\(0,25.2\frac{1}{3}.30.0,5.\frac{8}{45}\)

\(=\frac{1}{4}.\frac{7}{3}.30.\frac{1}{2}.\frac{8}{45}\)

\(=\frac{14}{9}\)

\(0,25.2\frac{1}{3}.30.0,5.\frac{8}{45}\)

\(=0,25.\frac{7}{3}.30.0,5.\frac{8}{45}\)

\(=\frac{7}{12}.30.\frac{4}{45}\)

\(\frac{35}{2}.\frac{4}{45}\)

\(=\frac{14}{9}\)

`25%+3/4+1/2:0,5-1/4:0,15+1/8:0,125`

`=1/4+3/4+1/2xx2-1/4xx4+1/8xx8`

`(1/4+3/4)+(1/2xx2)-(1/4xx4)+(1/8xx8)`

`=1+1-1+1`

`=2`

Bài làm:

\(2\left(x-0,5\right)+3=0,25\left(4x-1\right)\)

\(\Leftrightarrow2x-1+3=x-0,25\)

\(\Leftrightarrow2x-x=1-3-0,25\)

\(\Leftrightarrow x=-2,25\)

Vậy phương trình có tập nghiệm là \(S=\left\{-2,25\right\}\)

b) Ta có: \(3+\left(x-5\right)=2\left(3x-2\right)\)

\(\Leftrightarrow3+x-5=6x-4\)

\(\Leftrightarrow x-2-6x+4=0\)

\(\Leftrightarrow-5x+2=0\)

\(\Leftrightarrow-5x=-2\)

\(\Leftrightarrow x=\dfrac{2}{5}\)

Vậy: \(S=\left\{\dfrac{2}{5}\right\}\)

c) Ta có: \(2\left(x-0.5\right)+3=0.25\left(4x-1\right)\)

\(\Leftrightarrow2x-1+3=x-\dfrac{1}{4}\)

\(\Leftrightarrow2x+2-x+\dfrac{1}{4}=0\)

\(\Leftrightarrow x+\dfrac{9}{4}=0\)

\(\Leftrightarrow x=-\dfrac{9}{4}\)

Vậy: \(S=\left\{-\dfrac{9}{4}\right\}\)

d) Ta có: \(2\left(x-\dfrac{1}{4}\right)-4=-6\left(-\dfrac{1}{3}x+0.5\right)+2\)

\(\Leftrightarrow2x-\dfrac{1}{2}-4=2x-3+2\)

\(\Leftrightarrow2x-\dfrac{9}{2}=2x-1\)

\(\Leftrightarrow2x-2x=-1+\dfrac{9}{2}\)

\(\Leftrightarrow0x=\dfrac{7}{2}\)(vô lý)

Vậy: \(S=\varnothing\)

b. 

→ -2 + x = 6x - 4

→ -2 + 4 = 6x - x

→ 2 = 5x

→ x = \(\dfrac{2}{5}\) 

Vậy, phương trình có tập nghiệm S = {\(\dfrac{2}{5}\)}

khó quá

Nobita Kun

cho No 1 k nhé

chúc học tốt nhé

x = 13,6