\(\frac{16,2\cdot3,7+5,7\cdot16,2+7,8+4,8+4,6\cdot7,8}{11,2+12,3+13,4-12,6-11,5-10,4}\)\(=\frac{16,2\cdot(3,7+5,7)-7,8\cdot(4,8+4,6)}{(13,4-12,6)+(12,3-11,5)+(11,2-10,4)}\)

                                                                                     \(=\frac{16,2\cdot9,4-7,8\cdot9,4}{0,8+0,8+0,8}=32,9\)

~Chúc bạn học tốt

Mk ko chắc nữa

ta tach phep tinh do ra lam ahi ve .

ve A la phep tinh 16,2 * 3,7 +5,7 * 16,2 

ve B la phep tinh con lai

ve A = 16,2 *9( 3,7 + 5,7 ) = ........

ve B = 7,8 * (4, 8+ 4,6 )=.......

cuoi cung bang ve A + ve B la ra

cảm ơn bạn nhiều

=(126,73^2-1+20,7)*(126-12,6*8-12,6*2)

=0

\(\left(126,74\times126,72+18,63:0,9\right)\times\left(126-12,6:0,125-12,6\times2\right)\)

\(=\left(126,74\times126,72+18,63:0,9\right)\times\left[126-\left(12,6:0,125+12,6\times2\right)\right]\)

\(=\left(126,74\times126,72+18,63:0,9\right)\times\left[126-\left(12,6\times8+12,6\times2\right)\right]\)

\(=\left(126,74\times126,72+18,63:0,9\right)\times\left\{126-\left[12,6\times\left(8+2\right)\right]\right\}\)

\(=\left(126,74\times126,72+18,63:0,9\right)\times\left[126-(12,6\times10)\right]\)

\(=\left(126,74\times126,72+18,63:0,9\right)\times\left(126-126\right)\)

\(=\left(126,74\times126,72+18,63:0,9\right)\times0\)

\(=0\)

$\left(126,74\times 126,72+18,63:0,9\right)\times \left(126-12,6:0,125-12,6\times 2\right)$

$=\left(126,74\times 126,72+18,63:0,9\right)\times \left[126-\left(12,6:0,125+12,6\times 2\right)\right]$

$=\left(126,74\times 126,72+18,63:0,9\right)\times \left[126-\left(12,6\times 8+12,6\times 2\right)\right]$

$=\left(126,74\times 126,72+18,63:0,9\right)\times \left\{126-\left[12,6\times \left(8+2\right)\right]\right\}$

$=\left(126,74\times 126,72+18,63:0,9\right)\times \left[126-(12,6\times 10)\right]$

$=\left(126,74\times 126,72+18,63:0,9\right)\times \left(126-126\right)$

$=\left(126,74\times 126,72+18,63:0,9\right)\times 0$

$=0$

a: \(\Leftrightarrow\left[{}\begin{matrix}x-\dfrac{3}{4}=\dfrac{1}{5}\\x-\dfrac{3}{4}=-\dfrac{1}{5}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{19}{20}\\x=\dfrac{11}{20}\end{matrix}\right.\)

\(a,\left|x-\dfrac{3}{4}\right|=\dfrac{1}{5}\)

\(\Leftrightarrow\left[{}\begin{matrix}x-\dfrac{3}{4}=\dfrac{1}{5}\\x-\dfrac{3}{4}=\dfrac{-1}{5}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{19}{20}\\x=\dfrac{11}{20}\end{matrix}\right.\)

\(b,\dfrac{-1}{3}+\left|x\right|=0,5\)

\(\Leftrightarrow\left|x\right|=\dfrac{5}{6}\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{5}{6}\\x=\dfrac{-5}{6}\end{matrix}\right.\)

#\(N\)

\(x+7,78=11,34\)

\(x=11,34-7,78\)

\(x=3,56\)

`x+ 7,78 = 12,6 xx 0,9`

`=> x+ 7,78 = 11,34`

`=>x=11,34-7,78`

`=>x=3,56`

giúp mình đi mọi người T.T

a) x = 6/5 - 5/6

    x =  11/30

vậy x =...

b) x = 13/4 - 3/5 

    x = 53/20

vậy x =...

a. x=6/5-5/6=11/30

b.13/4-3/5=53/20

<=> 11 - 15 - x = x - 25 + 9

<=>   -x - x       = - 25 + 9 - 11 + 15

<=> - 2x           = -12

<=>    x            = -12 : (- 2)

<=>    x            = 6

Tìm số nguyên x biết:

\(11-\left(15+x\right)=x-\left(25-9\right)\)

\(11-\left(15+x\right)=x-16\)

      \(11-15-x=x-16\)

                 \(-x-x=-16-11+15\)

                       \(-2x=-16-11+15\)

                      \(-2x=-27+15\)

                      \(-2x=-12\)

                         \(-x=-12:2\)

                          \(-x=-6\)

\(=>x=6\)

Vậy \(x=6\)

là bài nào vậy

\(2,4:0,125+2,4:0,25-2,4:0,5\)

\(=2,4\cdot8+2,4\cdot4-2,4\cdot2\)

\(=2,4\left(8+4-2\right)\)

\(=2,4\cdot10=24\)