a) 9.(2x+3)^2 - 4.(x+1)^2
b) x^2/4 +2xy +4y^2
c) -4x^2 +12xy - 9y^2 +25
d) 25x^4 -10x^2y +y^2
GIÚP MIK DZỚI
ĐANG CẦN GẤP LẮM ẠK!!!
bài 1: phân tích các đa thức thành nhân tử:
a)x(3-4x)+5(3-4x)
b)2y(5y-6)-4(6-5y)
c)27(x-2)^3-3x(2-x)^2
d)6y(x^2-y^2)-8y(x+y)^2
bài 2:
a)2x^2-xy+2xz-yz
b)x^2-x+2y-4y^2
c)y^2+10y-9z^2+25
d) (x+2y)^3-x^2+4y^2
giúp mik nhé mik cần gấp ạ
2:
a: \(=\left(2x^2-xy\right)+\left(2xz-yz\right)\)
\(=x\left(2x-y\right)+z\left(x-2y\right)=\left(x-2y\right)\left(x+z\right)\)
b: \(=\left(x^2-4y^2\right)-\left(x-2y\right)\)
\(=\left(x-2y\right)\left(x+2y\right)-\left(x-2y\right)\)
\(=\left(x-2y\right)\left(x+2y-1\right)\)
c: \(=\left(y^2+10y+25\right)-9z^2\)
\(=\left(y+5\right)^2-\left(3z\right)^2\)
\(=\left(y+5+3z\right)\left(y+5-3z\right)\)
d: \(=\left(x+2y\right)^3-\left(x-2y\right)\left(x+2y\right)\)
\(=\left(x+2y\right)\left[\left(x+2y\right)^2-\left(x-2y\right)\right]\)
\(=\left(x+2y\right)\left(x^2+4xy+4y^2-x+2y\right)\)
1:
a: \(x\left(3-4x\right)+5\left(3-4x\right)=\left(3-4x\right)\left(x+5\right)\)
b: \(2y\left(5y-6\right)-4\left(6-5y\right)\)
\(=2y\left(5y-6\right)+4\left(5y-6\right)\)
\(=2\left(5y-6\right)\left(y+2\right)\)
c: \(=27\left(x-2\right)^3-3x\left(x-2\right)^2\)
\(=3\left(x-2\right)^2\cdot\left[9\left(x-2\right)-x\right]\)
\(=3\left(x-2\right)^2\left(8x-18\right)=6\left(x-2\right)^2\cdot\left(4x-9\right)\)
d: \(=6y\left(x-y\right)\left(x+y\right)-8y\left(x+y\right)^2\)
\(=2y\left(x+y\right)\left[3\left(x-y\right)-4\left(x+y\right)\right]\)
\(=2y\left(x+y\right)\left(3x-3y-4x-4y\right)\)
\(=2y\left(x+y\right)\left(-x-7y\right)\)
Bài 1
a) x(3 - 4x) + 5(3 - 4x)
= (3 - 4x)(x + 5)
b) 2y(5y - 6) - 4(6- 5y)
= 2y(5y - 6) + 4(5y - 6)
= (5y - 6)(2y + 4)
= 2(5y - 6)(y + 2)
c) 27(x - 2)³ - 3x(2 - x)²
= 27(x - 2)³ - 3x(x - 2)²
= 3(x - 2)²[9(x - 2) - x]
= 3(x - 2)²(9x - 18 - x)
= 3(x - 2)²(8x - 18)
= 6(x - 2)²(4x - 9)
d) 6y(x² - y²) - 8y(x + y)²
= 6y(x - y)(x + y) - 8y(x + y)²
= 2y(x + y)[3(x - y) - 4(x + y)]
= 2y(x + y)(3x - 3y - 4x - 4y)
= 2y(x + y)(-x - 7y)
= -2y(x + y)(x + 7y)
Tìm x,y
a) X^2+Y^2-2X+4Y+5=O
b) X^2+4Y^2+6X-12Y+18=O
c)5X^2+9y^2-12XY-6X+9=O
d)2X^2+2Y^2+2XY-10X-8Y+41=O
giup mình đi mình gấp lắm
Dạng : Phân tích đa thức thành nhân tử
a,2x^2y - 50xy
b,5x^2 -10x c.5x^3 -5x d.x^2 –xy + xe,x( x- y) -2(y- x) f,4x^2 -4xy -8y^2 g,x^2y- 6xy + 9y h,9x^2 - 4y^2 i,x^4 - 9x^2 k,25x^2 - 4y^2 m,2x^2 -18 n,x^2 - xy -4x +2y + 4 o,x^2 - y^2 - 2x -2y ô,x^ 2+ y^ 2 + 2xy - 9 ơ,x^ 2 -6x – 4y^2 +9 a1,x^ 2 +2x+1 – y^ 2 b1,3x^2 -6x +2xy -4y c1,5x^2 - 5xy- 9x+ 9y d1,3x^2 +5y - 3xy -5x e1,m^3 +4m^2 +3m f1,x^ 2 +x- y^ 2 +y g1,x^ 2 +3x +2 h1,x^ 2 -7x+10 k1,x^ 2 – 10x + 24 Giải nhanh giúp mình với, mình đang cần gấpa: 2x^2y-50xy=2xy(x-25)
