a) \(\dfrac{4}{11}+\dfrac{5}{22}=\dfrac{8}{22}+\dfrac{5}{22}=\dfrac{13}{22}\)

b) \(3-\dfrac{3}{8}=\dfrac{3}{1}-\dfrac{3}{8}=\dfrac{24}{8}-\dfrac{3}{8}=\dfrac{21}{8}\)

c) \(\dfrac{9}{25}\times5=\dfrac{45}{25}=\dfrac{9}{5}\)

d) \(\dfrac{3}{7}\div4=\dfrac{3}{28}\)

a)

= 8/22 + 5/22

= 11/22

= 1/2

b)

= 24/8 - 3/8

= 21/8

c)

= 45/25

= 9/5

d)

= 3/7 x 1/4

= 3/28

:)

Answer:

Bài 1: 

\(\left(135-35\right).\left(-37\right)+37.\left(-42-58\right)\)

\(=100.\left(-37\right)+37.\left(-100\right)\)

\(=\left(-3700\right)+\left(-3700\right)\)

\(=-7400\)

\(-65.\left(87-17\right)-87.\left(17-65\right)\)

\(=\left(-65\right).87-\left(-65\right).17-87.17+87.65\)

\(=-\left(-65\right).17-87.17\)

\(=17.\left(65-87\right)\)

\(=-374\)

\([3.\left(-2\right)-\left(-8\right)].\left(-7\right)-\left(-2\right).\left(-5\right)\)

\(=[\left(-6\right)+8].\left(-7\right)-\left(-2\right).\left(-5\right)\)

\(=2.\left(-7\right)-10\)

\(=-24\)

Bài 2:

\(\left(-55\right).\left(-25\right).\left(-8\right)\)

\(=\left(-55\right).[\left(-25\right).\left(-8\right)]\)

\(=\left(-55\right).200\)

\(=-11000\)

\(\left(-1\right).\left(-2\right).\left(-3\right).\left(-4\right).\left(-5\right).10\)

\(=[\left(-1\right).10].[\left(-2\right).\left(-5\right)].[\left(-3\right).\left(-4\right)]\)

\(=\left(-10\right).10.12\)

\(=-1200\)

Bài 1: Thực hiện các phép tính sau:

\(a)\)Chưa rỏ đề

\(b)\)\(5025\div5-25\div5\)

\(=\)\(1005-5\)

\(=\)\(1000\)

\(c)\)\(218-180\div2\div9\)

\(=\)\(218-10\)

\(=\)\(208\)

\(d)\)\(\left(328-8\right)\div32\)

\(=\)\(320\div32\)

\(=\)\(10\)

Bài 1:

a) ( Tôi không nhìn rõ đầu bài )

b) 5025  :  5  -  25  :  5

=  ( 5025  -  25 )  :  5

=        5000   :   5

=       1000

c)   218  -  180  :  2  :  9

=     218   -    180  :  (  2  .  9 )

=      218    -    180   :  18

=       218    -    10

=       208

d)   (  328  -  8  )  :  32

=      320   :   32

=     10 

Bài 2: Thực hiện phép tính:

\(a)\)\(27.75+25.27-150\)

\(=\)\(27.\left(75+25\right)-150\)

\(=\)\(27.100-150\)

\(=\)\(2700-150\)

\(=\)\(2550\)

\(b)\)\(12\div\left\{400\div\left[500-\left(125+25.7\right)\right]\right\}\)

\(=\)\(12\div\left\{400\div\left[500-\left(125+175\right)\right]\right\}\)

\(=\)\(12\div\left\{400\div\left[500-300\right]\right\}\)

\(=\)\(12\div\left\{400\div200\right\}\)

\(=\)\(12\div2\)

\(=\)\(6\)

\(c)\)\(13.17-256\div16+14\div7-1\)

\(=\)\(221-16+2-1\)

\(=\)\(206\)

\(d)\)\(18\div3+182+3.\left(51\div17\right)\)

\(=\)\(6+182+3.3\)

\(=\)\(6+182+9\)

\(=\)\(197\)

a) \(x+\frac{4}{5}=\frac{3}{2}\)

\(\Rightarrow x=\frac{3}{2}-\frac{4}{5}\)

\(\Rightarrow x=\frac{7}{10}\)

Vậy \(x=\frac{7}{10}.\)

b) \(x-\frac{3}{2}=\frac{11}{4}\)

