tìm x biết
a)x-\(\dfrac{3}{7}\)=\(\dfrac{2}{5}.\dfrac{1}{4}\)
b)x+\(\dfrac{4}{5}\)=\(\dfrac{-5}{12}\).\(\dfrac{3}{25}\)
c)\(\dfrac{x}{182}\)=\(\dfrac{-6}{12}\).\(\dfrac{35}{91}\)
a/ \(x-\dfrac{3}{7}=\dfrac{2}{5}\cdot\dfrac{1}{4}\)
\(x-\dfrac{3}{7}=\dfrac{1}{10}\)
\(x=\dfrac{1}{10}+\dfrac{3}{7}=\dfrac{37}{70}\)
Vậy....
b/ \(x+\dfrac{4}{5}=-\dfrac{5}{12}\cdot\dfrac{3}{25}\)
\(x+\dfrac{4}{5}=-\dfrac{1}{20}\)
\(x=-\dfrac{1}{20}-\dfrac{4}{5}=-\dfrac{17}{20}\)
Vậy....
c/ \(\dfrac{x}{182}=-\dfrac{6}{12}\cdot\dfrac{35}{91}\)
\(\dfrac{x}{182}=-\dfrac{5}{26}\)
\(=>x\cdot26=-5\cdot182\)
\(26x=-910\)
\(x=-910:26=-35\)
Vậy....
a) Ta có: \(x-\dfrac{3}{7}=\dfrac{2}{5}\cdot\dfrac{1}{4}\)
\(\Leftrightarrow x-\dfrac{3}{7}=\dfrac{1}{10}\)
\(\Leftrightarrow x=\dfrac{1}{10}+\dfrac{3}{7}=\dfrac{7}{70}+\dfrac{30}{70}\)
hay \(x=\dfrac{37}{70}\)
Vậy: \(x=\dfrac{37}{70}\)
tìm x , biết
a) 17/6- x( x-7/6)= 7/4
b) 3/35 - ( 3/5-x)= 2/7
tìm x thuộc Z , biết
3/4-5/6 < x/12 < 1 -( 2/3-1/4)
tìm x biết
a ) 2x-3=x + 1/2
b) 4x- ( x+ 1/2) = 2x - ( 1/2 - 5 )
Bài 1:
a) Ta có: \(\dfrac{17}{6}-x\left(x-\dfrac{7}{6}\right)=\dfrac{7}{4}\)
\(\Leftrightarrow\dfrac{17}{6}-x^2+\dfrac{7}{6}x-\dfrac{7}{4}=0\)
\(\Leftrightarrow-x^2+\dfrac{7}{6}x+\dfrac{13}{12}=0\)
\(\Leftrightarrow-12x^2+14x+13=0\)
\(\Delta=14^2-4\cdot\left(-12\right)\cdot13=196+624=820\)
Vì Δ>0 nên phương trình có hai nghiệm phân biệt là:
\(\left\{{}\begin{matrix}x_1=\dfrac{14-2\sqrt{205}}{-24}=\dfrac{-7+\sqrt{205}}{12}\\x_2=\dfrac{14+2\sqrt{2015}}{-24}=\dfrac{-7-\sqrt{205}}{12}\end{matrix}\right.\)
b) Ta có: \(\dfrac{3}{35}-\left(\dfrac{3}{5}-x\right)=\dfrac{2}{7}\)
\(\Leftrightarrow\dfrac{3}{5}-x=\dfrac{3}{35}-\dfrac{10}{35}=\dfrac{-7}{35}=\dfrac{-1}{5}\)
hay \(x=\dfrac{3}{5}-\dfrac{-1}{5}=\dfrac{3}{5}+\dfrac{1}{5}=\dfrac{4}{5}\)
Bài 3:
a) Ta có: \(2x-3=x+\dfrac{1}{2}\)
\(\Leftrightarrow2x-x=\dfrac{1}{2}+3\)
\(\Leftrightarrow x=\dfrac{7}{2}\)
b) Ta có: \(4x-\left(x+\dfrac{1}{2}\right)=2x-\left(\dfrac{1}{2}-5\right)\)
\(\Leftrightarrow3x-\dfrac{1}{2}-2x+\dfrac{1}{2}-5=0\)
\(\Leftrightarrow x=5\)
Giải các phương trình sau: 1)√3x²-√12=0
2)√(x-3)²=9
3)√4x²+4x+1=6
4)√(2x-1)²=3
5)√(x-3)²=3-x 6)√4x²-20x+25+2x=5
7)√1-12x+36x²=5
1.
$\sqrt{3x^2}-\sqrt{12}=0$
$\Leftrightarrow \sqrt{3x^2}=\sqrt{12}$
$\Leftrightarrow 3x^2=12$
$\Leftrightarrow x^2=4$
$\Leftrightarrow (x-2)(x+2)=0\Leftrightarrow x=\pm 2$
2.