b: 5x^2-10x=5x(x-2)
c: 5x^3-5x=5x(x^2-1)=5x(x-1)(x+1)
d: \(x^2-xy+x=x\left(x-y+1\right)\)
e: x(x-y)-2(y-x)
=x(x-y)+2(x-y)
=(x-y)(x+2)
f: 4x^2-4xy-8y^2
=4(x^2-xy-2y^2)
=4(x^2-2xy+xy-2y^2)
=4[x(x-2y)+y(x-2y)]
=4(x-2y)(x+y)
f1: x^2ỹ-y^2+y
=(x-y)(x+y)+(x+y)
=(x+y)(x-y+1)
a) x^2+4x+4-y^2
b) x^2-16-4xy+4y^2
c) x^3+2x^2y +xy^2
d) 5x+5y-x^2-2xy-y^2
e) x^5-x^4+x^3-x^2
a) \(x^2+4x+4-y^2\)
\(=\left(x^2+2.x.2+2^2\right)-y^2\)
\(=\left(x+2\right)^2-y^2\)
\(=\left(x+2+y\right)\left(x+2-y\right)\)
\(a,=\left(x+2\right)^2-y^2=\left(x-y+2\right)\left(x+y+2\right)\\ b=\left(x-2y\right)^2-16=\left(x-2y-4\right)\left(x-2y+4\right)\\ c,=x\left(x^2+2xy+y^2\right)=x\left(x+y\right)^2\\ d,=5\left(x+y\right)-\left(x+y\right)^2=\left(5-x-y\right)\left(x+y\right)\\ e,=x^4\left(x-1\right)+x^2\left(x-1\right)\\ =x^2\left(x^2+1\right)\left(x-1\right)\)
a: \(x^2+4x+4-y^2=\left(x+2-y\right)\left(x+2+y\right)\)
b: \(x^2-4xy+4y^2-16=\left(x-2y-4\right)\left(x-2y+4\right)\)
c: \(x^3+2x^2y+xy^2=x\left(x^2+2xy+y^2\right)=x\left(x+y\right)^2\)
1:phân tích các đa thức thành nhân tử
a) 10x^2y^3+5y^2y^4
b) 4a^2b+8a^3+12a^2b^4
c) 6x(x+y)^2+3x^2y(x+y)
2: phân tích đa thức thành nhân tử
a) 9x^2-12xy+4y^2
b) 1/4x^2-1,44y^2
c) 1/27a^3+0,064b^3
3) tìm x biết
a) x^3-4x^2+4x=0 b) x^3-25x=0 c) x^4-27/125x=0
tìm GTNN hoặc GTLN của
a) 5x^2-12xy+9y^2-4x+4
b) -x^2-2y^2+12x-4y+7
c)4y^2+10x^2+12xy+6x+7
d)3-10x^2-4xy-4y^2
e)x^2-5x+y^2-xy-4y+16
giúp mình với T_T
thank nhiều nha ! :)
a) \(5x^2-12xy+9y^2-4x+4=\left(4x^2-12xy+9y^2\right)+x^2-4x+4=\left(2x-3y\right)^2+\left(x-2\right)^2\ge0\)
b) \(-x^2-2y^2+12x-4y+7=-\left(x^2-12x+36\right)-2\left(y^2+2y+1\right)+45=-\left(x-6\right)^2-2\left(y+1\right)^2+45\le45\)
c)\(4y^2+10x^2+12xy+6x+7=\left(4y^2+12xy+9x^2\right)+x^2+6x+9-2=\left(2y+3x\right)^2+\left(x+3\right)^2-2\ge-2\)
d) \(3-10x^2-4xy-4y^2=3-\left(4y^2+4xy+x^2\right)-9x^2=-\left(2y+x\right)^2-9x^2+3\le3\)
e)\(x^2-5x+y^2-xy-4y+16=\left(\frac{1}{2}x^2-xy+\frac{1}{2}y^2\right)+\frac{1}{2}\left(x^2-10x+25\right)+\frac{1}{2}\left(y^2-8y+16\right)-\frac{9}{2}=\frac{1}{2}\left(x-y\right)^2+\frac{1}{2}\left(x-5\right)^2+\frac{1}{2}\left(y-4\right)^2-\frac{9}{2}\ge-\frac{9}{2}\)Phần e) mới nghĩ đk v, tui biết đáp án sao do k xảy ra dấu bằng
Cần gấp lắm ạ!
