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\(1.\) 12 x 11 + 21 x 11 x 11 + 11 x 33

= ( 12 x 11 ) + ( 21 x 11 x 11 ) + ( 11 x 33 )

= \(132+2541+363\)

= \(3036\)

132x11-11x32-54x11

= ( 132 x 11 ) - ( 11 x 32 ) - ( 54 x 11 )

\(=1452-352-594\)

= \(506\)

\(2.\)

45 x 32 + 1245

= ( 45 x 32 ) + 1245

= 1400 + 1245

= 2685

75 x 18 + 75 x 21

= ( 75 x 18 ) + ( 75 x 21 )

= 1350 + 1575

= 2925

12 x (27+46) -1567

= 12 x 73 - 1567

= ( 12 x 73 ) - 1567

= 876 - 1567

= - 691

d: \(D=x^3-6x^2+12x-100\)

\(=x^3-6x^2+12x-8-92\)

\(=\left(x-2\right)^3-92\)

Khi x=-98 thì \(D=\left(-98-2\right)^3-92=-1000000-92=-1000092\)

e: \(E=\left(x+1\right)^3+6\left(x+1\right)^2+12x+20\)

\(=\left(x+1\right)^3+6\left(x+1\right)^2+12\left(x+1\right)+8\)

\(=\left(x+1+2\right)^3\)

\(=\left(x+3\right)^3\)

Khi x=5 thì \(E=\left(5+3\right)^3=8^3=512\)

f: \(F=\left(2x-1\right)\left(4x^2+2x+1\right)-7\left(x^3+1\right)\)

\(=\left(2x\right)^3-1^3-7x^3-7\)

\(=x^3-8\)

Khi x=-1/2 thì \(F=\left(-\dfrac{1}{2}\right)^3-8=-\dfrac{1}{8}-8=-\dfrac{65}{8}\)

g: \(G=\left(-x-2\right)^3+\left(2x-4\right)\left(x^2+2x+4\right)-x^2\left(x-6\right)\)

\(=-\left(x+2\right)^3+2\left(x-2\right)\left(x^2+2x+4\right)-x^3+6x^2\)

\(=-x^3-6x^2-12x-8+2\left(x^3-8\right)-x^3+6x^2\)

\(=-2x^3-12x-8+2x^3-16=-12x-24\)

Khi x=-2 thì \(G=-12\cdot\left(-2\right)-24=24-24=0\)

h: \(H=\left(x-1\right)^3-\left(x+2\right)\left(x^2-2x+4\right)+3\left(x+4\right)\left(x-4\right)\)

\(=x^3-3x^2+3x-1-\left(x^3+8\right)+3\left(x^2-16\right)\)

\(=x^3-3x^2+3x-1-x^3-8+3x^2-48\)

\(=3x-57\)

Khi x=-1/2 thì \(H=3\cdot\dfrac{-1}{2}-57=-1,5-57=-58,5\)

A = 2 : x

Thay x = 0 vào biểu thức, ta được:

A = 2 : 0

A = 0

2xy : 2y

= ( 2y : 2y ) . ( x : 1 )

= x

a. = 12 + -12 + [-24]

=0+[-24]

=-24

b. = 23 + -23 + 23

=0+23

=23

cho mik nhé 

hok tốt

hihi

`A = |6 : 3/5 - 1 1/6 . 6/7| : |4 1/5 . 10/11 + 5 2/11|`

`=|10 - 1| : |42/11 + 57/11|`

`=9 : 9`

`=1`

=| 6 . 5/3 - 7/6 . 6/7 | : | 21/5 . 10/11 + 57/11 |
=| 10 - 1 | : | 42/11 + 57/11 |
= 9 : |99/11|
= 9 : 9
=1

P = (\(\dfrac{13}{84}\) x 1\(\dfrac{2}{5}\) - 2\(\dfrac{1}{2}\) x \(\dfrac{7}{180}\)) : 2\(\dfrac{7}{18}\) + 4\(\dfrac{1}{2}\) x \(\dfrac{1}{10}\)

P = (\(\dfrac{13}{84}\) x \(\dfrac{7}{5}\) - \(\dfrac{5}{2}\) x \(\dfrac{7}{180}\)):\(\dfrac{43}{18}\) + \(\dfrac{9}{2}\) x \(\dfrac{1}{10}\)

P = (\(\dfrac{13}{60}\) - \(\dfrac{7}{72}\)): \(\dfrac{43}{18}\) + \(\dfrac{9}{20}\)

P = \(\dfrac{43}{360}\) x \(\dfrac{18}{43}\) + \(\dfrac{9}{20}\)

P = \(\dfrac{1}{20}\) + \(\dfrac{9}{20}\)

P = \(\dfrac{10}{20}\)

P = \(\dfrac{1}{2}\)

\(\dfrac{6}{7}-\dfrac{7}{15}:\dfrac{14}{5}\)
\(=\dfrac{6}{7}-\dfrac{7}{15}\cdot\dfrac{5}{14}\)
\(=\dfrac{6}{7}-\dfrac{1}{6}\)
\(=\dfrac{36}{42}-\dfrac{7}{42}\)
\(=\dfrac{29}{42}\)

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