bằng 0

 (128,36×0,25+128,36×0,75)×(11×9-900×0,1-9)

=(128,36×0,25+128,36×0,75) X  0

=           0

0=nịt

a) 20 × 190 × 50 = (20 × 50) × 190 = 1000 × 190

= 190000

b) (900 × 28) ÷ 9 = (900 ÷ 9) × 28 = 100 × 28 = 2800

\(900\times28:9\\ =\left(900:9\right)\times28\\ =100\times28\\ =2800\)

(900x28):9

=(900:9)x28

=100x28

=2800

\(900\times28:9\)
\(\Rightarrow\left(900:9\right)\times28\)
\(\Rightarrow100\times28\)
\(\Rightarrow2800\)

(20,1*20,2 + 28,3 *12,4 ) * (11*9 -900*0.1-9)

=(20,1 *20,2 +28,3 *12.4)*(99-90-9) 

=20,1* 20,2 +28,3 *12,4 )*0 

=0

(792,81 x 0,25 + 792,81 x 0,75) x (11 x 9 - 900 x 0,1 - 9)

= (792,81 x 0,25 + 792,81 x 0,75) x 9 x (11 - 100 x 0,1 - 1)

= (792,81 x 0,25 + 792,81 x 0,75) x 9 x (11 - 10 - 1)

= 792,81 x 0,25 + 792,81 x 0,75) x 9 x 0

= 0

126 : 3 + 231 : 3 + 543 : 3

= ( 126 + 231 + 543 ) : 3

= 900 : 3

= 300

126 : 3 + 231 : 3 + 543 : 3

= \(126.\frac{1}{3}+231.\frac{1}{3}+543.\frac{1}{3}\)

=\(\frac{1}{3}\left(126+231+543\right)=\frac{1}{3}.900=300\)

126 : 3 + 231 : 3 + 543 : 3

= ( 126 + 231 + 543 ) : 3

= 900 : 3 = 300

P/s : Hình thức câu mới à Bonking ( -_- )

\((\frac{1}{2}+\frac{1}{4}+\frac{1}{6}) \)x \((\frac{36}{9}-\frac{12}{9}:\frac{1}{3}) \)

\(= (\frac{1}{2}+\frac{1}{4}+\frac{1}{6}) \) x \((\frac{36}{9}-\frac{36}{9})\)

\( = (\frac{1}{2}+\frac{1}{4}+\frac{1}{6}) \) x \(0\)

\(= 0\)

Hướng dẫn giải:

a.

17 x 543 + 83 x 543

= (17 + 83) x 543

= 100 x 543

= 54300

b.

318 x 963 + 682 x 963

= (318 + 682) x 963

= 1000 x 963

= 963000

a)17x543+83x543

=(17+83)x543

=100x543

=54300

b)318x963+682x963

=(318+682)x963

=1000x963

=963000

TL

1+2+3+4+5+6+7+8+9=45

nha bn

HT

1+2+3+...+9

=(1+9)+(2+8)+...+5

=10+10+...+5

=10.4+5

=45

HT

45

nha bn

HT

OK