k.x^2-xy-6x+9+3y
L.x^2+4-y^2+4x
Những câu hỏi liên quan
Phân tích đa thức thành nhân tử
5x^2y - 10x^2y^2 + 5xy^3
4x^3 - 36
X^2 - 4
X^2 - 6x + 9
27 + 27x + 9x ^2 +x^3
X^2 - 25 -2 xy +y^2
7y^4 - 14y^3 + 7y^2
1 - 4x^2
3x + 9 + 4x^2 + 12x
(X + 1 )^2 - 25
X^2 - y^2 + 4x +4
6x^2 + 6xy - 7x - 7y
a(15 xy^2z^3 :(3xyz^2)
b(12 x^y^4 : (-4x^4y^2)
c (-15x^2y^3z^2 ) :(-6xz^2)
d(x-y)^5 : (y-x)^3
(x-y)^5 : (y-x)^2
f(3xy-6x)^3 : 9(2x-y)
a: \(15xy^2z^3:3xyz^2=5yz\)
b: \(12x^4y^4:\left(-4x^4y^2\right)=-3y^2\)
c: \(\dfrac{-15x^2y^3z^2}{-6xz^2}=\dfrac{5}{2}xy^3\)
d: \(\dfrac{\left(x-y\right)^5}{\left(y-x\right)^3}=-\left(x-y\right)^2\)
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Nhân đa thức:
a) (1/2xy-3/4).(1/2xy+3/4)
b) (2x+3).(4x mũ 2 - 6x+9)
c) (xy-2).(x mũ 2 y mũ 2 + 2xy + 4)
a, \(\left(\frac{1}{2}xy-\frac{3}{4}\right)\left(\frac{1}{2}xy+\frac{3}{4}\right)=\frac{1}{4}x^2y^2+\frac{3}{8}xy-\frac{3}{8}xy-\frac{9}{16}=\frac{1}{4}x^2y^2-\frac{9}{16}\)
b, \(\left(2x+3\right)\left(4x^2-6x+9\right)=8x^3-12x^2+18x+12x^2-18x+27=8x^2+27\)
c, \(\left(xy-2\right)\left(x^2y^2+2xy+4\right)=x^3y^3+2x^2y^2+4xy-2x^2y^2-4xy-8=x^3y^3-8\)
Mk ko chép đề bài ra nhé
a, = 1/2xy.( -3/4 + 3/4 )
=1/2xy.
b, Áp dụng HĐT số 2, có: (Chỗ này ko cần chép cx đc)
=(2x+3).(2x+3)^2 (^ là mũ)
=(2x+3)^3
c, Áp dụng HĐT số 2, có:
=(xy-2).(xy + 2)^2
a)x^2(x-3)-4x+12 b)2a(x+y)-x+y c)6x^2-12x-7x+14 d)xy-y^2-3x+3y f)x^2y+xy^2-4x-4y g)10ax-5ay-7x+14 j)a^3-a^2+9a-9(tính nhân tử chung)
a: \(x^2\left(x-3\right)-4x+12\)
\(=x^2\left(x-3\right)-4\left(x-3\right)\)
\(=\left(x-3\right)\left(x-2\right)\left(x+2\right)\)
b: \(2a\left(x+y\right)+x+y=\left(x+y\right)\left(2a+1\right)\)
c: \(6x^2-12x-7x+14\)
\(=6x\left(x-2\right)-7\left(x-2\right)\)
\(=\left(x-2\right)\left(6x-7\right)\)
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Tìm số thực z,y,z thoả mãn
xy / 2y+4x = yz / 4z+6x = zx/ 6x+2z = x^2+y^2+z^2 / 2^2+4^2+6^2
Cho x,y thỏa mãn :\(\left\{{}\begin{matrix}6x^2-y^2+xy-6y-12x=0\\4x^2-xy+9=0\end{matrix}\right.\)
Bài 1: (5đ) Phân tích đa thức thành nhân tử.
a) 4x^3 - x^2
b) 6x - 4 + x(2 - 3x)
c) xy + 1 - x - y
d) y^2 - 4x^2 + 4y + 4
e) x^2 - 3x + 2
\(a,=x\left(4x^2-1\right)=x\left(2x-1\right)\left(2x+1\right)\\ b,=2\left(3x-2\right)-x\left(3x-2\right)=\left(2-x\right)\left(3x-2\right)\\ c,=x\left(y-1\right)-\left(y-1\right)=\left(x-1\right)\left(y-1\right)\\ d,=\left(y+2\right)^2-4x^2=\left(y+2-2x\right)\left(y+2+2x\right)\\ e,=x^2-x-2x+2=\left(x-1\right)\left(x-2\right)\)
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a) \(4x^3-x^2=x^2\left(4x-1\right)\)
b) \(6x-4+x\left(2-3x\right)=2\left(3x-2\right)-x\left(3x-2\right)=\left(2-x\right)\left(3x-2\right)\)
c) \(xy+1-x-y=\left(xy-x\right)-\left(y-1\right)=x\left(y-1\right)-\left(y-1\right)=\left(x-1\right)\left(y-1\right)\)
d) \(y^2-4x^2+4y+4=\left(y^2+4y+4\right)-4x^2=\left(y+2\right)^2-\left(2x\right)^2=\left(y-2x+2\right)\left(y+2x+2\right)\)
e) \(x^2-3x+2=\left(x^2-x\right)-\left(2x-2\right)=x\left(x-1\right)-2\left(x-1\right)=\left(x-1\right)\left(x-2\right)\)
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(x-5).y+2x-10=7
2.（3-y)-x(y-3)=19
xy-x=2y+9
xy-3y+6x=17+2x2
x2y+4x=11+2xy
bài 4 phân tích
3x^2-30x+75
xy -x^2-x^2-x
x^2-7x-8
4x^3 +8x^2y+4xy^2-16x
xy+xz -2y-2z
x^2+6x+9-y^3
a)\(=3\left(x-5\right)^2\)
b)\(=x\left(y-2x-1\right)\)
c)\(=\left(x+1\right)\left(x-8\right)\)
d)\(=4x\left(x+y+2\right)\left(x+y-2\right)\)
e)\(=\left(y+z\right)\left(x-2\right)\)
g)\(=\left(x+3+y\right)\left(x+3-y\right)\)
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