((6x - 39( : 7) x 4 = 12
tìm x: [(6x-39):7].4=12
\(\left[\left(6x-39\right):7\right].4=12\)
\(=>\left(6x-39\right):7=12:4\)
\(=>\left(6x-39\right):7=3\)
\(=>6x-39=3.7\)
\(=>6x-39=21\)
\(=>6x=21+39\)
\(=>6x=60\)
\(=>x=60:6\)
\(=>x=10\)
[(6x - 39) : 7] . 4 = 12
(6x - 39) : 7 = 12 : 4
(6x - 39) : 7 = 3
6x - 39 = 3 . 7
6x - 39 = 21
6x = 21 + 39
6x = 60
x = 60 : 6
x = 10
tìm x biết ;
[(6x - 39 ) :7] .4 = 12
(x:3-4).5 = 15
9.3x+1 = 81
[ ( 6 . x - 39 ) : 7 ] . 4 = 12
[ ( 6 . x - 39 ) : 7 ] = 12 : 4
( 6 . x - 39 ) : 7 = 3
6 . x - 39 = 3 . 7
a) (x : 3 - 4) . 5 = 15
x : 3 - 4 = 15 : 5
x : 3 - 4 = 3
x : 3 = 3 + 4
x : 3 = 7
x = 7 . 3
x = 21.
6 . x - 39 = 21
6 . x = 21 + 39
6 . x = 60
x = 60 : 6
x = 10
Vậy x = 10
9.3x+1 = 81
= 81
[(6x-39):7].4=12 (x:3-4).5=15 9.3x+1=81
(6x-39):7 =12:4=3 x:3-4 =15:5=3 27x+1=81
6x-39 =3.7 =21 x:3 =3+4=7 x+1=81:27=3
6x =21+39=60 x =7.3=21 x =3-1=2
x =60:6 =10
a) 128 - 3 .( x + 4 ) = 23
b) [ ( 6x - 39 ) : 7 ] . 4 = 12
a) 128 - 3( x + 4 ) = 23
<=> 3x + 12 = 128 - 23 =105
<=> 3x = 105 - 12 = 93
<=> x = 31
b) [ ( 6x - 39 ) : 7 ] . 4 =12
<=> ( 6x - 39 ) : 7 = 12 / 4 =3
<=> 6x - 39 = 3 . 7 =21
<=> 6x = 21 + 39 = 60
<=> x =10
a) x-7=-5
b) 128-3.(x+4)=23
c) [(6x - 39) : 7].4=12
d (x:3-4).5=15
Bài làm
a) x - 7 = 5 b) 128 - 3 . ( x + 4 ) = 23
x = 5 + 7 3 . ( x + 4 ) = 128 - 23
x = 12 3 . ( x + 4 ) = 105
Vậy x = 12 x + 4 = 105 : 3
x + 4 = 35
x = 35 - 4
x = 31
Vậy x = 31
c) [ ( 6x - 39 ) : 7 ] . 4 = 12 d) ( x : 3 - 4 ) . 5 = 15
( 6x - 39 ) : 7 = 12 : 4 x : 3 - 4 = 3 ( chỗ này là làm tắt của x : 3 - 4 = 15 : 5 )
( 6x - 39 ) : 7 = 3 x : 3 = 3 + 4
6x - 39 = 3 . 7 x : 3 = 7
6x - 39 = 21 x = 7 . 3
6x = 21 + 39 x = 21
6x = 60 Vậy x = 21
x = 60 : 6
x = 10
Vậy x = 10
# Chúc bạn học tốt #
x - 7 = -5
x = -5 + 7
x = 2
Vậy x = 2
128 - 3.( x + 4 ) = 23
3.( x + 4 ) = 128 - 23
3.( x + 4 ) = 105
x + 4 = 105 : 3
x + 4 = 35
x = 35 - 4
x = 31
Vậy x = 31
[ ( 6x - 39 ) : 7 ] . 4 = 12
[ ( 6x - 39 ) : 7 ] = 12 : 4
[ ( 6x - 39 ) : 7 ] = 3
( 6x - 39 ) : 7 = 3
6x - 39 = 3 x 7
6x - 39 = 21
6x = 21 + 39
6x = 60
x = 10
Vậy x = 10
( x : 3 - 4 ) . 5 = 15
x : 3 - 4 = 15 : 5
x : 3 - 4 = 3
x : 3 = 3 + 4
x : 3 = 7
x = 21
Vậy x = 21
Tim x
[(6x-39):7].4=12
Giup cho minh,minh like cho
[(6x-39):7]x4=12
[(6x-39):7]=12:4=3
(6x-39)=3x7=21
6x=21+39=60
x=60:6=10
tìm x, biết :
[ (6x - 39 ) : 7 ] . 4 = 12
( x : 3 - 4 ). 5 = 15
x - [ 42 + ( -28 ) ] = -8
[ ( 6x - 39 ) : 7 ] . 4 = 12
=> ( 6x - 39 ) : 7 = 12 : 4
=> ( 6x - 39 ) : 7 = 3
=> 6x - 39 = 3.7
=> 6x - 39 = 21
=> 6x = 21+39
=> 6x = 60
=> x = 10.
