1 4/23+5/11-4/23+6/11+0,5
1và 4/23(hỗn sô) + 5/11 - 4/23 + 6/11 + 0,5
\(1\dfrac{4}{23}+\dfrac{5}{11}-\dfrac{4}{23}+\dfrac{6}{11}+0,5=\dfrac{27}{23}+\dfrac{5}{11}-\dfrac{4}{23}+\dfrac{6}{11}+0,5\)
\(=\left(\dfrac{27}{23}-\dfrac{4}{23}\right)+\left(\dfrac{5}{11}+\dfrac{6}{11}\right)+0,5=\dfrac{23}{23}+\dfrac{11}{11}+0,5\)
\(=1+1+0,5=2,5\)
Hỗn số 1và 4/23 + 5/11- 4/23+ 6/11+ 0,5
\(1\dfrac{4}{23}+\dfrac{5}{11}-\dfrac{4}{23}+\dfrac{6}{11}+0,5\)
\(=\left(1\dfrac{4}{23}-\dfrac{4}{23}\right)+\left(\dfrac{5}{11}+\dfrac{6}{11}\right)+0,5\)
\(=1+1+0,5=2+0,5=2,5\)
1.\(\left(\frac{-6}{5}+\frac{6}{16}-\frac{6}{23}\right):\left(\frac{9}{5}-\frac{9}{19}+\frac{9}{23}\right)\)
2.\(\frac{\frac{3}{7}-\frac{3}{-11}+\frac{3}{13}}{\frac{5}{7}-\frac{5}{11}+\frac{5}{13}}+\frac{0,5-\frac{1}{3}+\frac{1}{4}}{\frac{-3}{2}+1-\frac{3}{4}}\)
1.\(\left(-\frac{6}{5}+\frac{6}{16}-\frac{6}{23}\right):\left(\frac{9}{5}-\frac{9}{16}+\frac{9}{23}\right)\)
\(=6\left(-\frac{1}{5}+\frac{1}{16}-\frac{1}{23}\right):\left(-9\right)\left(\frac{-1}{5}+\frac{1}{16}-\frac{1}{23}\right)\)
\(=6:\left(-9\right)=-\frac{2}{3}\)
2. \(\frac{\frac{3}{7}-\frac{3}{11}+\frac{3}{13}}{\frac{5}{7}-\frac{5}{11}+\frac{5}{13}}+\frac{0.5-\frac{1}{3}+\frac{1}{4}}{-\frac{3}{2}+1-\frac{3}{4}}\)
\(=\frac{3\left(\frac{1}{7}-\frac{1}{11}+\frac{1}{13}\right)}{5\left(\frac{1}{7}-\frac{1}{11}+\frac{1}{13}\right)}+\frac{\frac{1}{2}-\frac{1}{3}+\frac{1}{4}}{-3\left(\frac{1}{2}-\frac{1}{3}+\frac{1}{4}\right)}\)
\(=\frac{3}{5}-\frac{1}{3}\)
\(=\frac{9}{13}-\frac{5}{15}=\frac{4}{15}\)
Bài 1: Thực hiện phép tính:
1, 4/23 + 5/21 + 0,5 - 4/23 + 16/21
2, (1/3 + 12/67 + 13/41)-(79/67 - 28/41)
3, 12,5 x (-5/7)+1,5 x (-5/7)
4, 3/8x19 1/3- 3/8x33 1/3
5, 5/7x(-3/11)+5/7x(-8/11)+2 5/7
6, (-5/11:13/8-5/11:13/5)- giá trị tuyệt đối của -1/33
1: \(\dfrac{4}{23}+\dfrac{5}{21}+\dfrac{1}{2}-\dfrac{4}{23}+\dfrac{16}{21}\)
\(=1+\dfrac{1}{2}\)
\(=\dfrac{3}{2}\)
2: \(\left(\dfrac{1}{3}+\dfrac{12}{67}+\dfrac{13}{41}\right)-\left(\dfrac{79}{67}-\dfrac{28}{41}\right)\)
\(=\dfrac{1}{3}+\dfrac{12}{67}+\dfrac{13}{41}-\dfrac{79}{67}+\dfrac{28}{41}\)
\(=\dfrac{1}{3}\)
a)25%-5/4+11/6
b)75%:11/5-(0,5)².(-7)+2,5(23/3-17/3
c)45:18/7+50% -1,25
Giải:
a) \(25\%-\dfrac{5}{4}+\dfrac{11}{6}\)
\(=\dfrac{1}{4}-\dfrac{5}{4}+\dfrac{11}{6}\)
\(=-1+\dfrac{11}{6}\)
\(=\dfrac{5}{6}\)
Vậy ...
b) \(75\%:\dfrac{11}{5}-\left(0,5\right)^2.\left(-7\right)+2,5\left(\dfrac{23}{3}-\dfrac{17}{3}\right)\)
\(=\dfrac{3}{4}:\dfrac{11}{5}-\dfrac{1}{4}.\left(-7\right)+2,5.2\)
\(=\dfrac{15}{44} +\dfrac{7}{4}+5\)
\(=\dfrac{23}{11}+5\)
\(=\dfrac{78}{11}\)
Vậy ...
c) \(45:\dfrac{18}{7}+50\%-1,25\)
\(=45:\dfrac{18}{7}+\dfrac{1}{2}-\dfrac{5}{4}\)
\(=\dfrac{35}{2}+\dfrac{1}{2}-\dfrac{5}{4}\)
\(=18-\dfrac{5}{4}\)
\(=\dfrac{67}{4}\)
Vậy ...