a) x2-4x+5+y2+2y
b) 2x2+y2-2xy+10x+25
c) a2+2ab+5b2+4b+1
d) 2x2 +2b2+4x+4b+4
e) x4+13-6x2+4y+y2
f) -6x+9x2-8y+4y2+5
Cái này là viết dưới dạng tổng hai bình phương ạ
a)x2-4x+5+y2+2y=x2-4x+4+y2+2y+1=(x-2)2+(y+1)2
b)2x2+y2-2xy+10x+25=x2-2xy+y2+x2+10x+25=(X+Y)2+(X+5)2
c)a2+2ab+5b2+4b+1=a2+2ab+b2+4b2+4b+1=(a+b)2+(2b+1)2
d)2x2+2b2+4x+4b+4=2x2+4x+2+2b2+4b+2=(\(\sqrt{2}x+\sqrt{2}\))2+(\(\sqrt{2}b+\sqrt{2}\))2
e)X4+13-6x2+4y+y2=x4-6x2+9+y2+4y+4=(x2-3)2+(y+2)2
f)-6x+9x2-8y+4y+y2+5= 9x2-6x+1+4y2-8y+4= (3x-1)2+(2y-2)2
tôi chỉ rút gọn đc như thế là cùng rồi
ko còn cách nào khác đâu
chắc bạn đang học những hằng đẳng thức đáng nhớ
Phân tích các đa thức sau thành nhân tử :
a, 4x^2 - 12x + 9
b, 4x^2 + 4x + 1
c, 1 + 12x + 36x^2
d, 9x^2 - 24xy + 16y^2
e, x^2/4 + 2xy + 4y^2
f, -x^2 + 10x - 25
g, -16a^4 b^6 - 24a^5 b^5 - 9a^6 b^4
h, 25x^2 - 20xy + 4y^2
i, 25x^4 - 10x^2y + y^2
Giúp mình với ạ mình đang cần gấp
a) \(4x^2-12x+9\)
\(=\left(2x\right)^2-2.2x.3+3^2\)
\(=\left(2x-3\right)^2\)
b) \(4x^2+4x+1\)
\(=\left(2x\right)^2+2.2x.1+1^2\)
\(=\left(2x+1\right)^2\)
c) \(1+12x+36x^2\)
\(=1^2+2.1.6x+\left(6x\right)^2\)
\(=\left(1+6x\right)^2\)
d) \(9x^2-24xy+16y^2\)
\(=\left(3x\right)^2-2.3x.4y+\left(4y\right)^2\)
\(=\left(3x-4y\right)^2\)
e) \(\frac{x^2}{4}+2xy+4y^2\)
\(=\left(\frac{x}{2}\right)^2+2.\frac{x}{2}.2y+\left(2y\right)^2\)
\(=\left(\frac{x}{2}+2y\right)^2\)
f) \(-x^2+10x-25\)
\(=-\left(x^2-10x+25\right)\)
\(=-\left(x^2-2.5x+5^2\right)\)
\(=-\left(x-5\right)^2\)
g) \(-16a^4b^6-24a^5b^5-9a^6b^4\)
\(=-a^4b^4\left(16b^2+24ab+9a^2\right)\)
\(=-a^4b^4\left[\left(4b\right)^2+2.4b.3a+\left(3a\right)^2\right]\)
\(=-a^4b^4\left(4b+3a\right)^2\)
h) \(25x^2-20xy+4y^2\)
\(=\left(5x\right)^2-2.5x.2y+\left(2y\right)^2\)
\(=\left(5x-2y\right)^2\)
i) \(25x^4-10x^2y+y^2\)
\(=\left(5x^2\right)^2-2.5x^2y+y^2\)
\(=\left(5x^2-y\right)^2\)
Phân tích các đa thức sau đây thành nhân tử
a, 36x^2 - ( 3x -2 ) ^2
b, 16(4x+5)^5 - 25 (2x+2)^2
c, ( x - y + 4 )^2
d, (x+1)^4 - (x-1)^4
e, 16x^2 - 24xy + 9y^2
f, -x^4/4 + 2x^2y^3 - 4y^6
g , 64x^3 +1
h, x^3y^6z^9 - 125
k, 27x^6 - 8x^3
I , x^6 - y^6
m, 27x^3 - 54x^2y + 36xy^2 - 8y^3
n, y^9 - 9x^2y^6 + 27x^4y^3 - 27x^6
làm ơn giải chi tiết giúp mik vs ạ , cảm ơn
a: =(6x)^2-(3x-2)^2
=(6x-3x+2)(6x+3x-2)
=(9x-2)(3x+2)
d: \(=\left[\left(x+1\right)^2-\left(x-1\right)^2\right]\left[\left(x+1\right)^2+\left(x-1\right)^2\right]\)
\(=4x\cdot\left[x^2+2x+1+x^2-2x+1\right]\)
=8x(x^2+1)
e: =(4x)^2-2*4x*3y+(3y)^2
=(4x-3y)^2
f: \(=-\left(\dfrac{1}{4}x^4-2\cdot\dfrac{1}{2}x^2\cdot2y^3+4y^6\right)\)
\(=-\left(\dfrac{1}{2}x^2-2y^3\right)^2\)
g: =(4x)^3+1^3
=(4x+1)(16x^2-4x+1)
k: =x^3(27x^3-8)
=x^3(3x-2)(9x^2+6x+4)
l: =(x^3-y^3)(x^3+y^3)
=(x-y)(x+y)(x^2-xy+y^2)(x^2+xy+y^2)