( x : 3 - 4 ) . 5 = 15
=> x : 3 - 4 = 15 : 5
=> x : 3 - 4 = 3
=> x : 3 = 7
=> x = 7.3
=> x = 21
x - [ 42 + (-28) ] = -8
=> x - 14 = -8
=> x = -8 + 14
=> x = 6.
[ (6x - 39): 7] . 4=12
(6x-39) : 7=12:4
(6x -39) :7=3
(6x-39) =3 . 7
6x-39 =21
6x =21 +39
6x=20
x=10
(x :3 -4) .5 =15
(x : 3 -4) =15:5
x:3-4 =3
x : 3=3+4
x:3 =7
x=7 . 3
x=21
[(6x-39):7].4=12. (X-47)-115=0
(6x-39):7 = 12:4=3
6x-39 = 3 x 7 = 21
6x = 21+39 = 60
x = 60:6 = 10
X-47 = 0+115 = 115
X = 115+47 = 162
k mk nha
Tìm x thuộc Z:
a) [(6x - 39) : 7] . 4 = 12
b) (x : 3 - 4) . 5 = 15
c) |x - 5| = |7|
a.[(6x-39):7].4=12
(6x-39):7=12:4
(6x-39):7=3
(6x-39)=3.7
6x-39=21
6x=21+39
6x=60
x=10
vậy x=10
b.(x:3-4).5=15
x:3-4=15:5
x:3-4=3
x:3=3+4
x:3=7
x=7.3
x=21
vậy x=21
c.\(\left|x-5\right|=\left|7\right|\)
\(\left|x-5\right|=7\)
\(\Rightarrow\left[{}\begin{matrix}x-5=7\\x-5=-7\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=7+5\\x=-7+5\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=12\\x=-2\end{matrix}\right.\)
vậy x\(\in\left\{12;-2\right\}\)
a ) [( 6x - 39 ) : 7 ] . 4 = 12
=> [( 6x - 39 ) : 7 ] = 12 : 4
=> [( 6x - 39 ) : 7 ] = 3
=> 6x - 39 = 3 . 7
=> 6x - 39 = 21
=> 6x = 21 + 39
=> 6x = 60
=> x = 60 : 6
=> x = 10
Vậy x = 10
b) ( x : 3 - 4 ) . 5 = 15
=> x : 3 - 4 = 15 : 5
=> x : 3 - 4 = 3
=> x : 3 = 3 + 4
=> x : 3 = 7
=> x = 7.3
=> x = 21
Vậy x = 21
c) |x-5|=|-7 |
=> |x-5|=7 Vì giá trị tuyệt đối của -7 là 7
=》 x-5=7
=》 x =7+5
=> x =12
tìm x
a) x -7 = - 5
b) 128 - 3 . ( x + 4 ) = 23
c) [ ( 6x - 39 ) : 7 ] . 4 = 12
d) ( x : 3 - 4 ) . 5 = 15
cac ban oi giai giup minh nhe cam on
a) x - 7 = -5
=> x = -5 + 7
=> x = 2
b) 128 - 3 . (x + 4) = 23
=> 3.( x + 4) = 128 - 23
=> 3.( x + 4) = 105
=> x + 4 = 105 : 3
=> x + 4 = 35
=> x = 35 - 4
=> x = 31
c) [ ( 6x - 39 ) : 7 ].4 = 12
( 6x -39) : 7 = 12 :4
=> ( 6x - 39 ): 7 = 3
=> 6x - 39 = 3 x 7
=> 6x - 39 = 21
=> 6x = 21 + 39
=> 6x = 60
=> x = 60: 6
=> x = 10
d) ( x: 3 - 4) , 5 = 15
=> x: 3 - 4 = 15 : 5
=> x : 3 - 4 = 3
=> x: 3 = 3+4
=> x: 3 = 7
=> x = 7x 3
=> x =21
a) x -7=-5
x=-5 +7
x=2
b)128-3.(x+4)=23
3.(x+4)=128-23
3.(x+4)=105
x+4=105:3
x+4=35
x=35-4
x=31
c)[(6x-39):7].4=12
(6x-39):7=12:4
(6x-39):7=3
6x-39 =3.7
6x-39 =21
6x =21+39
6x =60
x =60:6
x =10
d)(x:3-4).5=15
x:3-4. =15:5
x:3-4 =3
x:3 =3+4
x:3 =7
x =7.3
x =21
Ai thấy đúng k mk nha