a: \(0.\left(13\right)=\dfrac{13}{99}\)

b: \(0,\left(4\right)+1,\left(4\right)=\dfrac{4}{9}+\dfrac{13}{9}=\dfrac{17}{9}\)

a. \(\dfrac{13}{99}\)

b.\(\dfrac{17}{9}\)

A=13/100

a) 0,333... = 3 . 0,111... = \(3.\frac{1}{9}=\frac{1}{3}\)

b) 0,454545... = 45 . 0,010101... = \(45.\frac{1}{99}=\frac{5}{11}\)

c) 0,162162... = 162 . 0,001001... = \(162.\frac{1}{999}=\frac{6}{37}\)

d) 5,272727... = 5 + 0,272727... = \(5+27.\frac{1}{99}=5\frac{3}{11}\)

\(a)\)

\(0,333...=3.0,111...=3.\frac{1}{9}=\frac{1}{3}\)

\(b)\)

\(0,454545...=45.0,010101...=45.\frac{1}{99}=\frac{5}{11}\)

\(c)\)

\(0,162162...=162.0,001001...=162.\frac{1}{999}=\frac{6}{37}\)

\(d)\)

\(5,272727...=5+0,272727...=5+27.\frac{1}{99}=5\frac{3}{11}\)

Câu 1: 

\(\dfrac{24}{10}=2.4\)

\(\dfrac{225}{100}=2.25\)

\(\dfrac{6453}{1000}=6.453\)

\(\dfrac{25789}{10000}=2.5789\)

a) \(\frac{{37}}{{100}} = 0,37\);  \(\frac{{ - 34517}}{{1000}} =  - 34,517\)

\(\frac{{ - 254}}{{10}} =  - 25,4\);   \(\frac{{ - 999}}{{10}} =  - 99,9\)

b) \(2 = \frac{2}{1}\);     \(2,5 = \frac{{25}}{{10}}\)

\( - 0,007 = \frac{{ - 7}}{{1000}}\);    \( - 3,053 = \frac{{ - 3053}}{{1000}}\)

\( - 7,001 = \frac{{ - 7001}}{{1000}}\);   \(7,01 = \frac{{701}}{{100}}\).

lỗi

:v

 Bài 1 
\(\dfrac{6}{5}\)=\(1\dfrac{1}{5}\)
\(\dfrac{7}{3}\)=\(2\dfrac{1}{3}\)
\(-\dfrac{16}{11}\)=\(-1\dfrac{5}{11}\)
Bài 2 : 
\(5\dfrac{1}{7}\)=\(\dfrac{5.7+1}{7}\)=\(\dfrac{36}{7}\)( Dấu " . " là dấu nhân )
\(6\dfrac{3}{4}\)=\(\dfrac{6.4+3}{4}\)=\(\dfrac{27}{4}\)
\(-1\dfrac{12}{13}\)=\(-\dfrac{25}{13}\)
Bài 3 :

Chuyển phân số về hỗn số

Bài 4 :
Sorry Mình không biết làm:(
Bài 5 :
7%=\(\dfrac{7}{100}\)
45%=\(\dfrac{9}{20}\)
216%=\(\dfrac{54}{25}\)
Bài 6 :
\(\dfrac{3}{7}\)=\(\dfrac{7}{3}\)
\(6\dfrac{1}{3}\)=\(\dfrac{19}{3}\)=\(\dfrac{3}{19}\)
\(\dfrac{-1}{12}\)=\(\dfrac{-12}{1}\)
Bài 7 :
 

Bài 5:

\(\dfrac{3}{4}=\dfrac{x}{20}=\dfrac{21}{y}\)

=>\(\left\{{}\begin{matrix}\dfrac{x}{20}=\dfrac{3}{4}\\\dfrac{21}{y}=\dfrac{3}{4}\end{matrix}\right.\)

=>\(\left\{{}\begin{matrix}x=20\cdot\dfrac{3}{4}=15\\y=21\cdot\dfrac{4}{3}=7\cdot4=28\end{matrix}\right.\)

Bài 4:

a: \(\dfrac{3}{5}=\dfrac{3\cdot9}{5\cdot9}=\dfrac{27}{45}\)

b: Đề sai rồi bạn

Bài 3:

a: \(21\cdot21=441\)

\(49\cdot9=441\)

=>\(21\cdot21=49\cdot9\)

=>\(\dfrac{21}{9}=\dfrac{49}{21}\)

b: \(\dfrac{-24}{34}=\dfrac{-24:2}{34:2}=\dfrac{-12}{17}\)

\(\dfrac{-60}{85}=\dfrac{-60:5}{85:5}=\dfrac{-12}{17}\)

Do đó: \(\dfrac{-24}{34}=\dfrac{-60}{85}\)

Bài 2:

\(15cm=\dfrac{3}{20}m\)

\(40mm=\left(\dfrac{40}{1000}\right)m=\dfrac{1}{25}m\)

Bài 1:

a: \(\left(-17\right):8=\dfrac{-17}{8}\)

b: \(\left(-8\right):\left(-9\right)=\dfrac{-8}{-9}\)

a)

b)  7 n 2 + 21 n 56 n = 7 n ( n + 3 ) 7 n .8 = n + 3 8

Vậy phân số 7 n 2 + 21 n 56 n viết được dưới dạng số thập phân hữu hạn vì 7 n 2 + 21 n 56 n = 7 n ( n + 3 ) 7 n .8 = n + 3 8 có mẫu là 8 = 2 3 không có ước nguyên tố khác 2 và 5 (với n là số nguyên)

\(a,-\dfrac{10}{21}=\dfrac{-2}{7}.\dfrac{5}{3}=\dfrac{-2}{3}.\dfrac{5}{7}\\ b,\dfrac{2}{21}=\dfrac{1}{3}.\dfrac{2}{7}=\dfrac{1}{7}.\dfrac{2}{3}\\ c,\dfrac{8}{15}=\dfrac{2}{3}.\dfrac{4}{5}=\dfrac{4}{3}.\dfrac{2}{5}\)