1.A
2.A
3.B
4.C
5.B
6.C
7.A
8.A
9.B
10.A
11.B
12.A
13.C
14.B
15.B
16.A
17.A
18.A
19.A
20.C

Độ dãn của lò xo:

\(F_{đh}=k\cdot\Delta l\Rightarrow\Delta l=\dfrac{F_{đh}}{k}=\dfrac{2}{100}=0,02\)m=2cm

B ... Thì lo xo dài 35cm tính f2

b)Lò xo dài 35cm.

   \(\Rightarrow\) Độ dãn của lò xo: \(\Delta l'=l'-l_0=35-30=5cm=0,05m\)

   \(F_2=k\cdot\Delta l'=100\cdot0,05=5N\)

mn làm đến câu H dòng 2 thôi nhá:)

g) 2³ . 5³ = 8 . 125 = 1000

Bạn sai cta nhé, sắp not xắp

Tham khảo

1. A special kind of tea is sold here 

2. All the cars and trucks have been searched 

3. He was put in prison by the goverment last years

4. We will be met by her parents at the station tomorrow 

5. A meeting is being held by Mr. Brown in the hall 

Bài 2 

1 Tea can't be made with cold water

2 Some of my books have been taken away.

3 Some pictures were taken away by the boys.

4 This room may be used for the classroom.

5 This machine mustn't be used after 5:30 p.m 

6 Mr Cole used to be visited at weekends by John.

7 All the homework ought to be done by her

đăng tách để mn cùng giúp bạn nhé 

a, \(A=10x^3y+4x^3-3xy^3\)

b, Thay x = 1 ; y = -1 ta được 

\(A=10.1.\left(-1\right)+4.1-3.1.\left(-1\right)=-10+4+3=-3\)

đề đâu bn??

......

Bài 5:

a, Áp dụng PTG: \(BC=\sqrt{AB^2+AC^2}=5\left(cm\right)\)

\(\sin B=\dfrac{AC}{BC}=\dfrac{3}{5}\approx\sin37^0\\ \Rightarrow\widehat{B}\approx37^0\\ \Rightarrow\widehat{C}\approx90^0-37^0=53^0\)

b, Áp dụng HTL: \(S_{AHC}=\dfrac{1}{2}AH\cdot HC=\dfrac{1}{2}\cdot\dfrac{AB\cdot AC}{BC}\cdot\dfrac{AC^2}{BC}=\dfrac{1}{2}\cdot\dfrac{12}{5}\cdot\dfrac{9}{5}=\dfrac{54}{25}\left(cm^2\right)\)

c, Vì AD là p/g nên \(\dfrac{DH}{DB}=\dfrac{AH}{AB}\)

Mà \(AC^2=CH\cdot BC\Leftrightarrow\dfrac{HC}{AC}=\dfrac{AC}{BC}\)

Mà \(AH\cdot BC=AB\cdot AC\Leftrightarrow\dfrac{AH}{AB}=\dfrac{AC}{BC}\)

Vậy \(\dfrac{DH}{DB}=\dfrac{HC}{AC}\)