(2/3x4/5)x5/6
(4/5+5/4)x3/4
11/23+2/23+9/23+18/23
27/12+17/6-25/36-15/6
thuận tiện nhất
\(a.=\left(\dfrac{4}{5}.\dfrac{5}{6}\right).\dfrac{2}{3}=\dfrac{4}{6}.\dfrac{2}{3}=\dfrac{4}{9}\)
\(b.\dfrac{4}{5}.\dfrac{3}{4}+\dfrac{5}{4}.\dfrac{3}{4}=\dfrac{3}{5}+\dfrac{15}{16}=\dfrac{123}{80}\)
\(c.\left(\dfrac{11}{23}+\dfrac{9}{23}\right)+\left(\dfrac{2}{23}+\dfrac{18}{23}\right)=\dfrac{20}{23}+\dfrac{20}{23}=\dfrac{40}{23}\)
\(d.\left(\dfrac{27}{12}-\dfrac{25}{36}\right)+\left(\dfrac{17}{6}-\dfrac{15}{6}\right)=\dfrac{14}{9}+\dfrac{1}{3}=\dfrac{17}{9}\)
Tính
a) 4/3*7 + 4/7*11 + 4/11*15 + 4/15*19 + 4/19*23 + 4/23*27
b) 1/2*3 + 1/3*4 + 1/4*5 + 1/5*6 +1/6*7
c) 2/3*5 + 2/5*7 + 2/7*9 + 2/9*11 + 2/11*13 + 2/1*2 + 2/2*3 + 2/3*4 + 2/8*9 + 2/9*10
a)\(\frac{4}{3.7}+\frac{4}{7.11}+...+\frac{4}{23.27}=\frac{1}{3}-\frac{1}{7}+\frac{1}{7}-\frac{1}{11}+...+\frac{1}{23}-\frac{1}{27}=\frac{1}{3}-\frac{1}{27}=\frac{8}{27}\)
b)\(\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{6.7}=\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{6}-\frac{1}{7}=\frac{1}{2}-\frac{1}{7}=\frac{5}{14}\)
c)\(\frac{2}{3.5}+\frac{2}{5.7}+...+\frac{2}{11.13}+\frac{2}{1.2}+\frac{2}{2.3}+...+\frac{2}{9.10}=\left(\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+...+\frac{1}{11}-\frac{1}{13}\right)+2\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{9}-\frac{1}{10}\right)\)
\(=\frac{1}{3}-\frac{1}{13}+2\left(1-\frac{1}{10}\right)=\frac{10}{39}+\frac{9}{5}=\frac{401}{195}\)
a)1/2- -1/3+1/23+1/6
b)11/24-5/41+13/24+0,5-36/41
c)-1/12-(1/6-1/4)
d)1/6-mở ngoặc vuông1/6-(1/4+9/12)đóng ngoặc vuông
e)0,5+1/3+0,4+5/7+1/6-4/35
GIÚP MÌNH VỚI Ạ. MÌNH CẦN GẤP. CẢM ƠN MỌI NGƯỜI!
cô THƯƠNG HOÀI GIÚP EM VỚI Ạ
a, \(\dfrac{1}{2}\) - ( - \(\dfrac{1}{3}\) ) + \(\dfrac{1}{23}\) + \(\dfrac{1}{6}\)
= \(\dfrac{5}{6}\) + \(\dfrac{1}{23}\) + \(\dfrac{1}{6}\)
= 1 + \(\dfrac{1}{23}\)
= \(\dfrac{24}{23}\)
b, \(\dfrac{11}{24}\) - \(\dfrac{5}{41}\) + \(\dfrac{13}{24}\) + 0,5 - \(\dfrac{36}{41}\)
= (\(\dfrac{11}{24}\) + \(\dfrac{13}{24}\)) - ( \(\dfrac{5}{41}\) + \(\dfrac{36}{41}\)) + 0,5
= 1 - 1 + 0,5
= 0,5
c,\(-\dfrac{1}{12}-\left(\dfrac{1}{6}-\dfrac{1}{4}\right)\)
=\(-\dfrac{1}{12}-\left(-\dfrac{1}{12}\right)\)
=0
d, \(\dfrac{1}{6}-\left[\dfrac{1}{6}-\left(\dfrac{1}{4}+\dfrac{9}{12}\right)\right]\)
= \(\dfrac{1}{6}-\left[\dfrac{1}{6}-1\right]\)
= \(\dfrac{1}{6}-\left(-\dfrac{5}{6}\right)\)
= 1
e, 0,5 + \(\dfrac{1}{3}\) + 0,4 + \(\dfrac{5}{7}\) + \(\dfrac{1}{6}\) - \(\dfrac{4}{35}\)
= (0,5 + 0,4) + ( \(\dfrac{1}{3}\) + \(\dfrac{1}{6}\)) + (\(\dfrac{5}{7}\) - \(\dfrac{4}{35}\))
= 0,9 + \(\dfrac{1}{2}\) + \(\dfrac{3}{5}\)
= 0,9 + 0,5 + 0,6
= 2
1> Tính
a) 3/11 + 5/-9 + 4/11 - 4/9 + 3/17 + 15/11
b) M = -3 * 4 - 6 * 8 - 9 * 12 - 12 * 16 - 16 * 20 / -1 * 2 - 2 * 4 - 3 * 6 - 4 * 8 - 6 * 10
c) N = 5/7 - 5/9 - 5/11 / 15/7 + 15/9 + 15/11
d) 4 + 4/73 * 1/23 / 5 + 5/73 * 1/23
nhanh lên nha mk đang cần gấp
thanks nha