mk cũng ko biết bn à

\(\frac{5-\frac{5}{3}+\frac{5}{9}-\frac{5}{27}}{8-\frac{8}{3}+\frac{8}{9}-\frac{8}{27}}:\frac{15-\frac{15}{11}+\frac{15}{121}}{16-\frac{16}{11}+\frac{16}{121}}\)

\(=\frac{5\left(1-\frac{1}{3}+\frac{1}{9}-\frac{1}{27}\right)}{8\left(1-\frac{1}{3}+\frac{1}{9}-\frac{1}{27}\right)}:\frac{15\left(1-\frac{1}{11}+\frac{1}{121}\right)}{16\left(1-\frac{1}{11}+\frac{1}{121}\right)}\)

\(=\frac{5}{8}:\frac{15}{16}\)

\(=\frac{2}{3}\)

2/3

Tk mk nha

`39/16 : 5/8 - 7/16 : 5/8`

`=39/16 xx 8/5- 7/16 xx 8/5`

`=8/5 xx (39/16 - 7/16)`

`= 8/5 xx2`

`= 16/5`

__

` 4/3 xx 9/8 - 4/3 xx 3/8`

`=4/3 -(9/8 - 3/8)`

`= 4/3 xx 3/4`

`=1`

\(a,\\ \dfrac{39}{16}:\dfrac{5}{8}-\dfrac{7}{16}:\dfrac{5}{8}\\ =\dfrac{39}{16}\cdot\dfrac{8}{5}-\dfrac{7}{16}\cdot\dfrac{8}{5}\\ =\dfrac{8}{5}\cdot\left(\dfrac{39}{16}-\dfrac{7}{16}\right)=\dfrac{8}{5}\cdot2=\dfrac{16}{5}\\ b,\\ \dfrac{4}{3}\cdot\dfrac{9}{8}-\dfrac{4}{3}\cdot\dfrac{3}{8}=\dfrac{3}{2}-\dfrac{1}{2}=1\)

a)

`39/16:5/8-7/16:5/8`

`=(39/16-7/16):5/8`

`=32/16xx8/5`

`=2xx8/5`

`=16/5`

b)

`4/3xx9/8-4/3xx3/8`

`=4/3xx(9/8-3/8)`

`=4/3xx6/8`

`=4/3xx3/4`

`=1`

Bài này bạn tính thôi

Trình bày ra 

Rồi làm thôi

Áp dụng công thức tính phân số ở Tiểu học

\(\frac{5\times\left(1-\frac{1}{3}+\frac{1}{9}-\frac{1}{27}\right)}{8\times\left(1-\frac{1}{3}+\frac{1}{9}-\frac{1}{27}\right)}\div\frac{15\times\left(1-\frac{1}{11}+\frac{1}{121}\right)}{16\times\left(1-\frac{1}{11}+\frac{1}{121}\right)}=\frac{5}{8}\div\frac{15}{16}=\frac{2}{3}\)

F=5-5x(1/3+1/9-1/27) /8-8x(1/3+1/9-1/27)

: 15-15x(1/11+1/121) /16-16x(1/11+1/121)

=5-5x1/8-8x1

: 15-15x1/16-16x1

=0:0=0

chắc vậy!

đi thi rồi dờ đưa lên à

\(a,=\dfrac{17}{12}\\ b,=\dfrac{3}{16}\\ c,=\dfrac{35}{72}\\ d,=\dfrac{3}{2}\)

a)17/12

b)3/16

c)35/72

d)3/2

chúc bạn học tốt nha <3

Phương pháp giải:

Tính nhẩm các số rồi điền kết quả vào chỗ trống.

Lời giải chi tiết:

Tính nhẩm:

\(=\frac{5-\frac{5}{3}-\frac{5}{9}-\frac{5}{27}}{8-\frac{8}{3}-\frac{8}{9}-\frac{8}{27}}:\frac{15-\frac{15}{11}+\frac{15}{121}}{16-\frac{16}{11}+\frac{16}{121}}\)

\(=\frac{5\left(1-\frac{1}{3}-\frac{1}{9}-\frac{1}{27}\right)}{8\left(1-\frac{1}{3}-\frac{1}{9}-\frac{1}{27}\right)}:\frac{15\left(1-\frac{1}{11}+\frac{1}{121}\right)}{16\left(1-\frac{1}{11}+\frac{1}{121}\right)}\)

\(=\frac{5}{8}:\frac{15}{16}=\frac{5}{8}.\frac{16}{15}=\frac{2}{3}\)