$\sqrt{(x-3)^2}=9$
$\Leftrightarrow |x-3|=9$
$\Leftrightarrow x-3=9$ hoặc $x-3=-9$
$\Leftrightarrow x=12$ hoặc $x=-6$
3.
$\sqrt{4x^2+4x+1}=6$
$\Leftrightarrow \sqrt{(2x+1)^2}=6$
$\Leftrightarrow |2x+1|=6$
$\Leftrightarrow 2x+1=6$ hoặc $2x+1=-6$
$\Leftrightarrow x=\frac{5}{2}$ hoặc $x=\frac{-7}{2}$
a) 28 + 2x = 35 – (- 13) ; b) - 25 – (x + 5) = 415 + 5(x – 83)
c) 2 (x + 1)2 = - 7 + 15 ; f) (x – 4)2 – 48 = - 12 ;
g) (x + 3)3:3 – 1 = - 10 ; h) (3x + 9)(11 – x) = 0.
a, 28 + 2x = 35 - ( -13 )
=> 2x = 35 + 13 - 28
=>2x = 20
=> x = 10. vậy x = 10
a, \(28+2x=35+13\Leftrightarrow28+2x=48\Leftrightarrow2x=20\Leftrightarrow x=10\)
b, \(-25-x-5=415+5x-415\Leftrightarrow-6x=30\Leftrightarrow x=-5\)
1) 10 -3 ( x -1 ) = -5
2) 3x + 75 = -15
3) 4x - 15 = -75 - x
4) 12 - ( x - 7 ) = -8
5) x + 75 = 15
6) x - 18 = 3x + 4
7) 2x + 18 = 10
8) 26 - 3x = 5
9) x - 12 = -15
10) 24 - 2 ( x + 5 ) = 38
11) 25 - 5 ( 3 - x ) = 15
12) x + ( -17 ) = -14
13) -5x - 13 = 47
14) 2x + 36 = -18
15) 9 . ( x + 7 ) - 12 = 24
Ai giải dùm mình nhanh nhất, đúng mình tick cho nha
1) 10 - 3 ( x - 1 ) = -5
3 ( x - 1 ) = 10 - ( - 5 )
3 ( x - 1 ) = 15
x - 1 = 15 : 3
x - 1 = 5
x = 5 + 1
x = 6
2) 3x + 75 = - 15
3x = - 15 - 75
3x = - 90
x = -90 : 3
x = -30
4) 12 - ( x - 7 ) = - 8
x - 7 = 12 - (- 8 )
x - 7 = 20
x = 20 + 7
x = 27
5) x + 75 = 15
x = 15 - 75
x = -60
7) 2x + 18 = 10
2x = 10 - 18
2x = -8
x = - 8 : 2
x = -4
8) 26 - 3x = 5
3x = 26 - 5
3x = 21
x = 21: 3
x = 7
9) x - 12 = - 15
x = -15 + 12
x =-3
10 ) 24 - 2 ( x + 5 ) = 38
2 ( x+ 5 ) = 24 - 38
2 ( x + 5 ) = - 14
x + 5 = -14 : 2
x + 5 = -7
x = -7 - 5
x = -12
còn là bạn tự làm tiếp nhé ! bạn gửi nhiều cầu qua bạn chỉ nên gửi ít một thời như vậy khó có thể giải làm bạn ạ!
