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tao 1234534
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Đào Thu Hiền
22 tháng 2 2022 lúc 15:54

21. didn’t go

22. isn’t painting

23. aren’t planting

24. Are they making

25. is repairing

26. is taking

27. is explaining

28. is studying

29. tries/ don’t think

30. passes

Valt Aoi
22 tháng 2 2022 lúc 15:55

21. didn’t go

22. isn’t painting

23. aren’t planting

24. Are they making

25. is repairing

26. is taking

27. is explaining

28. is studying

29. tries/ don’t think

30. passes

Phạm Trần Phát
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Hoàng Hạnh Nguyễn
20 tháng 5 2021 lúc 21:04

30B 31B 32D 33D 34C 35B 36B 37C 38B 39A 40D 41D 42A 43D 44D 45A 46C 47B 48C 49B 50C 51C 52B 53D 54B 55C 56A 57C 58A 59D 60B

Khinh Yên
22 tháng 9 2021 lúc 15:34

a d b d b

Givemesome Flan
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Givemesome Flan
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Givemesome Flan
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Givemesome Flan
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Anh chưa thấy ndung câu hỏi em ạ

Nguyễn Việt Lâm
9 tháng 11 2021 lúc 20:16

30.

\(V_{\left(O;\dfrac{3}{4}\right)}\left(M\right)=M_1\Rightarrow\left\{{}\begin{matrix}x_1=\dfrac{3}{4}.4=3\\y_1=\dfrac{3}{4}.1=\dfrac{3}{4}\end{matrix}\right.\)

\(Q_{\left(O;-90^0\right)}\left(M_1\right)=M'\Rightarrow\left\{{}\begin{matrix}x'=y_1=\dfrac{3}{4}\\y'=-x_1=-3\end{matrix}\right.\)

\(\Rightarrow M'\left(\dfrac{3}{4};-3\right)\)

31.

\(cos\dfrac{x}{2}=-\dfrac{\sqrt{3}}{2}\Rightarrow\dfrac{x}{2}=\pm\dfrac{5\pi}{6}+k2\pi\)

\(\Rightarrow x=\pm\dfrac{5\pi}{3}+k4\pi\)

Nghiệm dương nhỏ nhất \(x=\dfrac{5\pi}{3}\Rightarrow a+b=5+3=8\)

Phạm Trúc
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Nguyễn Việt Lâm
11 tháng 5 2021 lúc 22:41

\(\dfrac{x-7}{\left(x+2\right)\left(x-3\right)}>1\Leftrightarrow\dfrac{x-7-\left(x+2\right)\left(x-3\right)}{\left(x+2\right)\left(x-3\right)}>0\)

\(\Leftrightarrow\dfrac{-\left(x-1\right)^2}{\left(x+2\right)\left(x-3\right)}>0\Rightarrow x\in\left(-2;3\right)\backslash\left\{1\right\}\)

\(\Rightarrow2c+a-3b=2.1+\left(-2\right)-3.3=-9\)

30

\(=sin\left(\dfrac{5\pi}{12}\right).sin\left(2x+\dfrac{\pi}{12}\right)-sin\dfrac{\pi}{12}.cos\left(2x+\dfrac{\pi}{12}\right)\)

\(=cos\left(\dfrac{\pi}{2}-\dfrac{5\pi}{12}\right)sin\left(2x+\dfrac{\pi}{12}\right)-sin\left(\dfrac{\pi}{12}\right)cos\left(2x+\dfrac{\pi}{12}\right)\)

\(=sin\left(2x+\dfrac{\pi}{12}\right)cos\left(\dfrac{\pi}{12}\right)-cos\left(2x+\dfrac{\pi}{12}\right)sin\left(\dfrac{\pi}{12}\right)\)

\(=sin\left(2x+\dfrac{\pi}{12}-\dfrac{\pi}{12}\right)=sin2x\)

\(\Rightarrow\left\{{}\begin{matrix}a=2\\b=0\end{matrix}\right.\) \(\Rightarrow b-2a=-4\)