Phân tích đa thức thành nhân tử
1. x^7+x^2+1
2. X^7+x^5+1
3. X^4+x6x^3+7x^2-6x+1
Phân tích đa thức thành nhân tử
1)x^2-3x+2
2)x^2-x-6
3)x^2+7x+12
1: \(x^2-3x+2=\left(x-1\right)\left(x-2\right)\)
2: \(x^2-x-6=\left(x-3\right)\left(x+2\right)\)
3: \(x^2+7x+12=\left(x+3\right)\left(x+4\right)\)
Phân tích đa thức thành nhân tử
1)x^2-3x+2
2)x^2-x-6
3)x^2+7x+12
1) \(x^2-3x+2=\left(x^2-x\right)-\left(2x-2\right)=x\left(x-1\right)-2\left(x-1\right)=\left(x-1\right)\left(x-2\right)\)
2) \(x^2-x-6=\left(x^2-3x\right)+\left(2x-6\right)=x\left(x-3\right)+2\left(x-2\right)=\left(x-2\right)\left(x-3\right)\)
3) \(x^2+7x+12=\left(x^2+3x\right)+\left(4x+12\right)=x\left(x+3\right)+4\left(x+3\right)=\left(x+3\right)\left(x+4\right)\)
1: \(x^2-3x+2=\left(x-1\right)\left(x-2\right)\)
2: \(x^2-x-6=\left(x-3\right)\left(x+2\right)\)
3: \(x^2+7x+12=\left(x+3\right)\left(x+4\right)\)
Phân tích đa thức thành nhân tử
1. x^7 + x^2 + 1
2. x^7 + x^5 +1
3. x^4 + 6x^3 + 7x^2 - 6x+1
phân tích đa thức thành nhân tử
1. 6x^2 + 15x
2. 9x^2 - 1
3. x^2 + 6x -y^2 +9
1. \(=3x\left(2x+5\right)\)
2. \(=\left(3x-1\right)\left(3x+1\right)\)
3. \(=\left(x+3\right)^2-y^2=\left(x-y+3\right)\left(x+y+3\right)\)
1, = 3x.(2x + 5)
2. = (3x)2 - 12 = (3x - 1).(3x +1 )
3, =(x2 + 6x + 9) - y2 = (x + 3)2 - y2 =(x + y -3 ). (x - y +3)
3.\(x^2+6x-y^2+9=\left(x^2+6x+9\right)-y^2=\left(x+3\right)^2-y^2=\left(x+3-y\right)\left(x+3+y\right)\)
phân tích đa thức thành nhân tử
1 + 6x -6x\(^2\) - x\(^3\)
Ta có: \(1+6x-6x^2-x^3\)
\(=-x^3-6x^2+6x+1\)
\(=\left(-x^3+1\right)-6x\left(x-1\right)\)
\(=-\left(x-1\right)\left(x^2+x+1\right)-6x\cdot\left(x-1\right)\)
\(=\left(x-1\right)\left(-x^2-x-1-6x\right)\)
\(=-\left(x-1\right)\left(x^2+7x+1\right)\)
\(1+6x-6x^2-x^3\)
= (1-x^3)+(6x-6x^2)
=(1-x)(1+x+x^2)+6x(1-x)
=(1-x)( 1+ x+ x^2 + 6x)
=(1-x)(1+x^2 +7x)
Đây bạn ơi!
Phân tích đa thức thành nhân tử
1) 2xy^3-6x^2+10xy
2) a^6-a^5-2a^3+2a^2
3) (a+b)^3-(a-b)^3
4) x^3-3x^2+3x-1-y^3
5) y(x^2+1)-x(y^2+1)
1) \(2xy^3-6x^2+10xy\)
\(=2x.y^3-2x.3x+2x.5y\)
\(=2x\left(y^3-3x+5y\right)\)
\(=2x[y\left(y^2-5\right)-3x]\)
2) \(a^6-a^5-2a^3+2a^2\)
\(=\left(a^6-a^5\right)-\left(2a^3-2a^2\right)\)
\(=\left(a^5.a-a^5.1\right)-\left(2a^2.a-2a^2.1\right)\)
\(=a^5\left(a-1\right)-2a^2\left(a-1\right)\)
\(=\left(a^5-2a^2\right)\left(a-1\right)\)
\(=a^2\left(a^3-2\right)\left(a-1\right)\)
3: \(\left(a+b\right)^3-\left(a-b\right)^3\)
\(=\left(a+b-a+b\right)\left(a^2+2ab+b^2+a^2-b^2+a^2-2ab+b^2\right)\)
\(=2b\left(3a^2+b^2\right)\)
Phân tích đa thức thành nhân tử
1)3x^2+x-2
2)x^4+x^2+1
3)x^2+2xy-15y^2
\(3x^2+x-2=3x^2-2x+3x-2=x\left(3x-2\right)+\left(3x-2\right)=\left(x+1\right)\left(3x-2\right)\)
\(x^4+x^2+1=\left(x^4+2x^2+1\right)-x^2=\left(x^2+1\right)^2-x^2=\left(x^2-x+1\right)\left(x^2+x+1\right)\)
\(x^2+2xy-15y^2=x^2-3xy+5xy-15y^2=x\left(x-3y\right)+5y\left(x-3y\right)=\left(x+5y\right)\left(x-3y\right)\)
1: \(3x^2+x-2=\left(x+1\right)\left(3x-2\right)\)
2: \(x^4+x^2+1=\left(x^2+1-x\right)\left(x^2+x+1\right)\)
3: \(x^2+2xy-15y^2=\left(x+5y\right)\left(x-3y\right)\)
Bài 1: Phân tích đa thức sau thành nhân tử
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Phân tích đa thức thành nhân tử
1, x\(^2\)-xy+x-y
2, xz+yz-5x-5y
3, 3x\(^2\)-3xy-5x+5y
4, x\(^2\)-2xy+y\(^2\)-xz+yz
5, 3x\(^2\)+6xy+3y\(^2\)-3z\(^2\)
6, 45+x\(^{^{ }3}\)-5x\(^2\)-9x
7, x\(^2\)-6x+5
8,x\(^2\)+7x+12
9, 2x\(^2\)-7x+3
10, 3x\(^2\)-12y\(^2\)
11, 5xy\(^2\)-10xyz+5xz\(^2\)
12,x\(^2\)-y\(^2\)-x+y
13, a\(^3\)x-ab+b-x
14, (1+x\(^2\))-4x(1-x\(^2\))
CÁC CẬU GIẢI CHI TIẾT GIÚP MÌNH VỚI Ạ
13: =x(a^3-1)-b(a-1)
=x(a-1)(a^2+a+1)-b(a-1)
=(a-1)(a^2x+a*x+x-b)
12: =(x-y)(x+y)-(x-y)
=(x-y)(x+y-1)
10: =3(x^2-4y^2)
=3(x-2y)*(x+2y)
7: =x^2-x-5x+5=(x-1)(x-5)
8: =x^2+3x+4x+12=(x+3)(x+4)
9: =2x^2-6x-x+3=(x-3)(2x-1)