\(\dfrac{60}{81}< \dfrac{60}{80}\) và \(\dfrac{21}{25}>\dfrac{20}{25}\)

=> \(\dfrac{60}{80}=\dfrac{3}{4}\) và \(\dfrac{20}{25}=\dfrac{4}{5}\) => \(\dfrac{4}{5}>\dfrac{3}{4}\)

\(=>\dfrac{21}{25}>\dfrac{20}{25}>\dfrac{60}{80}>\dfrac{60}{81}\)

Vậy \(\dfrac{21}{25}>\dfrac{60}{81}\)

21/25>60/81

Ta có \(\dfrac{21}{25}>\dfrac{21}{27}\), lại có \(\dfrac{60}{81}=\dfrac{20}{27}< \dfrac{21}{27}\) nên \(\dfrac{21}{25}>\dfrac{60}{81}\)

\(\frac{21}{25};\frac{60}{81};\frac{19}{29}\)

Đúng 100% Chúc bạn zui ~^^

thankyou bạn

\(\frac{21}{25};\frac{60}{81};\frac{19}{29}\)

.................

k mk na 

hai phân số nào em nhở?

và phân số nào nữa?

b)21/27<21/25<23/25

21/25

19/29

60/81

\(\dfrac{12}{19}< \dfrac{23}{25}\)

\(\dfrac{21}{27}< \dfrac{23}{25}\)

\(\dfrac{12}{19}< \dfrac{23}{25};\dfrac{21}{27}< \dfrac{23}{25}\)

a) \(\dfrac{12}{19}=\dfrac{19}{19}-\dfrac{7}{19}=1-\dfrac{7}{19}\)

\(\dfrac{23}{25}=\dfrac{25}{25}-\dfrac{2}{25}=1-\dfrac{2}{25}\).

-So sánh: \(\dfrac{7}{19}\) và \(\dfrac{2}{25}\).

\(\dfrac{7}{19}=\dfrac{14}{38};\dfrac{2}{25}=\dfrac{14}{175}\Rightarrow\dfrac{7}{19}>\dfrac{2}{25}\left(\dfrac{14}{38}>\dfrac{14}{175}\right)\)

\(\Rightarrow1-\dfrac{7}{19}< 1-\dfrac{2}{25}\) 

\(\Rightarrow\dfrac{12}{19}< \dfrac{23}{25}\)

-Câu b làm tương tự bạn nhé.

Cần nhớ:

\(\frac{a}{b}< 1\Rightarrow\frac{a}{b}< \frac{a+n}{b+n}\left(n\inℕ^∗\right)\)

\(\frac{a}{b}>1\Rightarrow\frac{a}{b}>\frac{a+n}{b+n}\left(n\inℕ^∗\right)\)

Ta thấy:

\(\frac{19}{29}< 1\Rightarrow\frac{19}{29}< \frac{19+1}{29+1}=\frac{20}{30}=\frac{2}{3}\)

Ta lại có:

\(\frac{2}{3}=\frac{2.7}{3.7}=\frac{14}{21}< 1\Rightarrow\frac{14}{21}< \frac{14+6}{21+6}=\frac{20}{27}=\frac{20.3}{27.3}=\frac{60}{81}\)

\(\Rightarrow\frac{19}{29}< \frac{60}{81}\)     (1)

Ta có:

\(\frac{60}{81}=\frac{20}{27}< 1\Rightarrow\frac{20}{27}< \frac{20+1}{27+1}=\frac{21}{28}< \frac{21}{25}\)

=>\(\frac{60}{81}< \frac{21}{25}\)     (2)

Từ (1) và (2) => \(\frac{19}{29}< \frac{60}{81}< \frac{21}{25}\)