Ta có: \(\frac{-2^{10}\cdot3^{10}\cdot6^9}{4^3\cdot\left(-16\right)^{19}}\)
\(=\frac{-2^{10}\cdot3^{10}\cdot2^9\cdot3^9}{2^6\cdot\left(-1\right)\cdot16^{19}}=\frac{2^{19}\cdot3^{19}}{2^6\cdot\left(2^4\right)^{19}}\)
\(=\frac{2^{13}\cdot3^{19}}{2^{76}}=\frac{3^{19}}{2^{63}}\)