1)Tính
\(A=\frac{11.3^2.9^9-9^{15}}{\left(2.3^{14}\right)^2}\)
2)Cho S=1+5+52+53+...........+599
Tìm x\(\in\)N để 4.S+1=5x
giúp nha
Tính
A=\(\frac{11.3^{22}.3^7-9^{15}}{\left(2.3^{14}\right)^2}\)
Tính :
A = \(\dfrac{11.3^{22}.3^7-9^{15}}{\left(2.3^{14}\right)^2}\)
A=\(\dfrac{11.3^{22}.3^7-9^{15}}{\left(2.3^{14}\right)^2}=\dfrac{11.3^{29}-3^{29}.3}{2^2.3^{28}}=\dfrac{3^{29}.\left(11-3\right)}{2^2.3^{28}}=\dfrac{3^{29}.2^3}{2^2.3^{28}}=3.2=6\)
\(A=\dfrac{11\cdot3^{22}\cdot3^7-9^{15}}{\left(2\cdot3^{14}\right)^2}=\dfrac{11\cdot3^{29}-3^{30}}{2^2\cdot3^{28}}\)
\(=\dfrac{3^{29}\cdot2^3}{3^{28}\cdot2^2}=3\cdot2=6\)
Tính :
a ) \(\frac{11.3^{22}.3^7-9^{15}}{\left(2.3^{14}\right)^2}\)
b ) 27^16 : 9^10
a ) \(\frac{11\cdot3^{22}\cdot3^7-9^{15}}{\left(2\cdot3^{14}\right)^2}=\frac{11\cdot3^{29}-\left(3^2\right)^{15}}{2^2\cdot3^{28}}\)
\(=\frac{3^{28}\left(11\cdot3-3^2\right)}{2^2\cdot3^{28}}=\frac{33-9}{4}=\frac{24}{4}=6\)
b ) \(27^{16}\div9^{10}\)
\(=\left(3^3\right)^{16}\div\left(3^2\right)^{10}\)
\(=3^{48}\div3^{20}\)
\(=3^{48-20}\)
\(=3^{28}\)
Bg
a) \(\frac{11.3^{22}.3^7-9^{15}}{\left(2.3^{14}\right)^2}\)
= \(\frac{11.3^{22}.3^7-3^{30}}{2^2.3^{28}}\)
= \(\frac{11.3^{29}-3.3^{29}}{4.3^{28}}\)
= \(\frac{8.3^{29}}{4.3^{28}}\)
= \(\frac{2.3}{1.1}\)
= 6
b) 2716 ÷ 910
= 33.16 ÷ 32.10
= 348 ÷ 320
= 348 - 20
= 328
Phần ghi kết quả
Câu 1 Kết quả của phép tính \(\frac{11.3^{29}-9^{15}}{\left(2.3^{14}\right)^2}\)
Câu 2 Tìm x biết / 2x - 3 / + 23 . 3 = 25
Câu 3 Tìm các chữ số x,y biết x183y chia cho 2,5 và 9 dư 1
Câu 4 Tìm các số nguyên n để B = \(\frac{n-1}{n-4}\)có giá trị nguyên
Câu 5 Tìm các số tự nhiên x,y biết ( 2x + 1 ) . ( y2 - 5 ) = 12
kết quả là: 6
x=1;2
x=7 y=0
n=1;3;5;7
x=1 y=3
1)\(\frac{11\cdot3^{29}-9^{15}}{\left(2\cdot3^{14}\right)^2}=6\)
2)\(|2x-3|+2^3\cdot3=25\Rightarrow x=1;2\)
3) \(x183y=61831\Rightarrow x=6;y=1\)
4)\(B=\frac{n-1}{n-4}\Rightarrow n=1;3;5;7\)
5)\(\left(2x+1\right)\cdot\left(y^2-5\right)=12\Rightarrow x=1;y=3\)
mình là người đúng nhất ở bài 3 vì 61831 mới chia 2,5,9 dư 1
k cho mình nhé
A = \(\frac{11.3^{22}.3^7-9^{15}}{\left(2.3^{14}\right)^2}\)
\(B=\frac{11.3^2^2.3^7-9^{15}}{\left(2.3^{14}\right)^2}\)
\(B=\frac{11.3^{29}-3^{30}}{2^2.3^{28}}=\frac{3^{29}.\left(11-3\right)}{4.3^{28}}=\frac{3^{29}.8}{4.3^{28}}=\frac{3.2.3^{28}.4}{4.3^{28}}=3.2=6\)
tính giá trị biểu thức :
A= \(\frac{11.3^{29}-9^{15}}{\left(2.3^{14}\right)^2}\)
ta co:A = 11.329-915/ (2.314)2
=11.329-(32)15/22.328
=11.329-330/22.328
=329.(11-3)/22.328
= 3.7/4
=21/4
\(\frac{11.3^{29}-9^{15}}{\left(2.3^{14}\right)^2}=\frac{11.3^{29}-\left(3^2\right)^{15}}{2^2.3^{28}}=\frac{11.3^{29}-3^{30}}{2^2.3^{28}}=\frac{3^{29}\left(11-3\right)}{2^2.3^{28}}=\frac{3^{29}.8}{2^2.2^{28}}=\frac{3^{29}.2^3}{3^{28}.2^2}=\frac{3.2}{1.1}=6\)
tính giá trị biểu thức
\(\frac{11.3^{22}.3^8-9^{15}}{\left[2.3^{14}\right]^2}\)
\(\left(11.3^7.9^7-9^{15}\right):\left(2.3^{14}\right)^2\)
\(=\dfrac{11\cdot3^{21}-3^{30}}{2^2\cdot3^{28}}=\dfrac{3^{21}\left(11-3^7\right)}{2^2\cdot3^{28}}=\dfrac{-2176}{2^2\cdot3^7}=\dfrac{-2176}{8748}=\dfrac{-544}{2187}\)