5.3^x =8.3^10-3.3^10
Bạn nào giúp mình với. >.<
5.3^x=8.3^10-3.3^10
Mình cảm ơn nhiều lắm nha!!!!!!!!!!!!!!!!!!!!!!!!!!!
5.3x = 8.310 - 3.310
<=> 5.3x = ( 8-3 ) . 310
<=> 5.3x = 5 .310
<=> x = 10
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\(5.3^x=8.3^{10}-3.3^{10}\)
\(\Rightarrow5.3^x=\left(8-3\right).3^{10}\)
\(\Rightarrow5.3^x=5.3^{10}\)
\(\Rightarrow x=10\)
I have a crazy idea chơi bửn thế. Sao lại chép đáp án của Nguyen Thuy Trinh
BT3: Tìm x, biết
13) 25 \(\le\) 5\(^x\) \(\le\) 125
14) 5.3\(^x\) = 8.3\(^{10}\) - 3.3\(^{10}\)
13, ta có 25\(\le5^x\le125\)
Hay 52 \(\le\) 5x \(\le\) 53
suy ra 2 \(\le\) x \(\le\) 3
Cái này chắc là làm đến đây thôi vì có thể x là phân số hoặc số thập phân thì chịu !!!!
13) \(25\le5^x\le125\\ 5^2\le5^x\le5^3\\ \Rightarrow2\le x\le3\\ \Rightarrow x\in\left\{\varnothing\right\}\)
14,
Ta có :
5.3xx = 8.310 - 3.310
5.3x = 310(8-3)
5.3x = 310.5
=>3x=310
=>x=10
Xong !
2.3=
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10.3=
Ai tick mk mk tick lại
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lAM THI TUI LAM CHU K THI KHONG
tính a) \(\frac{11^4.11^5}{11^4-11^5}:\frac{9^8.3-9^9}{9^8.5-9^8.7}:\frac{10^5-10^5.3}{10^5.11}\)
a.\(\frac{11^4.11^5}{11^4-11^5}:\frac{9^8.3-9^9}{9^8.5-9^8.7}:\frac{10^5-10^5.3}{10^5.11}\)
=\(\frac{11^4.11^5}{11^4-11^4.11}:\frac{9^8.3-9^8.9}{9^8.5-9^8.7}:\frac{10^5-10^5.3}{10^5.11}\)
=\(\frac{11^4.11^5}{11^4.\left(1-11\right)}:\frac{9^8.\left(3-9\right)}{9^8.\left(5-7\right)}:\frac{10^5.\left(1-3\right)}{10^5.11}
\)
=\(\frac{11^4.11^5}{11^4.\left(-10\right)}:\frac{9^8.\left(-6\right)}{9^8.\left(-2\right)}:\frac{10^5.\left(-2\right)}{10^5.11}\)
=\(\frac{11^5}{-10}:3:\frac{-2}{11}\)
=\(\frac{11^5}{-10}.\frac{1}{3}.\frac{-11}{2}\)
Chiều mình làm tiếp cho nha!👋
tim x biet
X+35=-22-X
(6X-4^2) .7^8=2.7^9
5.3^x-1-7.3^12=8.3^12
3.(x-15)^3=-24
lx+18l=10
1 tìm x
\(\dfrac{15-x}{8}=\dfrac{x-23}{10}\)
\(5.3^x=8.3^{^{ }9}\)
\(\dfrac{1}{2}\left|2x-1\right|-3\dfrac{2}{5}=\left(\dfrac{-1}{2}\right).\left(2015\right)^0\)
*** \(\dfrac{15-x}{8}=\dfrac{x-23}{10}\)
\(\Rightarrow10\left(15-x\right)=8\left(x-23\right)\)
\(\Rightarrow150-10x=8x-184\)
\(\Rightarrow150+184=10x+8x\)
\(\Rightarrow18x=334\)
\(\Rightarrow x=\dfrac{167}{9}\)
*** \(\dfrac{1}{2}\left|2x-1\right|-3\dfrac{2}{5}=\left(-\dfrac{1}{2}\right).\left(2015\right)^0\)
\(\Rightarrow\dfrac{1}{2}\left|2x-1\right|-3\dfrac{2}{5}=\left(-\dfrac{1}{2}\right).1\)
\(\Rightarrow\dfrac{1}{2}\left|2x-1\right|-3\dfrac{2}{5}=\left(-\dfrac{1}{2}\right)\)
\(\Rightarrow\dfrac{1}{2}\left|2x-1\right|-3\dfrac{2}{5}=\left(-\dfrac{1}{2}\right)\)
\(\Rightarrow\dfrac{1}{2}\left|2x-1\right|=\left(-\dfrac{1}{2}\right)+3\dfrac{2}{5}\)
\(\Rightarrow\dfrac{1}{2}\left|2x-1\right|=\dfrac{29}{10}\)
\(\Rightarrow\left|2x-1\right|=\dfrac{29}{10}:\dfrac{1}{2}\)
\(\Rightarrow\left|2x-1\right|=\dfrac{29}{5}\)
\(\Rightarrow\left[{}\begin{matrix}2x-1=\dfrac{29}{5}\\2x-1=-\dfrac{29}{5}\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}2x=\dfrac{34}{5}\\2x=-\dfrac{24}{5}\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=\dfrac{17}{5}\\x=-\dfrac{12}{5}\end{matrix}\right.\)
rút gọn
a) \(\frac{11^4.6-11^5}{11^4-11^5}\)
b ) \(\frac{9^8.3-3^{18}}{9^8.5+9^8.7}\)
c ) \(\frac{10^5-10^5.3}{10^5.11}\)
a.
\(\frac{11^4\times6-11^5}{11^4-11^5}=\frac{11^4\times\left(6-11\right)}{11^4\times\left(1-11\right)}=\frac{-5}{-10}=\frac{1}{2}\)
b.
\(\frac{9^8\times3-3^{18}}{9^8\times5+9^8\times7}=\frac{9^8\times3-\left(3^2\right)^9}{9^8\times\left(5+7\right)}=\frac{9^8\times3-9^9}{9^8\times12}=\frac{9^8\times\left(3-9\right)}{9^8\times12}=-\frac{6}{12}=-\frac{1}{2}\)
c.
\(\frac{10^5-10^5\times3}{10^5\times11}=\frac{10^5\times\left(1-3\right)}{10^5\times11}=-\frac{2}{11}\)
Chúc bạn học tốt
giá trị của biểu thức:
\(A=\frac{\left(11^4.6-11^5\right)}{11^4-11^5}:\frac{9^8.3-9^9}{9^8.5+9^8.7}:\frac{10^5-10^5.3}{10^5.11}\)
tính xong mình tích cho 3 cái! nhanh lên nhé
11/2 mink đoán thế,số thập phân thì là 5,5
Tìm x,y thuộc N biết:
a) 2x+1. 3y =12x
b) 10x : 5y =20y
c) -3.3x + 5.3x =162
\(2^{x-1}=3^{y-x}\Rightarrow x-1=y-x=0\Rightarrow\hept{\begin{cases}x=1\\y=1\end{cases}}\)
\(2^{x+1}.3^y=12^x\Rightarrow2^{x+1}.3^y=2^{2x}.3y\Rightarrow\frac{2^{2x}}{2^{x+1}}=\frac{3^y}{3^x}\Rightarrow2^{2x-x-1}=3^{y-x}\)