ra đi ra lại không chán hả

\(1,\sqrt{3}x-3=\sqrt{27}\)

\(\Leftrightarrow\sqrt{3}x-3=3\sqrt{3}\)

\(\Leftrightarrow\sqrt{3}\left(x-\sqrt{3}\right)=3\sqrt{3}\)

\(\Leftrightarrow x-\sqrt{3}=3\)

\(\Leftrightarrow x=3+\sqrt{3}\)

\(2,\sqrt{2}x-\sqrt{28}=\sqrt{32}\)

\(\Leftrightarrow\sqrt{2}x-2\sqrt{7}=4\sqrt{2}\)

\(\Leftrightarrow\sqrt{2}x=4\sqrt{2}+2\sqrt{7}\)

\(\Leftrightarrow x=\dfrac{\sqrt{2^2}\left(2\sqrt{2}+\sqrt{7}\right)}{\sqrt{2}}\)

\(\Leftrightarrow x=\sqrt{2}\left(2\sqrt{2}+\sqrt{7}\right)\)

\(\Leftrightarrow x=4+\sqrt{14}\)

\(3,\sqrt{6}x-2\sqrt{6}=\sqrt{54}\)

\(\Leftrightarrow\sqrt{6}\left(x-2\right)=3\sqrt{6}\)

\(\Leftrightarrow x-2=3\)

\(\Leftrightarrow x=5\)

\(4,\sqrt{3}x-\sqrt{2}x=\sqrt{3}+\sqrt{2}\)

\(\Leftrightarrow\left(\sqrt{3}-\sqrt{2}\right)x=\sqrt{3}+\sqrt{2}\)

\(\Leftrightarrow x=\dfrac{\sqrt{3}+\sqrt{2}}{\sqrt{3}-\sqrt{2}}\)

\(2^x+2^{x+4}=544\Leftrightarrow2^x\left(1+2^4\right)=544\)

\(\Leftrightarrow2^x=\frac{544}{17}=32=2^5\Rightarrow x=5\)

~ Học tốt ~

Ta có : 2^x + 2^{x + 4} = 544

=> 2^x(1 + 2⁴) = 544

=> 2^x.17 = 544

=> 2^x = 32

=> 2^x = 2⁵

=> x = 5

Vậy x = 5

\(a,\Leftrightarrow2^x\left(1+2^4\right)=544\\ \Leftrightarrow2^x=\dfrac{544}{17}=32=2^5\\ \Leftrightarrow x=5\\ b,\Leftrightarrow\left(\dfrac{2}{5}-3x\right)^2=\dfrac{9}{25}\Leftrightarrow\left[{}\begin{matrix}\dfrac{2}{5}-3x=\dfrac{3}{5}\\3x-\dfrac{2}{5}=\dfrac{3}{5}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}3x=-\dfrac{1}{5}\\3x=1\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-\dfrac{1}{15}\\x=\dfrac{1}{3}\end{matrix}\right.\)

Sửa lại đề

\(2^x+2^x+4=516\)

\(\Rightarrow2^x+2^x=512\)

\(\Rightarrow2^x+2^x=2^8+2^8\)

\(\Rightarrow x=8\)

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\(2^x+2^{x+4}=544\)

\(2^x\left(1+2^4\right)=544\)

\(2^x.17=544\)

\(2^x=32\)

\(2^x=2^5\)

\(\Rightarrow x=5\)

\(2^x+2^{x+4}=544\)

\(\Rightarrow2^x.1+2^x.2^4=544\)

\(\Rightarrow2^x\left(1+2^4\right)=544\)

\(\Rightarrow2^x.17=544\)

\(\Rightarrow2^x=544\div17\)

\(\Rightarrow2x=32=2^5\)

\(\Rightarrow x=5\)

x = 5 bạn nhé

\(2^x+2^{x+4}=544\\ \Leftrightarrow2^x.\left(1+2^4\right)=544\\ \Leftrightarrow2^x.17=544\\ \Leftrightarrow2^x=\dfrac{544}{17}=32=2^5\\ Vậy:x=5\)

\(...2^x\left(1+16\right)=544\Rightarrow2^x=544:17=32=2^5\)

\(\Rightarrow x=5\)