a: Ta có: \(\left(2^{17}+17^2\right)\cdot\left(9^{15}-3^{15}\right)\cdot\left(2^4-4^2\right)\)

\(=\left(2^{17}+17^2\right)\cdot\left(9^{15}-3^{15}\right)\cdot\left(16-16\right)\)

=0

b: Ta có: \(\dfrac{8^{2017}-8^{2015}}{8^{2104}\cdot8}\)

\(=\dfrac{8^{2015}\cdot\left(8^2-1\right)}{8^{2105}}\)

\(=\dfrac{1\cdot63}{8^{90}}\)+

c: Ta có: \(\left(1^3+2^3+3^4+4^5\right)\cdot\left(1^3+2^3+3^3+4^3\right)\cdot\left(3^8-81^2\right)\)

\(=\left(1^3+2^3+3^4+4^5\right)\cdot\left(1^3+2^3+3^3+4^3\right)\cdot\left(3^8-3^8\right)\)

=0

d: Ta có: \(\left(2^8+8^3\right):\left(2^5\cdot2^3\right)\)

\(=\dfrac{2^8+2^9}{2^8}\)

=3

a,  2 17 + 17 2 9 15 - 3 15 2 4 - 4 2

=  2 17 + 17 2 9 15 - 3 15 16 - 16

=  2 17 + 17 2 9 15 - 3 15 . 0

= 0

b,  1 2 + 2 3 + 3 4 + 4 5 . ( 1 3 + 2 3 + 3 3 + 4 3 ) ( 3 8 - 81 2 )

=  1 2 + 2 3 + 3 4 + 4 5 . ( 1 3 + 2 3 + 3 3 + 4 3 ) ( 3 4 . 2 - 81 2 )

=  1 2 + 2 3 + 3 4 + 4 5 . ( 1 3 + 2 3 + 3 3 + 4 3 ) ( 81 2 - 81 2 )

=  1 2 + 2 3 + 3 4 + 4 5 . ( 1 3 + 2 3 + 3 3 + 4 3 ) . 0

= 0

c,  7 24 + 7 23 : 7 22

=  7 24 : 7 22 + 7 23 : 7 22

=  7 24 - 22 + 7 23 - 22

=  7 2 + 7 1

= 49 + 7 = 56

a) (217 + 172).(915 – 315).(24 – 42)

= (217 + 172).(915 – 315).(16 - 16)

= 0

Vậy giá trị cần tìm là: 0

b) (82017 – 82015) : (82104.8)

= 82015.(82- 1) : 82015 

= 64 – 1

= 63

Vậy giá trị cần tìm là: 63

a) 0

b) 63

a) (2¹⁷+ 17²).(9¹⁵– 3¹⁵).(2⁴ – 4²)

= (2¹⁷ + 17²).(9¹⁵ – 3¹⁵).(16 - 16)

= 0

Vậy giá trị cần tìm là: 0

b) (8²⁰¹⁷– 8²⁰¹⁵) : (8²¹⁰⁴.8)

= 8²⁰¹⁵.(8²- 1) : 8²⁰¹⁵ 

= 64 – 1

= 63

Vậy giá trị cần tìm là: 63

\(a,A=\left(2^{17}+17^2\right)\left(9^{15}-3^{30}\right).\left(2^4-32^2\right)\)

\(\Rightarrow A=\left(2^{17}+17^2\right)\left(3^{30}-3^{30}\right).\left(2^4-32^2\right)\)

\(\Rightarrow A=\left(2^{17}+17^2\right).0.\left(2^4-32^2\right)\)

\(\Rightarrow A=0.\)

\(\Rightarrow B=\left(2^8.8^3\right):\left(2^5.2^3\right)\)

\(\Rightarrow B=\left(2^8.2^9\right):\left(2^5.2^3\right)\)

\(\Rightarrow B=2^{17}:2^8\)

\(\Rightarrow B=2^9\)

\(\Rightarrow B=512\)

\(c,C=64^4.16^5:4^{20}\)

\(\Rightarrow C=2^{24}.2^{20}:2^{40}\)

\(\Rightarrow C=2^4\)

\(\Rightarrow C=16\)

a: \(A=\left(2^{17}+17^2\right)\cdot\left(2^4-32^2\right)\cdot\left(3^{30}-3^{30}\right)=0\)

b: \(B=\dfrac{2^8\cdot2^9}{2^5\cdot2^3}=2^9\)

c: \(C=2^{24}\cdot2^{20}:2^{40}=2^4=16\)

\(\left(1^2+2^3+3^4+4^5\right)\left(1^3+2^3+3^3+4^3\right)\left(3^8-81^2\right)\\ =\left(1^2+2^3+3^4+4^5\right)\left(1^3+2^3+3^3+4^3\right)\left[3^8-\left(3^4\right)^2\right]\\ =\left(1^2+2^3+3^4+4^5\right)\left(1^3+2^3+3^3+4^3\right)\left(3^8-3^8\right)\\ =\left(1^2+2^3+3^4+4^5\right)\left(1^3+2^3+3^3+4^3\right).0=0\)

\(\left(1^2+2^3+3^4+4^5\right)\left(1^3+2^3+3^3+4^3\right)\left(3^8-81^2\right)=\left(1^2+2^3+3^4+4^5\right)\left(1^3+2^3+3^3+4^3\right)\left(3^8-3^8\right)=\left(1^2+2^3+3^4+4^5\right)\left(1^3+2^3+3^3+4^3\right).0=0\)

đáp án bằng 0

Vì ta phân tích \(2^4\) bằng \(4^2\) nên khi ta trừ cho nhau =0

Mặt khác tất cả các số nhân với nhau bằng 0

\(\left(2^{17}+17^2\right).\left(9^{15}-3^{15}\right).\left(2^4-4^2\right)\\ =\left(2^{17}+17^2\right).\left(9^{15}-3^{15}\right).\left(16-16\right)\\ =\left(2^{17}+17^2\right).\left(9^{15}-3^{15}\right).0=0\)