= 0 nhé!

250 : 50 - ( 46 - 75 + 54 ) : 5 

=  5 - 25 : 5

=  5 - 5

= 0

Các bạn tk cho mình nha

\(250:50-\left(46-75+54\right):5\)

\(=5-\left[\left(-29\right)+54\right]:5\)

\(=5-25:5\)

\(=5:5=0\)

687+(2×5)+10

=687+10+10

=697+10

=707

`687 + (2 × 5) + 10`

`= 687 + 10 + 10`

`= 697 + 10`

`= 707`

687+(2x5)+10= 687+10+10=707

Lời giải:
$A=2^{50}-2^{49}-...2^2-2$

$-A=2+2^2+2^3+...+2^{49}-2^{50}$

$-2A=2^2+2^3+2^4+...+2^{50}-2^{51}$

$-A-(-2A)=(2-2^{50})-(2^{50}-2^{51})$

$A=2-2^{50}-2^{50}+2^{51}=2-2^{51}+2^{51}=2$

900 + ( 120 : 1 + 0 : 250 ) = 900 + ( 120 + 0 )

                                          = 900 + 120

                                          = 1020

Chúc bạn học tốt ! Mik hứa sẽ tk lại ! Thanks !

900+(120:1+0:250)

=900+(120+0)

=900+120

=1020

=900+(120+0)

=900+120

=1020

~  dễ ợt~

464 + 38 + 536 + 162 + 250

= ( 464 + 536 ) + ( 38 + 162 ) + 250

= 1000 + 200 + 250

= 1450

a) = 8 . 15 - [115- 7² ]

     = 8 . 15 - [115- 49 ]

     = 120    - 56

      = 64

b) = 100 : {250 : [450 - (2.125 - 8.25)]}

    = 100 : {250 : [450 - (250 - 200 )]}

     = 100 : {250 : [450 - 50]}

     = 100 : {250 :400}

     = 100 : 0,265

      = 0,00265

     = 

\(a,2^3.15-\left[115-\left(12-5\right)^2\right]\)

\(=8.15-\left[115-\left(12-5\right)^2\right]\)

\(=120-\left[115-7^2\right]\)

\(=120-\left[115-49\right]\)

\(=120-66\)

\(=54\)

\(b,100:\left\{250:\left[450-\left(2.5^3-2^3.25\right)\right]\right\}\)

\(=100:\left\{250:\left[450-\left(2.125-8.25\right)\right]\right\}\)

\(=100:\left\{250:\left[450-\left(250-200\right)\right]\right\}\)

\(=100:\left\{250:\left[450-50\right]\right\}\)

\(=100:\left\{250:400\right\}\)

\(=100:0,625\)

\(=160\)

a: \(2^3\cdot15-\left[115-\left(12-5\right)^2\right]\)

\(=8\cdot15-115+7^2\)

\(=54\)

b: \(100:\left\{250:\left[450-\left(2\cdot5^3-2^3\cdot25\right)\right]\right\}\)

\(=100:\left\{250:\left[450-50\right]\right\}\)

\(=100:\left\{250:400\right\}\)

\(=100:\dfrac{5}{8}=160\)

Mik làm 1 câu thôi sức ko

\(2^3.15-\left[115-\left(12-5\right)^2\right]=8.15-\left[115-7^2\right]=120-\left[115-49\right]=120-66=54\)

\(100:\left\{250:\left[450-\left(4.5^3-2^2.25\right)\right]\right\}=100:\left\{250:\left[450-\left(4.125-4.25\right)\right]\right\}=100:\left\{250:\left[450-\left(500-100\right)\right]\right\}\)

\(=100:\left[250:\left(450-400\right)\right]=100:\left(250:50\right)=100:5=20\)

a,2³ . 15 -[115-\((\)12-5)²]

= 8. 15 - [115- 7² ]

=120-[115-49]

=120-66

=54

b, 100:{250:[450-\((\)4.5³ - 2³.25)]}

=100:{250:[450-\((\)4.125-8.25)]}

=100:{250:[450-\((\)500-300)]}

=100:{250:[450-200]}

=100:{250:250}

=100:1

=100