng hơn!

\(\left(2x+5\right).\left|-7\right|=73\)

\(\left(2x+5\right).7=73\)

\(\left(2x+5\right)=\frac{73}{7}\)

\(2x=\frac{73}{7}-5=\frac{38}{7}\)

\(x=\frac{38}{7}:2=\frac{19}{7}\)

  (2x+5).7=73

<=>2x.7+5.7=73

<=>14x+35=73

<=>14x=73-35

<=>14x=38

<=>x=38:14

=>x= 17/7

(2x+5) . l-7l = 73

=(2x+5) . 7 =73

=(2x+5)     =\(\frac{73}{7}\) 

=2x          =\(\frac{73}{7}\) - 5

=2x          =\(\frac{38}{7}\) 

=x           =\(\frac{38}{7}\) :2

=x           =\(\frac{19}{7}\)

(2x+5).|-7|=73

=> (2x+5).7=73

=> 2x+5=73:7

=> 2x+5=\(\frac{73}{7}\)

=>2x=\(\frac{73}{7}\)-5

=>2x=\(\frac{38}{7}\)

=>x=\(\frac{38}{7}\):2

=>x=\(\frac{19}{7}\)

vậy.....

Cảm ơn các bạn nhé !

a: Ta có: \(71-\left(x+33\right)=26\)

\(\Leftrightarrow x+33=45\)

hay x=12

b: Ta có: \(\left(x+73\right)-26=76\)

\(\Leftrightarrow x+73=102\)

hay x=29

c: Ta có: \(45-\left(x+9\right)=6\)

\(\Leftrightarrow x+9=39\)

hay x=30

a) 71 - ( 33 + x ) = 26

(33 + x ) = 71 -26

33 + x = 45

x        = 45 - 33 = 12

b) ( x + 73 ) - 26 = 76

    ( x + 73 )        = 102

    x                     = 102 - 73 = 29

c) 45 - ( x + 9 ) = 6

 ( x + 9 )           = 45 - 6 = 39

 x                      = 39 - 9 = 30

d) 89 - ( 73 - x ) = 20 

 73 - x  = 89 - 20

73 - x = 69

x          = 73 - 69 = 4

e) 4(x+41) = 400

   x + 41 = 400 : 4 = 100

   x = 100 - 41 = 59

f) 11(x-9 ) = 77

     x - 9 = 77 : 11 = 7

    x = 7 + 9 = 16

g) x + 7 = 25 + 13 = 38

    x = 38 - 7 = 31

h) x + 4 = 198 - 120 = 78

   x = 78 - 4 = 74

i) x - 9 = 350 : 5 = 70

   x = 70 + 9 = 79

j) 2x - 49 = 5 . 9 = 45

   2x = 45 + 49 = 94

   x = 94 : 2 = 47

k) 25 + 3( x - 8 ) = 106

    3(x-8 ) = 106 - 25 = 81

   x - 8 = 81 : 3 = 27 

x = 27 +8= 35

l) 9( x + 4 ) - 25 = 20

   9( x + 4 ) = 20 + 25 = 45

     x + 4 =45 : 9 = 5

   x = 5 - 4 = 1

m) 200 - ( 2x + 6 ) = 64

     2x + 6 = 200 - 64 = 136

   2x = 136 - 6 = 130

x = 130 : 2 = 65

n) 2(x-51) = 16 + 20 = 36

   x - 51 = 36 : 2 = 13

  x = 13 + 51 = 64

o) 450 : ( x - 19 ) = 50

  x - 19 = 450 : 50 = 9

x = 19 + 9 = 28

p)4(x-3) = 49 - 1 = 48

x - 3 = 48 : 4 = 12

x + 15

q) 156 - ( x+61 ) = 82

x + 61 = 156 - 82 = 74

x = 74 - 61 = 13

r) ( x - 35 ) - 120 = 0

x - 35 = 120

x = 120 + 35 = 155

x - 48 : 3 = 12          

x - 16 = 12

x = 12 + 16

x = 28

còn câu thứ 2 thì chia có dư bạn xem lại xem có chép sai đầu bài ko

Hoctot

a: Ta có: \(100-7\left(x-5\right)=58\)

\(\Leftrightarrow7\left(x-5\right)=42\)

\(\Leftrightarrow x-5=6\)

hay x=11

b: Ta có: \(12\left(x-1\right):3=4^3+2^3\)

\(\Leftrightarrow12\left(x-1\right)=216\)

\(\Leftrightarrow x-1=18\)

hay x=19

`#040911`

\(2^x+2^{x-3}-2^{x+5}=73\)

\(\Rightarrow2^x+2^x\div2^3-2^x\cdot2^5=73\\ \Rightarrow2^x+2^x\cdot\dfrac{1}{8}-2^x\cdot2^5=73\\ \Rightarrow2^x\cdot\left(1+\dfrac{1}{8}-2^5\right)=73\\ \Rightarrow2^x\cdot\left(-\dfrac{247}{8}\right)=73\\ \Rightarrow2^x=73\div\left(-\dfrac{247}{8}\right)\\ \Rightarrow2^x=-\dfrac{584}{247}\)

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