Sửa đề: Tìm x
a: \(x\left(6-x\right)^{2023}=\left(6-x\right)^{2023}\)
=>\(x\left(6-x\right)^{2023}-\left(6-x\right)^{2023}=0\)
=>\(\left(6-x\right)^{2023}\left(x-1\right)=0\)
=>\(\left[\begin{array}{l}6-x=0\\ x-1=0\end{array}\right.\Rightarrow\left[\begin{array}{l}x=6\\ x=1\end{array}\right.\)
b: \(5^{x}+5^{x+2}=650\)
=>\(5^{x}+5^{x}\cdot25=650\)
=>\(5^{x}\left(1+25\right)=650\)
=>\(5^{x}=\frac{650}{26}=25=5^2\)
=>x=2
c: \(2^{x+2}-2^{x}=96\)
=>\(2^{x}\cdot2^2-2^{x}=96\)
=>\(2^{x}\left(2^2-1\right)=96\)
=>\(2^{x}\cdot3=96\)
=>\(2^{x}=\frac{96}{3}=32=2^5\)
=>x=5
d: \(10^{x}:5^{y}=20^{y}\)
=>\(10^{x}=20^{y}\cdot5^{y}=100^{y}=\left(10\right)^{2y}\)
=>x=2y
