Question

\(\dfrac{201-x}{99}\)+\(\dfrac{203-x}{97}\)+\(\dfrac{205-x}{95}\)+3=0

Answer 1

\(\Leftrightarrow\left(\dfrac{201-x}{99}+1\right)+\left(\dfrac{203-x}{97}+1\right)+\left(\dfrac{205-x}{95}+1\right)=0\)

=>300-x=0

=>x=300

Answer 2

<=> 300-x/99+300-x/97+300-x/95=0

<=>(300-x).(1/99+1/97+1/95)=0

<=>300-x=0

<=>x=300