Bài 1: 

a) 0²⁰⁰² < 0²⁰²³

b) 2022⁰ = 2023⁰

c) 54⁹ < 55¹⁰

d) ( 4 + 5 )³ > 4² + 5²

đ) 9² - 3² > ( 9 - 3 )²

Bài 2:

a) 3² x 4³ - 3² + 333

= 9 x 64 - 9 + 333

= 576 - 9 + 333

= 567 + 333

= 900

b) 5 x 4³ + 24 x 5 + 41⁰

= 5 x 64 + 24 x 5 + 1

= 5 x ( 64 + 24 ) + 1

= 5 x 88 + 1

= 440 + 1

= 441

c) 2³ x 4² + 3² x 5 - 40 x 1²⁰²³

= 8 x 16 + 9 x 5 - 40 x 1

= 128 + 45 - 40

= 133

Bài 1 :

a) \(0^{2002}=0;0^{2023}=0\Rightarrow0^{2002}=0^{2023}\)

b) \(2022^0=1;2023^0=1\Rightarrow2022^0=2023^0\)

c) \(54^9< 55^9;55^9< 55^{10}\Rightarrow54^9< 55^{10}\)

d) \(\left(4+5\right)^3>\left(4+5\right)^2;\left(4+5\right)^2>4^2+5^2\Rightarrow\left(4+5\right)^3>4^2+5^2\)

đ) \(9^2-3^2=81-9=82;\left(9-3\right)^2=6^2=36\Rightarrow9^2-3^2>\left(9-3\right)^2\)

Bài 2 :

a) \(3^2.4^3-3^2+333=3^2\left(4^3-1\right)+9.37=9.63+9.37=9\left(63+37\right)=9.100=900\)

b) \(5.4^3+24.5+41^0=20.4^2+20.6+1=20\left(16+6\right)+1=20.22+1=441\)

c) \(2^3.4^2+3^2.5-40.1^{2023}=8.16+9.5-40.1=128+45-40=128+5=133\)

`(2^x+1)^2 =25`

`=> (2^x+1)^2 = (+-5)^2`

\(\Rightarrow\left[{}\begin{matrix}2^x+1=5\\2^x+1=-5\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}2^x=4\\2^x=-6\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=2\\x\in\varnothing\end{matrix}\right.\)

\(\left(x+6\right)\left(5^x-1\right)=0\)

\(\Rightarrow\left[{}\begin{matrix}x+6=0\\5^x-1=0\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=-6\\5^x=1\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=-6\\x=0\end{matrix}\right.\)

\(\left(x-3\right)^{2023}=x-3\)

\(\Rightarrow\left(x-3\right)^{2023}-\left(x-3\right)=0\)

\(\Rightarrow\left(x-3\right)\left[\left(x-3\right)^{2022}-1\right]=0\)

\(\Rightarrow\left[{}\begin{matrix}x-3=0\\\left(x-3\right)^{2022}-1=0\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=3\\\left(x-3\right)^{2022}=1\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=3\\x-3=1\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=3\\x=4\end{matrix}\right.\)

`#3107.101107`

1.

`(2^x + 1)^2 = 25`

`=> (2^x + 1)^2 = (+-5)^2`

`=>`\(\left[{}\begin{matrix}2^x+1=5\\2^x+1=-5\end{matrix}\right.\)

`=>`\(\left[{}\begin{matrix}2^x=4\\2^x=-6\left(\text{vô lý}\right)\end{matrix}\right.\)

`=>`\(\left[{}\begin{matrix}x=2\\x\in\varnothing\end{matrix}\right.\)

Vậy, `x =2.`

2.

`(x + 6)(5x - 1) = 0`

`=>`\(\left[{}\begin{matrix}x+6=0\\5x-1=0\end{matrix}\right.\)

`=>`\(\left[{}\begin{matrix}x=-6\\5x=1\end{matrix}\right.\)

`=>`\(\left[{}\begin{matrix}x=-6\\x=\dfrac{1}{5}\end{matrix}\right.\)

Vậy, `x \in {-6; 1/5}`

3.

