Question

Phân tích đa thức thành nhân tử
1)3x^2+x-2
2)x^4+x^2+1
3)x^2+2xy-15y^2

Answer 1

\(3x^2+x-2=3x^2-2x+3x-2=x\left(3x-2\right)+\left(3x-2\right)=\left(x+1\right)\left(3x-2\right)\)

\(x^4+x^2+1=\left(x^4+2x^2+1\right)-x^2=\left(x^2+1\right)^2-x^2=\left(x^2-x+1\right)\left(x^2+x+1\right)\)

\(x^2+2xy-15y^2=x^2-3xy+5xy-15y^2=x\left(x-3y\right)+5y\left(x-3y\right)=\left(x+5y\right)\left(x-3y\right)\)

 

Answer 2

Answer 3

1: \(3x^2+x-2=\left(x+1\right)\left(3x-2\right)\)

2: \(x^4+x^2+1=\left(x^2+1-x\right)\left(x^2+x+1\right)\)

3: \(x^2+2xy-15y^2=\left(x+5y\right)\left(x-3y\right)\)