\(\Rightarrow x=\frac{11}{4}+\frac{3}{2}\)

\(\Rightarrow x=\frac{17}{4}\)

Vậy \(x=\frac{17}{4}.\)

c) \(\frac{25}{3-x}=\frac{5}{6}\)

\(\Rightarrow\left(3-x\right)5=25.6\)

\(\Rightarrow15-5x=150\)

\(\Rightarrow5x=15-150\)

\(\Rightarrow5x=-135\)

\(\Rightarrow x=-135:5\)

\(\Rightarrow x=-27\)

Vậy \(x=-27.\)

ai giúp mình câu c đi

`@` `\text {Ans}`

`\downarrow`

`1,`

`a)`

`-7/25 + (-8)/25`

`= (-7 - 8)/25`

`= -15/25`

`= -3/5`

`b)`

`6/13 + (-15)/39`

`= 18/39 + (-15)/39`

`= (18 - 15)/39`

`= 3/39`

`= 1/13`

`c)`

`5/7 + 4/(-14)`

`= 10/14 + (-4)/14`

`= (10 - 4)/14`

`= 6/14`

`= 3/7`

`d)`

`-8/18 + (-15)/27`

`= -4/9 + (-5)/9`

`= (-4-5)/9`

`= -9/9 = -1`

`2,`

`a)`

`3/5 + (-7)/4`

`= 12/20 + (-35)/20`

`= (12 - 35)/20`

`=-23/20`

`b)`

`(-2) + (-5)/8`

`= (-16)/8 + (-5)/8`

`= (-16 - 5)/8`

`= -21/8`

`c)`

`1/8 + (-5)/9`

`= 9/72 + (-40)/72`

`= (9-40)/72`

`= -31/72`

`d)`

`6/13 + (-14)/39`

`= 18/39 + (-14)/39`

`= (18 - 14)/39`

`= 4/39`

`e)`

`(-18)/24 + 15/21`

`= (-3)/4 + 5/7`

`= (-21)/28 + 20/28`

`= (-21 + 20)/28`

`= -1/28`

\(\frac{17}{33}.\frac{2}{5}+\frac{3}{5}.\frac{17}{33}-\frac{17}{33}\)

\(=\frac{17}{33}\times\frac{2}{5}+\frac{3}{5}\times\frac{17}{33}-\frac{17}{33}\times1\)

\(=\frac{17}{33}\times\left(\frac{2}{5}+\frac{3}{5}-1\right)\)

\(=\frac{17}{33}\times\left(1-1\right)\)

\(=\frac{17}{33}\times0=\frac{17}{33}\)

 Làm he LÀM đi bạ nó lại  cồn bỏ bỏ

2/3+5/4=8/12+15/12=23/12

15/25+6/21=31/35

35/11-2=13/11

68/17-3=1

a) \(\frac{2}{3}+\frac{5}{4}=\frac{8}{12}+\frac{15}{12}\)

                   \(=\frac{8+15}{12}=\frac{23}{12}\)

b) \(\frac{15}{25}+\frac{6}{21}=\frac{3}{5}+\frac{2}{7}\)

                          \(=\frac{21}{35}+\frac{10}{35}=\frac{31}{35}\)

c) \(\frac{35}{11}-2=\frac{35}{11}-\frac{22}{11}\)

                      \(=\frac{13}{11}\)

d) \(\frac{68}{17}-3=\frac{68}{17}-\frac{51}{17}\)

                    \(=1\)

2/3+5/4=23/12

15/25+6/21=31/35

35/11-2=13/11

68/17-3=1

Bài 1: 

Ta có: \(x-35\%\cdot x=\dfrac{1}{25}\)

\(\Leftrightarrow65\%\cdot x=\dfrac{1}{25}\)

\(\Leftrightarrow x=\dfrac{1}{25}:\dfrac{13}{20}=\dfrac{1}{25}\cdot\dfrac{20}{13}=\dfrac{4}{65}\)

Vậy: \(x=\dfrac{4}{65}\)

Bài 2: 

a) Ta có: \(17\dfrac{2}{31}-\left(\dfrac{15}{17}+6\dfrac{2}{31}\right)\)

\(=17\dfrac{2}{31}-\dfrac{15}{17}-6\dfrac{2}{31}\)

\(=11+\dfrac{2}{31}-\dfrac{15}{17}\)

\(=\dfrac{5366}{527}\)