`2*3^(x + 3) + 3^(2 + x) = 891`

`=> 2* 3^x * 3^3 + 3^2 * 3^x = 891`

`=> 54*3^x + 9*3^x = 891`

`=> 3^x * (54 + 9) = 891`

`=> 3^x * 63 = 891`

`=> 3^x = 891 \div 63`

`=> 3^x = 891/63`

Bạn xem lại đề.

4.

`(x - 3)^2023 = x - 3`

`=> (x - 3)^2023 - (x - 3) = 0`

`=> (x - 3) * [ (x - 3)^2022 - 1] = 0`

`=>`\(\left[{}\begin{matrix}x-3=0\\\left(x-3\right)^{2022}-1=0\end{matrix}\right.\)

`=>`\(\left[{}\begin{matrix}x=3\\\left(x-3\right)^{2022}=1\end{matrix}\right.\)

`=>`\(\left[{}\begin{matrix}x=3\\\left(x-3\right)^{2022}=\left(\pm1\right)^{2022}\end{matrix}\right.\)

`=>`\(\left[{}\begin{matrix}x=3\\x-3=1\\x-3=-1\end{matrix}\right.\)

`=>`\(\left[{}\begin{matrix}x=3\\x=4\\x=2\end{matrix}\right.\)

Vậy, `x \in {2; 3; 4}.`

A = 2^3 + 2^4+ 2^5+ 2^6 + 2^7 + ... + 2^90 

2A = 2^4 + 2^5 + 2^6 + 2^7 + 2^8 + .... + 2^90 + 2^100

2A - A = ( 2^4 + 2^5 + 2^6 + 2^7 + 2^8 + .... + 2^90 + 2^100 ) - (  2^3 + 2^4+ 2^5+ 2^6 + 2^7 + ... + 2^90 ) 

A = 2^100 - 2^3 

B = 1 + 5 + 5^2 + 5^3 + 5^4 + .... + 5^50 

5B = 5 + 5^2 + 5^3 + 5^4 + 5^5 + .... + 5^50 + 5^51 

5B - B = ( 5 + 5^2 + 5^3 + 5^4 + 5^5 + .... + 5^50 + 5^51 ) - ( 1 + 5 + 5^2 + 5^3 + 5^4 + .... + 5^50 )

4B = 5^51 - 1 

B = 5^51 - 1 / 4

Em nên viết bằng công thức toán học em nhé, như vậy sẽ giúp mọi người hiểu đề đúng và hỗ trợ tốt nhất cho em!

a: =5-78*32

=5-2496

=-2491

b: \(=6\left(9-6\right)=6\cdot3=18\)

c: \(=46\cdot\dfrac{\left(123-42\right)}{81}=46\)

d: \(=181+3-84+8\cdot25\)

=100+200

=300

e: \(=64\cdot35+140\cdot84-1=2240-1+11760\)

=14000-1

=13999

f: \(=3^3+25\cdot8-1=26+200=226\)

g: \(=3+2^4+1=16+4=20\)

h: \(=36:4\cdot3+2\cdot25-1=27+50-1=27+49=76\)

1; 7³.5².5⁴.7⁶:(5⁵.7⁸)

= (7³.7⁶).(5².5⁴) : (5⁵.7⁸)

= 7⁹.5⁶: (5⁵.7⁸)

= (7⁹:7⁸).(5⁶:5⁵)

= 7.5

= 35

2; 3³.a⁷.3.a²:(3⁴.a⁶)

= (3³.3).(a⁷.a²): (3⁴.a⁶)

= 3⁴.a⁹: (3⁴.a⁶)

= (3⁴:3⁴).(a⁹:a⁶)

= a³

3; 7³.11⁴.a⁸.b⁷: 7².11².a⁵.b⁶

=  (7³:7²).(11⁴.11²).(a⁸.a⁵).(b⁷.b⁶)

= 7.11⁶.a¹³.b¹³

Bài 8:

a: \(\left(\dfrac{2}{5}+\dfrac{3}{4}\right)^2=\left(\dfrac{8+15}{20}\right)^2=\left(\dfrac{23}{20}\right)^2=\dfrac{529}{400}\)

b: \(\left(\dfrac{5}{4}-\dfrac{1}{6}\right)^2=\left(\dfrac{15}{12}-\dfrac{2}{12}\right)^2=\left(\dfrac{13}{12}\right)^2=\dfrac{169}{144}\)