= 293 906 250 000

500 x 30 x 25 x 75 x 95 x 100 = 267187500000

500 x 30 x 25 x 75 x 95 x 110 = 293906250000

500x6+500x4-108:12:9

=500x(6+4)-9:9

=500x10-1

=5000-1

=4999

9782x35-9782x25+1000:5:2

=9782x(35-25)+200:2

=9782x10+100

=97820+100

=97920

37800:25:4+57+467x43

=1512:4+57+20081

=378+57+20081

=435+20081

=20516

a) 4.25-12.5+170:10

=100-60+17

=40+17

=57

b) (7+3³:3²).4-3

=(7+3).4-3

=10.4-3

=40-3

=37

c) 12:{400:[500-(125+25.7)]}

=12:{400:[500-(125+175)]}

=12:{400:[500-300]}

=12:{400:200}

=12:2

=6

d) 168+{[2.(2⁴+3²)-256⁰]:7²}

=168+{[2.(16+9)-1]:49}

=168+{[2.25-1]:49}

=168+{[50-1]:49}

=168+{49:49}

=168+1

=169

a,

36 x 40 = (36 x 4) x 10 = 144 x 10 = 1 440

72 x 60 = (72 x 6) x 10 = 432 x 10 = 4 320

89 x 50 = (89 x 5) x 10 = 445 x 10 = 4 450

b,

450 x 70 = (45 x 7) x 100 = 315 x 100 = 31 500

2300 x 500 = (23 x 5) x 10 000 = 115 x 10 000 = 1 150 000

17 000 x 30 = (17 x 3) x 10 000 = 510 000

câu 1. 7800

câu 2:1000

\(\left(x+1\right)+\left(x+2\right)+\left(x+3\right)+...+\left(x+30\right)=500\)

Số lượng số hạng là: \(30-1+1=30\)

\(\Rightarrow30x+\dfrac{30\left(30+1\right)}{2}=500\)

\(30x+465=500\)

\(30x=35\)

\(x=\dfrac{7}{6}\)

\(\left(x+1\right)+\left(x+2\right)+...+\left(x+30\right)=500\)

\(\Rightarrow x+1+x+2+..+x+30=500\)

\(\Rightarrow\left(x+x+...+x\right)+\left(1+2+...+30\right)=500\)

\(\Rightarrow30\cdot x+465=500\)

\(\Rightarrow30\cdot x=500-465\)

\(\Rightarrow30\cdot x=35\)

\(\Rightarrow x=\dfrac{35}{30}\)

\(\Rightarrow x=\dfrac{7}{6}\)

GIÚP MÌNH VỚI Ạ 

\(a,\left(3x-17\right)4^2=4^3\)

\(3x-17=4\)

\(3x=21\)

\(x=7\)

\(b,5x-18=-3\)

\(5x=15\)

\(x=3\)

\(c,\hept{\begin{cases}x⋮12\\x⋮25\\x⋮30\end{cases}}\)\(\Rightarrow x\in B\left(12;25;30\right)\) 

rồi tìm , lâu , quên =>>  tìm BC xog thì xét ĐK rồi KL 

\(\text{a) (3x - 17) . 4^2= 4^3}\)

\(\Rightarrow3x-17=4^3:4^2=4\)

\(\Rightarrow3x=4+17=21\)

\(\Rightarrow x=7\)

\(\text{b) 5x - 18 = -3}\)

\(\Rightarrow5x=-3+18=15\)

\(\Rightarrow x=15:5=3\)

c) x chia hết cho 12; x chia hết cho 25; x chia hết cho 30 và 0 < x< 500.

\(\Rightarrow x⋮12,x⋮25,x⋮30\)

\(\Rightarrow x\in BC\left(12,15,30\right)=30\)

\(\Rightarrow x\in\left\{0,30,60,90,120,150,...,480,....\right\}\)

Mà 0<x<500

\(\Rightarrow x\in\left\{30,60,90,120,150,...,480\right\}\)

học tốt

t.i.k nha

a) ( 3. x - 17 ) . 4² = 4³

<=> 3.x - 17          = 4³ :4²

<=> 3.x - 17          = 4

<=> 3.x                = 4 + 17

<=> 3.x                  = 21

<=> x                     = 21 : 7

<=> x                    = 3

Vậy x 3

b) 5.x - 18 = -3

<=> 5.x       = (-3) + 18

<=> 5.x        = 15

<=> x          = 15 : 5

<=> x          = 3

Vậy x = 3

c) Ta có : \(\hept{\begin{cases}x⋮12\\x⋮25\\x⋮30\end{cases}\Rightarrow x\in BC\left(12;25;30\right)}\)

Mà \(\hept{\begin{cases}12=2^2.3\\25=5^2\\30=2.3.5\end{cases}\Rightarrow BCNN\left(12,25,30\right)=300}\)

=> BC(12,25,30)=B(300 ) = { 0;300; 600 ;900 ;1200 ;... }

Mà 0< x < 500 = > x = 300

Vậy x = 300

\(BCNN\left(12;25;30\right)=300\)

\(\Rightarrow x=300\) ( t/m điều kiện )

`=> x in BC(12, 25, 30)`.

Ta có: `12 = 2^2 xx 3`.

`25 = 5^2`.

`30 = 5 xx 2 xx 3`.

`=> x in B(300)`.

`=> x in {0, 300, 600, ...}` mà `0 <= x <= 500`

`=> x = 0, 300`.

`=>` Ta có:

`BCNNN (12; 25; 30) = 300`

`=>` `x = 300` vì:

`0 <= x <= 500`