10.6 :x+7.19:X=3
tìm x
10.6 : x + 7.19 : x = 3
7 : x - 3.9 : x = 5
10.6 : x + 7.19 : x = 3
(10,6+7,19):x=3
17,79:x=3
x=17,79:3
x=5,93
7 : x - 3.9 : x = 5
(7-3,9):x=5
3,1:x=5
x=3,1:5
x=0,62
\(a,10,6:x+7,19:x=3\\ \left(10,6+7,19\right):x=3\\ 17,79:x=3\\ x=17,79:3\\ x=5,93\\ b,7:x-3,9:x=5\\ \left(7-3,9\right):x=5\\ 3,1:x=5\\ x=3,1:5\\ x=0,62\)
\(10,6:x+7,19:x=3\)
\(\left(10,6+7,19\right):x=3\)
\(17,79:x=3\)
\(x=\dfrac{17,19}{3}\)
\(x=5,73\)
\(------------\)
\(7:x-3,9:x=5\)
\(\left(7-3,9\right):x=5\)
\(3,1:x=5\)
\(x=\dfrac{3,1}{5}\)
\(x=0,62\)
16,2 x 4.7 + 10.6 x 8.1 - 7.8 x 4.5 - 2.3 x 15.6
x nhân 2.6 cộng x nhân 6.4 cộng x bằng 10.6
Tìm x chứ gì :
X * 2,6 + X * 6,4 + X = 10,6
X * [ 2,6 + 6,4 + 1 ] = 10,6
X * 10 = 10,6
X = 10,6 : 10
X = 1,06
NHỚ K MÌNH NHÉ !!!!!!!!!!
-2^10.3^10.6^9/4^3.(-16)^19
-2^10.3^10.6^9/4^3.(-16)^19
HELP
a,3/7.19/15-3/7.12/15 b,1/5+(-1/3)ᒾ.√81/25 c,(-1/2)³:3/8+|-2/3|-2021⁰
a: \(=\dfrac{3}{7}\cdot\dfrac{7}{5}=\dfrac{3}{5}\)
b: \(=\dfrac{1}{5}+\dfrac{1}{9}=\dfrac{14}{45}\)
2^10.6^15+3^14.15.4^13/2^19.18^7.3-3^15.2^25 =?
Ta có: 210.615+314.15.413:219 .187.3-315.225
=210.215.315+314.3.5.226:219.97.27.3-315.225
=225.315+315.225.10:225.315.2-315.225
=225.315+5-225.315
=5
\(\frac{7}{4}-\left(\frac{1}{2.2}+\frac{1}{4.3}+\frac{1}{6.4}+\frac{1}{8.5}+\frac{1}{10.6}+\frac{1}{12.7}+\frac{1}{14.8}\right):x=0\)
\(\frac{7}{4}-\left(\frac{1}{2.2}+\frac{1}{4.3}+\frac{1}{6.4}+\frac{1}{8.5}+\frac{1}{10.6}+\frac{1}{12.7}+\frac{1}{14.8}\right)\div x=0\)
\((\frac{1}{2.2}+\frac{1}{4.3}+\frac{1}{6.4}+\frac{1}{8.5}+\frac{1}{10.6}+\frac{1}{12.7}+\frac{1}{14.8})\div x=\frac{7}{4}\)
\((\frac{1}{4}+\frac{1}{12}+\frac{1}{24}+\frac{1}{40}+\frac{1}{60}+\frac{1}{84}+\frac{1}{112})\div x=\frac{7}{4}\)
\(\left[\frac{1}{2}\left(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+\frac{1}{30}+\frac{1}{42}+\frac{1}{56}\right)\right]\div x=\frac{7}{4}\)
\(\left[\frac{1}{2}\left(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+\frac{1}{5.6}+\frac{1}{6.7}+\frac{1}{7.8}\right)\right]\div x=\frac{7}{4}\)
\(\left[\frac{1}{2}\left(1-\frac{1}{8}\right)\right]\div x=\frac{7}{4}\)
\(\left(\frac{1}{2}.\frac{7}{8}\right)\div x=\frac{7}{4}\)
\(\frac{7}{16}\div x=\frac{7}{4}\)
\(x=\frac{7}{16}\div\frac{7}{4}\)
\(x=\frac{7}{16}\times\frac{4}{7}\)
\(x=\frac{1}{4}\)
\(\frac{7}{4}-\left(\frac{1}{2\cdot2}+\frac{1}{4\cdot3}+\frac{1}{6\cdot4}+\frac{1}{8\cdot5}+\frac{1}{10\cdot6}+\frac{1}{12\cdot7}+\frac{1}{14\cdot8}\right)\)
\(=\frac{7}{4}-\left(\frac{1}{4}+\frac{1}{12}+\frac{1}{24}+\frac{1}{40}+\frac{1}{60}+\frac{1}{84}+\frac{1}{112}\right)\)
\(=\frac{7}{4}-\frac{1}{2}\left(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+\frac{1}{30}+\frac{1}{42}+\frac{1}{56}\right)\)
\(=\frac{7}{4}-\frac{1}{2}\left(\frac{1}{1\cdot2}+\frac{1}{2\cdot3}+\frac{1}{3\cdot4}+\frac{1}{4\cdot5}+\frac{1}{5\cdot6}+\frac{1}{6\cdot7}+\frac{1}{7\cdot8}\right)\)
\(=\frac{7}{4}-\frac{1}{2}\left(\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{6}-\frac{1}{7}+\frac{1}{7}-\frac{1}{8}\right)\)
\(=\frac{7}{4}-\frac{1}{2}\left(1-\frac{1}{8}\right)\)
\(=\frac{7}{4}-\frac{1}{2}\cdot\frac{7}{8}\)
\(=\frac{7}{4}-\frac{7}{16}=\frac{28}{16}-\frac{7}{16}=\frac{21}{16}\)
19.5+7.19+12-18.12
\(19\times5+7\times19+12-18\times12\)
\(=19\left(5+7\right)+12\left(1-18\right)\)
\(=19\times12+12\times\left(-17\right)\)
\(=12\left[19+\left(-17\right)\right]\)
\(=12\times2=24\)
19.5+7.19+12-18.12=19(5+7) +12(1-18)
=19.12+12(-17)
=12(19-17)
=12.2=24
19.5+17.19+12-18.12
=[ 19×(5+7)] + 12-216
=19.12+12-216
=288+(-204)
=24