\(2x\left(x-2\right)+5\left(x+3\right)+3\left(x+1\right).\)

\(=2x^2-4x+5x+15+3x+3=2x^2+4x+18.\)

\(5x^2-2\left(x+1\right)+3x\left(x-2\right)+5.\)

\(=5x^2-2x-2+3x^2-6x+5=8x^2-8x+3.\)

\(a/4x\left(x-3\right)-3x\left(2+x\right)\\ =4x.x-4x.3-3x.2-3x.x\\ =4x^2-12x-6x-3x^2\\ =x^2-18x\\ b/2x\left(5x+2\right)+\left(2x-3\right)\left(3x-1\right)\\ =2x.5x+2x.2+2x.3x-2x.1-3.3x+3.1\\ =10x^2+4x+6x^2-2x-9x+3\\ =16x^2-7x+3\)

Thu gọn:

(x-1)^2 - (x+2)(x-2)

4x(x-3) -3x(2+x)

2x(5x+2) + (2x-3)(3x-1)

\(\left(x-1\right)^2-\left(x+2\right)\left(x-2\right)\)

\(=x^2-2x+1-x^2+4\)

\(=-2x+5\)

\(4x\left(x-3\right)-3x\left(2+x\right)\)

\(=4x^2-12x-6x-3x^2\)

\(=x^2-18x\)

\(2x\left(5x+2\right)+\left(2x-3\right)\left(3x-1\right)\)

\(=10x^2+4x+6x^2-11x+3\)

\(=16x^2-7x+3\)

\(a,=3x^2-12+12x-3x^2+8-2x=10x-4\\ b,=x^2+10x+25+5x^2+15x-x-3=6x^2+24x+22\)

1+1=

a: =12x^3y^2-12x^3y^3+6x^2y^2

b: =\(\left(-3x+2\right)\left(5x^2-\dfrac{1}{3}x+4\right)\)

=-15x^3+x^2-12x+10x^2-2/3x+8

=-15x^3+11x^2-38/3x+8

c: =x^2-x-2+3x-x^2

=2x-2

a: =18x^3y^2-12x^3y^3+6x^2y^2

b: (-3x+2)(5x^2-1/3x+4)

=-12x^3+x^2-12x+10x^2-2/3x+8

=-12x^3+11x^2-38/3x+8

c: =x^2-x-2+3x-x^2

=2x-2

d: =4x^2+12x+9-4x^2+25-(x-1)(x^2+12)

=12x+34-x^3-12x+x^2+12

=-x^3+x^2+46

a) A = 4x(3x - 2 )- 6x(x-3)

       = 12x^2 - 8x - 12x^2 + 18x

       = 10x

b) B = 5x(x^2 - 2x + 1 ) - x^2 (5x-2)

        = 5x^3 - 10x^2 + 5x -5x^3 + 2x^2

       =  -8x^2 + 5x

a, 14x ( 3x - 2 ) - 6x ( x- 3 )

= 14 x ²-8x-6x ²+18 x

= 6x²+ 10 x

b , 5x ( x²-2x +1 ) - x²(5x - 2 )

= 5x ³-10x²+ 5x -5x ³+ 2x²

= -8x²+ 5x

tick đún _ g mình nha

a: Ta có: \(x^2-4x\left(3x-4\right)+7x-5\)

\(=x^2-12x^2+16x+7x-5\)

\(=-11x^2+23x-5\)

b: Ta có: \(7x\left(x^2-5\right)-3x^2y\left(xy-6y^2\right)\)

\(=7x^3-35x-3x^3y^2+18x^2y^3\)

c: Ta có: \(\left(5x+4\right)\left(2x-7\right)\)

\(=10x^2-35x+8x-28\)

\(=10x^2-27x-28\)

f(x)=2x^2-3x+3+8x

     =2x^2+8x-3x+3

     =2x^2+5x-3

g(x)=5x^2+5x+x^4-2-3x

      =x^4+5x^2+5x-3x-2

      =x^4+5x^2+2x-2