a,91-5(5+x)=61

=>25+5x=91-61=30

=>5x=30-25=5

=>x=1

b,\([\left(x+34\right)-50]\)x2=56

=>(x+34)-50=56:2=28

=>x+34=28+50=78

=>x=78-34=44.

c,1045-\([2015-\left(3x-24\right)]\)=5

=>2015-(3x-24)=1045-5=1040

=>3x-24=2015-1040=975

=>3x=975+24=999

=>x=999:3=333

d,\([195-\left(3x-27\right)]\)x39=4212

=>195-(3x-27)=4212:39=108

=>3x-27=195-108=87

=>3x=87+27=117

=>x=39

e,30-3(x-2)=18

=>30-3x+6=18

=>30-3x=18-6=12

=>3x=30-12=18

=>x=18:3=6

a) \(...\Rightarrow5\left(5+x\right)=91-61=30\)

\(\Rightarrow\left(5+x\right)=30:5=6\Rightarrow x=6-5=1\)

b) \(...\Rightarrow\left(x+34\right)-50=56:2=28\)

\(\Rightarrow\left(x+34\right)=28+50=78\Rightarrow x=78-34=44\)

c) \(...\Rightarrow2015-\left(3x-24\right)=1045-5=1040\)

\(\Rightarrow\left(3x-24\right)=2015-1040=975\)

\(\Rightarrow3x=975+24=999\Rightarrow x=999:3=333\)

d) \(...\Rightarrow195-\left(3x-27\right)=4212:39=108\)

\(\Rightarrow\left(3x-27\right)=195-108=87\)

\(\Rightarrow3x=87+27=114\Rightarrow x=114:3=38\)

e) \(...\Rightarrow3\left(x-2\right)=30-18=12\Rightarrow x-2=12:3=4\)

\(\Rightarrow x=4+2=6\)

\(\left[195-\left(3x-27\right)\right]\cdot39=4212\)

\(\Rightarrow\left(195-3x+27\right)\cdot39=4212\)

\(\Rightarrow\left(-3x+222\right)\cdot39=4212\)

\(\Rightarrow-3x+222=\dfrac{4212}{39}\)

\(\Rightarrow-3x+222=108\)

\(\Rightarrow3x=222-108\)

\(\Rightarrow3x=114\)

\(\Rightarrow x=\dfrac{114}{3}\)

\(\Rightarrow x=38\)

=>[195-(3x-27)]=4212:39=108

=>3x-27=195-108=87

=>3x=27+87=114

=>x=38

\(\left[195-\left(3x-27\right)\right]\cdot39=4212\\ \Rightarrow195-\left(3x-27\right)=4212:39\\ \Rightarrow195-\left(3x-27\right)=108\\ \Rightarrow3x-27=195-108\\ \Rightarrow3x-27=87\\ \Rightarrow3x=87+27\\ \Rightarrow3x=114\\ \Rightarrow x=114:3\\ \Rightarrow x=38\)

\(\left[195-\left(3x-27\right)\right]\cdot39=4212\\ \Leftrightarrow195-\left(3x-27\right)=108\\ \Leftrightarrow3x-27=87\\ \Leftrightarrow3x=114\\ \Leftrightarrow x=38\)

Vậy x = 38.

[195−(3x−27)]⋅39=4212

⇒195−(3x−27)=4212:39

⇒195−(3x−27)=108

⇒3x−27=195−108

⇒3x−27=87⇒3x=87+27✿

⇒3x=114⇒x=114:3⇒x=38

[195-(15x-27).39=4212

195-(15x-27)=4212 : 39

195-(15x-27)=108

15x-27=195-108

15x-27=87

15x=87+27

15x=114

x=114:15

x=38/5

x=7,6

k đúng cho m nha bạn !

Đề thiếu bạn ạ.

thank you quang anh nguyễn

a) \(1045:\left[215-\left(3x-24\right)\right]=5\)

\(\Rightarrow215-\left(3x-24\right)=1045:5\)

\(\Rightarrow215-\left(3x-24\right)=209\)

\(\Rightarrow3x-24=215-209\)

\(\Rightarrow3x-24=6\)

\(\Rightarrow3x=6+24\)

\(\Rightarrow3x=30\)

\(\Rightarrow x=30:3\)

\(\Rightarrow x=10\)

Vậy x = 10

b) \(\left[195-\left(15x+27\right)\right]\times39=4212\)

\(\Rightarrow195-\left(15x+27\right)=4212:39\)

\(\Rightarrow195-\left(15x+27\right)=108\)

\(\Rightarrow15x+27=195-108\)

\(\Rightarrow15x+27=87\)

\(\Rightarrow15x=87-27\)

\(\Rightarrow15x=60\)

\(\Rightarrow x=60:15\)

\(\Rightarrow x=4\)

Vậy x = 4

_Chúc bạn học tốt_

\(1734:17=102x17:17=102x1=102\)

