\(P=\dfrac{2^{20}\cdot3^{10}+2^9\cdot2^{12}\cdot3^9}{15\cdot2^{18}\cdot3^8-2^{19}\cdot3^9}=\dfrac{2^{20}\cdot3^9\left(3+2\right)}{2^{18}\cdot3^9\cdot5-2^{19}\cdot3^9}\)

\(=\dfrac{2^{20}\cdot3^9\cdot5}{2^{18}\cdot3^9\left(5-2\right)}=4\cdot\dfrac{5}{3}=\dfrac{20}{3}\)

\(A=\dfrac{2^{20}\cdot3^{10}+2^9\cdot2^{12}\cdot3^9}{2^{18}\cdot5\cdot3\cdot3^8-2^{19}\cdot3^9}\)

\(=\dfrac{2^{20}\cdot3^9\left(3+2\right)}{2^{18}\cdot3^9\left(5-2\right)}=4\cdot\dfrac{5}{3}=\dfrac{20}{3}\)

là 1 nha bạn

\(\dfrac{2^{20}.27^3+30.4^9.9^4}{6^9.4^5+12^{10}}=\dfrac{2^{20}.3^9+3.2.5.2^{18}.3^8}{2^9.3^9+2^{10}+2^{20}.3^{10}}\)

\(=\dfrac{2^{19}.3^9.\left(2+5\right)}{2^9.3^9.\left(1+2^{11}.3\right)+2^{10}}=\dfrac{2^{10}.\left(2+5\right)}{1+2^{10}.\left(2.3+1\right)}\)

\(=\dfrac{2^{10}.7}{2^{10}.7+1}=\dfrac{7168}{7169}\)

Chúc bạn học tốt!!!

\(\dfrac{2^{20}.27^3+30.4^9.9^4}{6^9.4^5+12^{10}}=\dfrac{2^{20}.3^9+2.3.5.2^{18}.3^8}{2^9.3^9+2^{20}.3^{10}}=\dfrac{2^{20}.3^9+5.2^{19}.3^9}{2^9.3^9+2^{20}.3^{10}}=\dfrac{2^9.3^9\left(2^{11}+5.2^{10}\right)}{2^9.3^9\left(1+2^{11}.3\right)}\)

\(\dfrac{2^{11}+5.2^{10}}{1+2^{11}.3}\)

tới bc này chiu :))

\(=\frac{2^{19}3^9+3\cdot5\cdot2^{18}\cdot3^8}{2^9\cdot3^9\cdot2^{10}+4^{10}\cdot3^{10}}=\frac{2^{19}\cdot3^9+5\cdot2^{18}\cdot3^9}{2^{19}\cdot3^9+2^{20}\cdot3^{10}}=\frac{2^{18}\cdot3^9\cdot\left(2+5\right)}{2^{19}\cdot3^9\left(1+6\right)}=\frac{1}{2}\)

\(A=\frac{2^{19}.27^3+15.4^9.9^4}{6^9.2^{10}+12^{10}}\)

\(A=\frac{2^{19}.\left(3^3\right)^3+3.5.\left(2^2\right)^9.\left(3^2\right)^4}{\left(2.3\right)^9.2^{10}+\left(2^2.3\right)^{10}}\)

\(A=\frac{2^{19}.3^9+3.5.2^{18}.3^8}{2^9.3^9.2^{10}+2^{20}.3^{10}}\)

\(A=\frac{2^{19}.3^9+5.2^{18}.3^9}{2^{19}.3^9+2^{20}.3^{10}}\)

\(A=\frac{2^{18}.3^9.\left(2+5\right)}{2^{18}.3^9.\left(2+2^2.3\right)}\)

\(A=1.\frac{2+5}{2+4.3}\)

\(A=\frac{7}{14}=\frac{1}{2}\)

Vậy \(A=\frac{1}{2}\)

\(\frac{2^{19}.27^3+15.4^9.9^4}{6^9.2^{10}+12^{10}}=\frac{2^{19}.3^9+3.5.2^{18}.3^8}{2^9.3^9.2^{10}+3^{10}.2^{20}}=\frac{2^{18}.3^9\left(2+5\right)}{2^{18}.3^9\left(2+3.2^2\right)}=\frac{7}{14}=\frac{1}{2}\)

Ta có:

\(\frac{2^{19}.27^9+15.4^9.9^4}{6^9.2^{12}+12^{10}}=\frac{2^{19}.\left(3^3\right)^9+3.5.\left(2^2\right)^9.\left(3^2\right)^4}{\left(2.3\right)^9.2^{12}+\left(2^2.3\right)^{10}}\)

\(=\frac{2^{19}.3^{27}+3.5.2^{18}.3^8}{2^9.3^9.2^{12}+2^{20}.3^{10}}=\frac{2^{19}.3^{27}+3^9.2^{18}.5}{2^{21}.3^9+2^{20}.3^{10}}=\frac{2^{18}.3^9.\left(2.3^{18}+5\right)}{2^{20}.3^9.\left(2+3\right)}\)

\(=\frac{1.1.\left(2.3^{18}+5\right)}{2^2.1.5}=\frac{2.3^{18}+5}{20}\)

1/ \(\frac{9.5^{20}.27^9-3.9^{15}.25^9}{7.3^{29}.125^6-3.3^9.15^{19}}\)

\(=\frac{5^{20}.3^{29}-3^{31}.5^{18}}{7.3^{29}.5^{18}-3^{29}.5^{19}}=\frac{3^{29}.5^{18}.\left(25-9\right)}{3^{29}.5^{18}.\left(7-5\right)}=\frac{16}{2}=8\)

CÁC BÀI CÒN LẠI TƯƠNG TỰ HẾT NHÉ E