a ) \(x^3-7x-6=x^3-x-6x-6=x^3-x-6\left(x+1\right)\)

\(=x\left(x^2-1\right)-6\left(x+1\right)=\left(x+1\right)\left[x\left(x-1\right)-6\right]\)

\(=\left(x+1\right)\left[\left(x^2-x-6\right)\right]=\left(x+1\right)\left[\left(x^2+2x-3x-6\right)\right]\)

\(=\left(x+1\right)\left[x\left(x+2\right)-3\left(x+2\right)\right]=\left(x+1\right)\left(x+2\right)\left(x+3\right)\)

b )

\(x^3-19x-30=\left(x^3-9x\right)-\left(10x+30\right)=x\left(x^2-9\right)-10\left(x+3\right)\)

\(=\left(x+3\right)\left(x^2-3x-10\right)=\left(x+2\right)\left(x+3\right)\left(x-5\right)\)

c )

\(a^3-6a^2+11a-6=\left(a-3\right)\left(a-2\right)\left(a-1\right).\)

a: =xy(x^2-4xy^2+4y^4)

=xy(x-2y^2)^2

b:=(x^3-y)^2

c: =(a^2-b^2)(a^2+b^2)

=(a^2+b^2)(a-b)(a+b)

d: 64x^6-27y^6

=(4x^2-3y^2)(16x^4+12x^2y^2+9y^4)

e: =(2x)^3+(3y)^3

=(2x+3y)(4x^2-6xy+9y^2)

a)\(x^3-x^2-14x+24=x^3-3x^2+2x^2-6x-8x+24\)

\(=x^2\left(x-3\right)+2x\left(x-3\right)-8\left(x-3\right)\)

\(=\left(x-3\right)\left(x^2+2x-8\right)\)

=\(\left(x-3\right)\left(x^2+4x-2x-8\right)=\left(x-3\right)\left(x-2\right)\left(x+4\right)\)

b)Tương tự câu a

c)\(x^3-7x+6=x^3-x^2+x^2-x-6x+6\)

=\(x^2\left(x-1\right)+x\left(x-1\right)-6\left(x+1\right)=\left(x+1\right)\left(x^2+x-6\right)\)

=\(\left(x+1\right)\left(x^2+3x-2x-6\right)\)

=\(\left(x+1\right)\left(x-2\right)\left(x+3\right)\)

d;e thương tự câu c

\(x^3+4x^2+4x+3\)

\(=\left(x^3+3x^2\right)+\left(x^2+3x\right)+\left(x+3\right)\)

\(=\left(x+3\right)\left(x^2+x+1\right)\)

Phân tích đa thức thành nhân tử à bạn?

thank bạn <3

Đề sai rồi nhé .... Bấm máy tính là biết.

mình làm 1 câu còn câu còn lại bạn tự làm nha giờ mình bận 

a) \(a^4+6a^2+11a+6\)

\(=a^3+a^2+5a^2+5a+6a+6\)

\(=a^2\left(a+1\right)+5a\left(a+1\right)+6\left(a+1\right)\)

\(=\left(a^2+5a+6\right)\left(a+1\right)\)

\(=\left(a^2+2a+3a+6\right)\left(a+1\right)\)

\(=\left[a\left(a+2\right)+3\left(a+2\right)\right]\left(a+1\right)\)

\(=\left(x+2\right)\left(x+3\right)\left(x+1\right)\)

a^4 mà chắc bài sai đề tks

\(a,x\left(x-3\right)=x^2-6\\ \Rightarrow x^2-3x-x^2=-6\\ \Rightarrow-3x=-6\\ \Rightarrow x=2\\ b,x^2-7x+12=0\\ \Rightarrow\left(x^2-3x\right)-\left(4x-12\right)=0\\ \Rightarrow x\left(x-3\right)-4\left(x-3\right)=0\\ \Rightarrow\left(x-3\right)\left(x-4\right)=0\\ \Rightarrow\left[{}\begin{matrix}x=3\\x=4\end{matrix}\right.\\ d,x^3-25x=0\\ \Rightarrow x\left(x^2-25\right)=0\\ \Rightarrow x\left(x-5\right)\left(x+5\right)=0\\ \Rightarrow\left[{}\begin{matrix}x0=\\x=5\\x=-5\end{matrix}\right.\)