Tìm x:
x^99 - x^97 = 0
X+1/99+x+2/98+x+3/97+x+4/96=0
Tìm x
An
Ai lam2 mk cũng tk hết
x+1/99+x+2/98+x+3/97+x+4/96=0
=> 4x+(1/99+2/98+3/97+4/96)=0
=> x=-0,025775918
\(\frac{x-99-1}{99}-\frac{x-99-1}{98}-\frac{x-99-1}{97}-\frac{x-99-1}{96}-\frac{x-99-1}{95}-\frac{x-99-1}{94}\)=0
Ta có :
\(\frac{x-99-1}{99}-\frac{x-99-1}{98}-\frac{x-99-1}{97}-\frac{x-99-1}{96}-\frac{x-99-1}{95}-\frac{x-99-1}{94}=0\)
\(\Leftrightarrow\)\(\frac{x-100}{99}-\frac{x-100}{98}-\frac{x-100}{97}-\frac{x-100}{96}-\frac{x-100}{95}-\frac{x-100}{94}=0\)
\(\Leftrightarrow\)\(\left(x-100\right)\left(\frac{1}{99}-\frac{1}{98}-\frac{1}{97}-\frac{1}{96}-\frac{1}{95}-\frac{1}{94}\right)=0\)
Vì \(\frac{1}{99}-\frac{1}{98}-\frac{1}{97}-\frac{1}{96}-\frac{1}{95}-\frac{1}{94}\ne0\)
Nên \(x-100=0\)
\(\Rightarrow\)\(x=100\)
Vậy \(x=100\)
Bài làm mang tính chất tham khảo vì em mới lớp 7 ~
x-1/99+x-2/98+x-3/97+x-4/96-4=0
(201-x)/99 +(203- x)/97+ (205 - x)/95 + 3 = 0
201-x/99 + 205-x/95 + 203-x/97 + 3 = 0
Giải:
Ta có: \(\frac{201-x}{99}+\frac{205-x}{95}+\frac{203-x}{97}+3=0\)
\(\Leftrightarrow\frac{201-x}{99}+1+\frac{205-x}{95}+1+\frac{203-x}{97}+1=0\)
\(\Leftrightarrow\frac{300-x}{99}+\frac{300-x}{95}+\frac{300-x}{97}=0\)
\(\Leftrightarrow\left(300-x\right)\left(\frac{1}{99}+\frac{1}{95}+\frac{1}{97}\right)=0\)
\(\Leftrightarrow300-x=0\) (Vì \(\frac{1}{99}+\frac{1}{95}+\frac{1}{97}\ne0\))
\(\Leftrightarrow x=300\)
Vậy phương trình có nghiệm là \(x=300.\)
Chúc bạn học tốt@@
201-x/99+203-x/97+205-x/96+3=0
( 201 - x)/99 + (203 - x)/97 + (205 - x)/95 + 3 = 0
<=> (300-x)/99+(300-x)/97+(300-x)/95=0
<=> (300-x)(1/99+1/97+1/95)=0
=> 300-x=0 vì 1/99+1/97+1/95 khác 0
=> x=300
Vậy x=300
\(\dfrac{201-x}{99}+\dfrac{203-x}{97}=\dfrac{205-x}{95}+3=0\)
`(201-x)/99+(203-x)/97+(205-x)/95+3=0`
`<=>(201-x)/99+1+(203-x)/97+1+(205-x)/95+1=0`
`<=>(300-x)/99+(300-x)/97+(300-x)/95=0`
`<=>(300-x)(1/99+1/97+1/95)=0`
`<=>300-x=0`
`<=>x=300`
Vậy `x=300`
Vì 205-x/95+3=0
=>205-x/95=0-3=-3
=>205-x=-3*95=-285
=>x=205-(-285)=490
Vậy x=490
\(\dfrac{201-x}{99}\)+\(\dfrac{203-x}{97}\)+\(\dfrac{205-x}{95}\)+3=0
\(\Leftrightarrow\left(\dfrac{201-x}{99}+1\right)+\left(\dfrac{203-x}{97}+1\right)+\left(\dfrac{205-x}{95}+1\right)=0\)
=>300-x=0
=>x=300
<=> 300-x/99+300-x/97+300-x/95=0
<=>(300-x).(1/99+1/97+1/95)=0
<=>300-x=0
<=>x=300
tìm x biết:
\(\frac{x-1}{99}-\frac{x+1}{101}+\frac{x-2}{98}-\frac{x+2}{102}+\frac{x-3}{97}-\frac{x+3}{103}+\frac{x-4}{96}-\frac{x+4}{104}=0\)