\(\left(x-7\right)\)\(2-26=13x17-13x7=13\left(17-7\right)=13x10=130\)

\(\left(x-7\right)2=130+26=156\)

\(x-7=156:2=78\)

\(x=78+7=85\)

\(=>x=85\)

\(195-\left(15x+27\right)=4212:39=108\)

\(15x+27=195-108=87\)

\(15x=87-27=60\)

\(x=60:15=4\)

\(=>x=4\)

- Tính nhẩm
1734 : 17 = 102

- Tìm x
(x - 7) .2 - 26 = 13.17 - 13.7
(x - 7) .2 - 26 = 13.(17 - 7)
(x - 7) .2 - 26 = 13. 10
(x - 7) .2 - 26 = 130
(x - 7) .2         = 130 + 26
(x - 7) .2         = 156
(x - 7)             = 156 : 2
(x - 7)             = 78
 x                    = 78 + 7
 x                    = 85
___________________
195 - (15x + 27) .39 = 4212         (dấu "[" đặt ở đấu tiên nên không cần thiết)
         (15x + 27) .39 = 195 - 4212
         (15x + 27) .39 = -4017
         (15x + 27)       = -4017 : 39
         (15x + 27)       = -103
          15x                 = -103 -27
          15x                 = -130
              x                 = -130 : 15
              x                 = -26/3
 

\(95-\left(3x-27\right).39=4212\)

\(95-\left(3x-27\right)=108\)

\(3x-27=-13\)

\(3x=14\)

\(x=\dfrac{14}{3}\)

\(95-\left(3x-27\right).39=4212\)

\(95-\left(3x-27\right)=4212:39\)

\(95-\left(3x-27\right)=108\)

\(3x-27=95-108\)

\(3x-27=-13\)

\(3x=-13+27\)

\(3x=14\)

\(x=14:3\)

\(x=\dfrac{14}{3}\)

Vậy \(x=\dfrac{14}{3}\)

\(\dfrac{x+3}{97}+\dfrac{x+5}{95}+\dfrac{x+9}{91}=\dfrac{x+91}{9}+\dfrac{x+92}{8}+\dfrac{x+61}{39}\)

=> \(\dfrac{x+3}{97}+1+\dfrac{x+5}{95}+1+\dfrac{x+9}{91}+1=\dfrac{x+91}{9}+1+\dfrac{x+92}{8}+1+\dfrac{x+61}{39}+1\)

=> \(\dfrac{x+100}{97}+\dfrac{x+100}{95}+\dfrac{x+100}{91}=\dfrac{x+100}{9}+\dfrac{x+100}{8}+\dfrac{x+100}{39}\)

=> \(\dfrac{x+100}{97}+\dfrac{x+100}{95}+\dfrac{x+100}{91}-\dfrac{x+100}{9}-\dfrac{x+100}{8}-\dfrac{x+100}{39}=0\)

=> \(\left(x+100\right).\left(\dfrac{1}{97}+\dfrac{1}{95}+\dfrac{1}{91}-\dfrac{1}{9}-\dfrac{1}{8}-\dfrac{1}{39}\right)=0\)

=> x =  - 100 (do \(\dfrac{1}{97}+\dfrac{1}{95}+\dfrac{1}{91}-\dfrac{1}{9}-\dfrac{1}{8}-\dfrac{1}{39}\ne0\)

Ta có: \(\dfrac{x+3}{97}+\dfrac{x+5}{95}+\dfrac{x+9}{91}=\dfrac{x+91}{9}+\dfrac{x+92}{8}+\dfrac{x+61}{39}\)

\(\Leftrightarrow\dfrac{x+3}{97}+1+\dfrac{x+5}{95}+1+\dfrac{x+9}{91}+1=\dfrac{x+91}{9}+1+\dfrac{x+92}{8}+1+\dfrac{x+61}{39}+1\)

\(\Leftrightarrow\dfrac{x+100}{97}+\dfrac{x+100}{95}+\dfrac{x+100}{91}=\dfrac{x+100}{9}+\dfrac{x+100}{8}+\dfrac{x+100}{39}\)

\(\Leftrightarrow\dfrac{x+100}{97}+\dfrac{x+100}{95}+\dfrac{x+100}{91}-\dfrac{x+100}{9}-\dfrac{x+100}{8}-\dfrac{x+100}{39}=0\)

\(\Leftrightarrow\left(x+100\right)\left(\dfrac{1}{97}+\dfrac{1}{95}+\dfrac{1}{91}-\dfrac{1}{9}-\dfrac{1}{8}-\dfrac{1}{39}\right)=0\)

mà \(\dfrac{1}{97}+\dfrac{1}{95}+\dfrac{1}{91}-\dfrac{1}{9}-\dfrac{1}{8}-\dfrac{1}{39}\ne0\)

nên x+100=0

hay x=-100

Vậy: S={-100}