x²-4xy+4y²-x+2y=(x-2y)²-(x-2y)

                         =(x-2y)(x-2y-1)

1.A

2.C

3.B

4.C

a

c

b

c

(x-1)y^2-4(x-1)y

x² - 2x + 2y - xy = (x² - 2x) - (xy - 2y) = x(x - 2) - y(x - 2) = (x - 2)(x - y)

x² + 4xy - 16 + 4y² = (x² + 4xy + 4y²) - 16 = (x + 2y)² - 16 = (x + 2y + 4)(x + 2y - 4)

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CHỊU!!!

\(R=\left(2x\right)^2-2.2x.y+y^2\\ =\left(2x-y\right)^2\\ =>D\)

\(1,=x\left(x^2-2x+1-y^2\right)=x\left[\left(x-1\right)^2-y^2\right]=x\left(x-y-1\right)\left(x+y-1\right)\\ 2,=\left(x+y\right)^3\\ 3,=\left(2y-z\right)\left(4x+7y\right)\\ 4,=\left(x+2\right)^2\\ 5,Sửa:x\left(x-2\right)-x+2=0\\ \Leftrightarrow\left(x-2\right)\left(x-1\right)=0\Leftrightarrow\left[{}\begin{matrix}x=1\\x=2\end{matrix}\right.\)

\(=4xy\left(1-5x^2y+4xy\right)\)

=4xy(1-  5x²y+4xy) 

= 4xy ( 1 - 20x²y + 4xy )

\(=y\times\left(x^2+4x+4-y^2\right)\)

\(=y\left[\left(x+2\right)^2-y^2\right]=y\left(x+2-y\right)\left(x+2+y\right)\)

quên rồi

lười quá ban

a) Xem lại đề

b) x³ - 4x²y + 4xy² - 9x

= x(x² - 4xy + 4y² - 9)

= x[(x² - 4xy + 4y² - 3²]

= x[(x - 2y)² - 3²]

= x(x - 2y - 3)(x - 2y + 3)

c) x³ - y³ + x - y

= (x³ - y³) + (x - y)

= (x - y)(x² + xy + y²) + (x - y)

= (x - y)(x² + xy + y² + 1)

d) 4x² - 4xy + 2x - y + y²

= (4x² - 4xy + y²) + (2x - y)

= (2x - y)² + (2x - y)

= (2x - y)(2x - y + 1)

e) 9x² - 3x + 2y - 4y²

= (9x² - 4y²) - (3x - 2y)

= (3x - 2y)(3x + 2y) - (3x - 2y)

= (3x - 2y)(3x + 2y - 1)

f) 3x² - 6xy + 3y² - 5x + 5y

= (3x² - 6xy + 3y²) - (5x - 5y)

= 3(x² - 2xy + y²) - 5(x - y)

= 3(x - y)² - 5(x - y)

= (x - y)[(3(x - y) - 5]

= (x - y)(3x - 3y - 5)