25 - 5 (3- x) = 15
25 - 5 (3-x) = 15
5 (3-x) = 25 -15
5 (3-x) = 10
3 - x = 10 : 5
3 - x = 2
x = 3 - 2
x = 1
Giải các phương trình sau:
a/ 3x – 2 = 2x – 3
b/ 7 – 2x = 22 – 3x
c) 8x – 3 = 5x + 12
d/ x – 12 + 4x = 25 + 2x – 1
e/ x + 2x + 3x – 19 = 3x + 5
a) \(PT\Leftrightarrow3x-2x=2-3\Leftrightarrow x=-1\)
Vậy: \(S=\left\{-1\right\}\)
b) \(PT\Leftrightarrow-2x+3x=-7+22\Leftrightarrow x=15\)
Vậy: \(S=\left\{15\right\}\)
c) \(PT\Leftrightarrow8x-5x=3+12\Leftrightarrow3x=15\Leftrightarrow x=5\)
Vậy: \(S=\left\{5\right\}\)
d) \(PT\Leftrightarrow x+4x-2x=12+25-1\Leftrightarrow3x=36\Leftrightarrow x=12\)
Vậy: \(S=\left\{12\right\}\)
e) \(PT\Leftrightarrow x+2x+3x-3x=19+5\Leftrightarrow3x=24\Leftrightarrow x=8\)
Vậy: \(S=\left\{8\right\}\)
a)3x-2=2x-3
=>x=-1
b)7-2x=22-3x
=>x=15
c)8x-3=5x+12
=>3x=15
=>x=5
d)x-12+4x=25+2x-1
=>3x=12
=>x=4
e)x+2x+3x-19=3x+5
=>3x=24
=>x=8
a)3x-2=2x-3
=>x=-1
b)7-2x=22-3x
=>x=15
c)8x-3=5x+12
=>3x=15
=>x=5
d)x-12+4x=25+2x-1
=>3x=36
=>x=12
e)x+2x+3x-19=3x+5
=>3x=24
=>x=8
a. 3(x-1/2) - 5(x+3/5=-x+1/5
b. 2/3× + 1/2x = 5/2:15/4
c. 3x + 2x = 5/8 × 4/3
d. 17/2 - |2x - 3/4| = -7/4
e. (x + 1/25) + 17/25 = 26/25
f. 2/3x - 1/2x = 5/12
g. (x + 1/2) × (2/3-2x) = 0
ai làm nhanh đúng mk cho 10 tk
g. \(\left(x+\frac{1}{2}\right)\left(\frac{2}{3}-2x\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}x+\frac{1}{2}=0\\\frac{2}{3}-2x=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=\frac{-1}{2}\\x=\frac{1}{3}\end{cases}}\)
Vậy \(x\in\left\{\frac{-1}{2};\frac{1}{3}\right\}\)
f. \(\frac{2}{3}x-\frac{1}{2}x=\frac{5}{12}\)
\(\Leftrightarrow x\left(\frac{2}{3}-\frac{1}{2}\right)=\frac{5}{12}\)
\(\Leftrightarrow x\left(\frac{4}{6}-\frac{3}{6}\right)=\frac{5}{12}\)
\(\Leftrightarrow\frac{1}{6}x=\frac{5}{12}\)
\(\Leftrightarrow x=\frac{5}{12}\div\frac{1}{6}\)
\(\Leftrightarrow x=\frac{30}{12}=\frac{5}{2}\)
c. \(3x+2x=\frac{5}{8}\times\frac{4}{3}\)
\(\Leftrightarrow x\left(3+2\right)=\frac{5.4}{8.3}\)
\(\Leftrightarrow5x=\frac{5.1}{2.3}\)
\(\Leftrightarrow5x=\frac{5}{6}\)
\(\Leftrightarrow x=\frac{5}{6}\div5\)
\(\Leftrightarrow x=\frac{1}{6}\)
Mọi người check xem đúng không:
<=>x(3x+2)+(x+1)^2 - (2x - 5)(2x+5)= -12
<=>3x^2 + 2x + (x+1)^2 - 2x^2 - 5^2= -12
<=>(3x^2 - 2x^2) + [ (x +1)^2 -5^2] + 2x = -12
<=>(3x - 2x)(3x + 2x)+ (x+1-5) (x+1+5) + 2x = -12
=> 3x - 2x = -12 ; 3x+2x = -12 ; x+1+5 = -12 ; x+1-5 = -12 hoặc 2x = -12
=> x = -12 ; 5x =-12 ; x+ 6 = -12 ; x -4 = -12 hoặc x = -12: 2
=> x= -12 ; x = -12:5; x = -12 :6; x = -12 + 4 hoặc x= -6
=> x= -12 x = -12/5; x = -2 ; x = -8 hoặc x = -6
đúng rồi nha bạn
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Mọi người check xem đúng không:
<=>x(3x+2)+(x+1)^2 - (2x - 5)(2x+5)= -12
<=>3x^2 + 2x + (x+1)^2 - 2x^2 - 5^2= -12
<=>(3x^2 - 2x^2) + [ (x +1)^2 -5^2] + 2x = -12
<=>(3x - 2x)(3x + 2x)+ (x+1-5) (x+1+5) + 2x = -12
=> 3x - 2x = -12 ; 3x+2x = -12 ; x+1+5 = -12 ; x+1-5 = -12 hoặc 2x = -12
=> x = -12 ; 5x =-12 ; x+ 6 = -12 ; x -4 = -12 hoặc x = -12: 2
=> x= -12 ; x = -12:5; x = -12 :6; x = -12 + 4 hoặc x= -6
=> x= -12 x = -12/5; x = -2 ; x = -8 hoặc x = -6
bạn làm sai rồi !
\(\Leftrightarrow x\left(3x+2\right)+\left(x+1\right)^2-\left(2x-5\right)\left(2x+5\right)=-12\)
\(\Leftrightarrow3x^2+2x+x^2+2x+1-4x^2+25=-12\)
\(\Leftrightarrow4x+26=-12\)
\(\Leftrightarrow4x=-38\)
\(\Leftrightarrow x=-\frac{19}{2}\)
Vậy tập nghiệm của phương trình là \(S=\left\{-\frac{19}{2}\right\}\)
