1)Tìm x:
a.(15.x+2.23)-4=10
b.3.x.155=156
Tìm x:
a)x*3=4 giờ 15 phút
b)4 giờ 15 phút :x =3
x = 4 giờ 15 phút:3
x = 1 giờ 25 phút
x =4 giờ 15 phút : 3
x = 1 giờ 25 phút
Tìm x:
a) x +\(\dfrac{4}{15}\) = \(\dfrac{4}{12}\) b) x - \(\dfrac{5}{8}\) = \(1\dfrac{2}{3}\)
a) \(x+\dfrac{4}{15}=\dfrac{4}{12}\)
\(x=\dfrac{4}{12}-\dfrac{4}{15}\)
\(x=\dfrac{20}{60}-\dfrac{16}{60}\)
\(x=\dfrac{1}{15}\)
b) \(x-\dfrac{5}{8}=1\dfrac{2}{3}\)
\(x-\dfrac{5}{8}=\dfrac{5}{3}\)
\(x=\dfrac{5}{3}+\dfrac{5}{8}\)
\(x=\dfrac{40}{24}+\dfrac{15}{24}\)
\(x=\dfrac{55}{24}\)
Tìm x:
a) 3x ( 12x - 4 ) - 9x( 4x - 3 ) = 30
b) x( 5 - 2x) + 2x( x - 1) = 15
`@` `\text {Ans}`
`\downarrow`
`a)`
`3x ( 12x - 4 ) - 9x( 4x - 3 ) = 30`
`=> 3x (12x-4) - 3*3x (4x - 3) = 30`
`=> 3x [12x - 4 - 3(4x-3)] = 30`
`=> 3x (12x - 4 - 12x + 9) = 30`
`=> 3x (-4+9)=30`
`=> 3x*5=30`
`=> 3x=6`
`=> x=2`
Vậy, `x=2`
`b)`
`x( 5 - 2x) + 2x( x - 1)`
`=> x(5-2x) + 2x^2 - 2x=15`
`=> 5x - 2x^2 + 2x^2 - 2x =15`
`=> 3x = 15`
`=> x=5`
Vậy, `x=5.`
a: =>36x^2-12x-36x^2+27x=30
=>15x=30
=>x=2
b: =>5x-2x^2+2x^2-2x=15
=>3x=15
=>x=5
tìm x biết x+1/156+x+2/155+x+3/154+x+257/30=0
tìm x biết x+1/156+x+2/155+x+3/154+x+257/30=0
Tìm X:
a) (x + 3)2 – x2 + 15 = 1
b) (5 – x)2 + 6x – x2 = –7
c) (1 + x)(1 – x) – (x – 4)2 = –15
giúp mik với mik cần gấp!!
a)(x+3)2-x2+15=2x+6-2x+15=1
=21=1
Bạn chép sai đầu bài à
1 . Tìm x:
a) x.2 / -15 = -5/3
b) x-1 / -12 = -3 / x - 1
a) \(\dfrac{x.2}{-15}=\dfrac{-5}{3}\)
\(\dfrac{x.2}{-15}=\dfrac{25}{-15}\)
x.2=25
x=12,5
b) \(\dfrac{x-1}{-12}=\dfrac{-3}{x-1}\)
(x-1)2=-3.(-12)
(x-1)2=36
⇒(x-1)2\(\Rightarrow\left[{}\begin{matrix}x-1=6\\x-1=-6\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=7\\x=-5\end{matrix}\right.\)
Tìm x biết :
a, 3x - 357 = 156
b, ( 9 |x| +4)*5=155
c, |x-3|=|-7|
Tìm x:
a)\(\dfrac{1}{3}\sqrt{x-1}+2\sqrt{4x-4}-12\sqrt{\dfrac{x-1}{25}}=\dfrac{29}{15}\)
b)\(\dfrac{3x-2}{\sqrt{x-1}}-\sqrt{x+1}=\sqrt{2x-3}\)
1. Tìm x:
a) x + 2 / -15 = -5/3
\(x+\dfrac{2}{-15}=\dfrac{5}{3}\)
\(x=\dfrac{9}{5}\)
\(x+\dfrac{2}{-15}=\dfrac{-5}{3}\)
\(x=\dfrac{-5}{3}-\dfrac{-2}{15}\)
\(x=\dfrac{-23}{15}\)