a.1/5x1/2:3/10
b.1/2x1/3:1/4
1/1x1/2+1/2x1/3+1/3x1/4+1/4x1/5+1/5x1/6
= 1/1x2 + 1/2x3 + 1/3x4 + 1/4x5 + 1/5 x 6
= (1 - 1/2) + (1/2 - 1/3) + (1/3 - 1/4) + (1/4 - 1/5) + (1/5 - 1/6)
= 1 - 1/6
= 5/6
nha,mơn nhìu
\(\frac{1}{1}x\frac{1}{2}+\frac{1}{2}x\frac{1}{3}+\frac{1}{3}x\frac{1}{4}+\frac{1}{4}x\frac{1}{5}+\frac{1}{5}x\frac{1}{6}\)
\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}\)
\(=1-\frac{1}{6}=\frac{5}{6}\)
1/2x1/3+1/3x1/4+1/4x1/5+1/5x1/6+1/6x1/7+1/7x1/8+1/8x1/9
1/2x1/3+1/3x1/4+1/4x1/5+1/5x1/6+1/6x1/7+1/7x1/8+1/8x1/9
=7/18
Bài 1:Tính
a.1/5x1/2:1/3 b.2/9:2/3x1/2
c.1/2x1/3+1/4 c.2/7:2/3-1/7
Giúp mình nhé :)
\(a)\frac{1}{5}\times\frac{1}{2}:\frac{1}{3}=\frac{1}{5}\times\frac{1}{2}\times\frac{3}{1}=\frac{1\times1\times3}{5\times2\times1}=\frac{1\times3}{5\times2}=\frac{3}{10}\)
\(b)\frac{2}{9}:\frac{2}{3}\times\frac{1}{2}=\frac{2}{9}\times\frac{3}{2}\times\frac{1}{2}=\frac{2\times3\times1}{9\times2\times2}=\frac{1\times1\times1}{3\times1\times2}=\frac{1}{6}\)
\(c)\frac{1}{2}\times\frac{1}{3}+\frac{1}{4}=\frac{1}{6}+\frac{1}{4}=\frac{2}{12}+\frac{3}{12}=\frac{2+3}{12}=\frac{5}{12}\)
d, Tương tự như câu c
P/S : Bất phương trình????
\(\frac{1}{5}\times\frac{1}{2}:\frac{1}{3}\)
\(=\frac{1}{10}\times\frac{3}{1}\)
\(=\frac{3}{10}\)
\(\frac{2}{9}:\frac{2}{3}\times\frac{1}{2}\)
\(=\frac{2}{9}\times\frac{3}{2}\times\frac{1}{2}\)
\(=\frac{1}{3}\times\frac{1}{1}\times\frac{1}{2}\)
\(=\frac{1}{3}\times\frac{1}{2}\)
\(=\frac{1}{6}\)
1/8+2x1/8+5x1/8+2x1?8
hãy ghi câu trả lời vào bình luận!
= 1/8 x (1+2+5+2)
=1/8 x 10
= 10/8 = 5/4
Giúp em ạ X1+x2=-4 X1x2=-2m-3 Giải vi-et 2x1³+5x1²x2+5x1x2²+2x2³=-284
=>2[(x1+x2)^3-3x1x2(x1+x2)]+5x1x2(x1+x2)=-284
=>2[(-4)^3-3*(-4)(-2m-3)]+5(-2m-3)*(-4)=-284
=>2[-64+12(-2m-3)]+20(2m-3)=-284
=>-128+24(-2m-3)+40m-60=-284
=>40m-188-48m-72=-284
=>-8m-260=-284
=>8m=24
=>m=3
A=[3/10+4/5x1/2]:[1 và 8/9-1 và 1/3]
Tính giá trị biểu thức
4/5-2/5x1/4 1/4+3/4;1/8
11/10-2/5:1/3
\(\dfrac{4}{5}-\dfrac{2}{5}\times\dfrac{1}{4}=\dfrac{4}{5}-\dfrac{1}{10}=\dfrac{8}{10}-\dfrac{1}{10}=\dfrac{7}{10}\)
\(\dfrac{1}{4}+\dfrac{3}{4}:\dfrac{1}{8}=\dfrac{1}{4}+\dfrac{3}{4}\times8=\dfrac{1}{4}+6=\dfrac{1}{4}+\dfrac{24}{4}=\dfrac{25}{4}\)
\(\)\(\dfrac{11}{10}-\dfrac{2}{5}:\dfrac{1}{3}=\dfrac{11}{10}-\dfrac{2}{5}\times3=\dfrac{11}{10}-\dfrac{6}{5}=\dfrac{11}{10}-\dfrac{12}{10}=-\dfrac{1}{10}\)
4/5-2/5.1/4
=4/5-1/10
=8/10-1/10
=7/10
1/4+3/4:1/8
=1/4+3/4.8
=1/4+6
=1/4+24/4
=25/4
11/10-2/5:1/3
=11/10-2/5.3
=11/10-6/5
=11/10-12/10
=-1/10
\(\dfrac{4}{5}-\dfrac{2}{5}x\dfrac{1}{4}=\dfrac{4}{5}-\dfrac{2}{20}=\dfrac{16}{20}-\dfrac{2}{20}=\dfrac{14}{20}=\dfrac{7}{10}\)
\(\dfrac{1}{4}+\dfrac{3}{4}:\dfrac{1}{8}=\dfrac{1}{4}+\dfrac{3}{4}x\dfrac{8}{1}=\dfrac{25}{4}\)
\(\dfrac{11}{10}-\dfrac{2}{5}:\dfrac{1}{3}=\dfrac{11}{10}-\dfrac{2}{5}x\dfrac{3}{1}=\dfrac{11}{10}-\dfrac{6}{5}=\dfrac{11}{10}-\dfrac{12}{10}=-\dfrac{1}{10}\)
Tìm M:1/2 :(1/3:1/4:1/5x1/120)=2008
\(M=\frac{1}{2}:\left(\frac{1}{3}:\frac{1}{4}:\frac{1}{5}\times\frac{1}{120}\right)=2008\)
\(M=\frac{1}{2}:\left(\frac{1}{3}\times\frac{4}{1}\times\frac{5}{1}\times\frac{1}{120}\right)=2008\)
\(M=\frac{1}{2}:\left(\frac{4}{3}\times\frac{1}{1}\times\frac{1}{24}\right)=2008\)
\(M=\frac{1}{2}:\left(\frac{4}{3}\times\frac{1}{24}\right)=2008\)
\(M=\frac{1}{2}:\left(\frac{1}{3}\times\frac{1}{6}\right)=2008\)
\(M=\frac{1}{2}:\frac{1}{18}=2008\)
\(M=\frac{1}{2}\times\frac{18}{1}=2008\)
\(M=\frac{18}{2}=2008\)
\(M=9=2008\)
a.4/5-(-2/7)-7/10
b,2/3-/(-4/7)-(1/2+3/8)/
4/5 - (-2/7) - 7/10
= 4/5 + 2/7 - 7/10
= 8/10 - 7/10 + 2/7
= 1/10 + 2/7
= 7/70 + 20/70
= 27/70
\(\dfrac{4}{5}-\left(-\dfrac{2}{7}\right)-\dfrac{7}{10}\)
\(=\dfrac{4}{5}+\dfrac{2}{7}-\dfrac{7}{10}\)
\(=\dfrac{8-7}{10}+\dfrac{2}{7}\)
\(=\dfrac{1}{10}+\dfrac{2}{7}\)
\(=\dfrac{7+20}{70}\)
\(=\dfrac{27}{70}\)