2019+2019+2019+2019+2019x7-2019
tính nhanh phép tính : 2019+2019+2019+2019+2019x7-2019
\(2019+2019+2019+2019+2019\times7-2019\\ =2019\times\left(1+1+1+1+7-1\right)\\ =2019\times10\\ =20190\)
Tính bằng cách thuận tiện nhất.
2019 + 2019 +2019 + 2019 + 2019 x 7 - 2019
= 2019 x ( 7 +1 +1+1 - 1 ) = 2019 x 10 = 20190
Tính :A= [(2018/1)+(2017/2)+(2016/3)+(2015/4)+...+(4/2015)+(3/2016)+(2/2017)+(1/2018)]/[(2019/2)+(2019/3)+(2019/4)+(2019/5)+...+(2019/2015)+(2019/2016)+(2019/2017)+(2019/2018)+(2019/2019)]
Tính :A= [(2018/1)+(2017/2)+(2016/3)+(2015/4)+...+(4/2015)+(3/2016)+(2/2017)+(1/2018)]/[(2019/1)+(2019/2)+(2019/3)+(2019/4)+...+(2019/2015)+(2019/2016)+(2019/2017)+(2019/2018)+(2019/2019)]
Tính bằng cách thuận tiện nhất.
2019 + 2019 +2019 + 2019 + 2019 x 7 - 2019
Tính bằng cách thuận tiện nhất.
2019 + 2019 +2019 + 2019 + 2019 x 7 - 2019
= 2019 x ( 7 +1 +1+1 - 1 ) = 2019 x 10 = 20190
Cho \(\dfrac{x^2+y^2+z^2}{a^2+b^2+c^2}=\dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}+\dfrac{z^2}{c^2}\)
CMR:\(\dfrac{x^{2019}+y^{2019}+z^{2019}}{a^{2019}+b^{2019}+c^{2019}}=\dfrac{x^{2019}}{a^{2019}}+\dfrac{y^{2019}}{b^{2019}}+\dfrac{z^{2019}}{c^{2019}}\)
Giups mk vs ạ ai nhanh mk tick nha
Lời giải:
Đặt \(\frac{x}{a}=m; \frac{y}{b}=n; \frac{z}{c}=p\). Khi đó:
ĐKĐB $\Leftrightarrow \frac{a^2m^2+b^2n^2+c^2p^2}{a^2+b^2+c^2}=m^2+n^2+p^2$
$\Rightarrow a^2m^2+b^2n^2+c^2p^2=(a^2+b^2+c^2)(m^2+n^2+p^2)$
$\Leftrightarrow a^2n^2+a^2p^2+b^2m^2+b^2p^2+c^2m^2+c^2n^2=0$
$\Rightarrow an=ap=bm=bp=cm=cn=0$
Vì $a,b,c\neq 0$ nên $m=n=p=0$
$\Rightarrow x=y=z=0$
Khi đó:
$\frac{x^{2019}+y^{2019}+z^{2019}}{a^{2019}+b^{2019}+c^{2019}}=0$
$\frac{x^{2019}}{a^{2019}}=\frac{y^{2019}}{b^{2019}}=\frac{z^{2019}}{c^{2019}}=0$
$\Rightarrow$ đpcm
Cho xyz=2019
Cm A = 2019/2019+x+xy + 2019/2019+z+xz + 2019/2019+y+yz thuộc N
tính bằng cách thuận tiện nhất: 2019+2019+2019+2019+2019 nhân 7-2019=?
2019 + 2019 + 2019 + 2019 + 2019 . ( 7-2019 )
= 2019 . 5 . ( -2012 )
= - 20311140
Học tốt
tính bằng cách thuận tiện nhất:
2019+2019+2019+2019+2019x7-2019=20190
# hok tốt #
Câu 4 Tính bằng cách thuận tiện nhất.
2019 + 2019 +2019 + 2019 + 2019 x 7 - 2019
`2019 + 2019 + 2019 + 2019 + 1029 xx 7 - 2019`
`= 2019 xx ( 1 + 1 + 1 + 1 + 7 - 1 )`
`= 2019 xx 10`
`= 20190`
2019 + 2019 +2019 + 2019 + 2019 x 7 - 2019
= 2019 x ( 7 +1 +1+1 - 1 )
= 2019 x 10
= 20190
2019 + 2019 +2019 + 2019 + 2019 x 7 - 2019
= 2019 x 1 + 2019 x 1 + 2019 x 1 + 2019 x 1 + 2019 x 7 - 2019 x 1
= 2019 x ( 1 + 1 + 1 + 1 + 7 - 1 )
= 2019 x 10
= 20190
cho a+b=c+1/2019 ; 1/a+1/b=1/c+2019 tính A=(a^2019+b^2019-c^2019)(1/a^2019+1/b^2019-1/c^2019)