Giúp mình câu 30
làm cho mình từ câu 21 đến câu 30 nha giúp mình với
21. didn’t go
22. isn’t painting
23. aren’t planting
24. Are they making
25. is repairing
26. is taking
27. is explaining
28. is studying
29. tries/ don’t think
30. passes
21. didn’t go
22. isn’t painting
23. aren’t planting
24. Are they making
25. is repairing
26. is taking
27. is explaining
28. is studying
29. tries/ don’t think
30. passes
GIÚP MÌNH TỪ CÂU 30 ĐẾN CÂU 39 VỚI Ạ!!
30B 31B 32D 33D 34C 35B 36B 37C 38B 39A 40D 41D 42A 43D 44D 45A 46C 47B 48C 49B 50C 51C 52B 53D 54B 55C 56A 57C 58A 59D 60B
GIÚP MÌNH CÂU 26 --> 30
Giúp mình câu 29 30
Giúp mình câu 29 30
Giúp mình câu 29 30
Giúp mình câu 29 30
Anh chưa thấy ndung câu hỏi em ạ
giúp mình câu 30 31 ạ
30.
\(V_{\left(O;\dfrac{3}{4}\right)}\left(M\right)=M_1\Rightarrow\left\{{}\begin{matrix}x_1=\dfrac{3}{4}.4=3\\y_1=\dfrac{3}{4}.1=\dfrac{3}{4}\end{matrix}\right.\)
\(Q_{\left(O;-90^0\right)}\left(M_1\right)=M'\Rightarrow\left\{{}\begin{matrix}x'=y_1=\dfrac{3}{4}\\y'=-x_1=-3\end{matrix}\right.\)
\(\Rightarrow M'\left(\dfrac{3}{4};-3\right)\)
31.
\(cos\dfrac{x}{2}=-\dfrac{\sqrt{3}}{2}\Rightarrow\dfrac{x}{2}=\pm\dfrac{5\pi}{6}+k2\pi\)
\(\Rightarrow x=\pm\dfrac{5\pi}{3}+k4\pi\)
Nghiệm dương nhỏ nhất \(x=\dfrac{5\pi}{3}\Rightarrow a+b=5+3=8\)
Giúp mình giải câu 29 , 30
\(\dfrac{x-7}{\left(x+2\right)\left(x-3\right)}>1\Leftrightarrow\dfrac{x-7-\left(x+2\right)\left(x-3\right)}{\left(x+2\right)\left(x-3\right)}>0\)
\(\Leftrightarrow\dfrac{-\left(x-1\right)^2}{\left(x+2\right)\left(x-3\right)}>0\Rightarrow x\in\left(-2;3\right)\backslash\left\{1\right\}\)
\(\Rightarrow2c+a-3b=2.1+\left(-2\right)-3.3=-9\)
30
\(=sin\left(\dfrac{5\pi}{12}\right).sin\left(2x+\dfrac{\pi}{12}\right)-sin\dfrac{\pi}{12}.cos\left(2x+\dfrac{\pi}{12}\right)\)
\(=cos\left(\dfrac{\pi}{2}-\dfrac{5\pi}{12}\right)sin\left(2x+\dfrac{\pi}{12}\right)-sin\left(\dfrac{\pi}{12}\right)cos\left(2x+\dfrac{\pi}{12}\right)\)
\(=sin\left(2x+\dfrac{\pi}{12}\right)cos\left(\dfrac{\pi}{12}\right)-cos\left(2x+\dfrac{\pi}{12}\right)sin\left(\dfrac{\pi}{12}\right)\)
\(=sin\left(2x+\dfrac{\pi}{12}-\dfrac{\pi}{12}\right)=sin2x\)
\(\Rightarrow\left\{{}\begin{matrix}a=2\\b=0\end{matrix}\right.\) \(\Rightarrow b-2a=-4\)