\(\left(-\dfrac{2}{3}\right)^2:\dfrac{5}{9}+0.25\)
Những câu hỏi liên quan
\(\left(0.25\right)^{10}\cdot4^{10}+\sqrt{5^2-3^2}\)
\(\dfrac{5}{20}+\dfrac{18}{11}-25\%-\left(\dfrac{18}{11}-\dfrac{4}{9}\right)\)
\(\left(0.25\right)^{10}.4^{10}+\sqrt{5^2-3^2}\)
\(=0.4^{10}+\sqrt{25-9}\)
\(=0+\sqrt{16}=0+4=4\)
\(\dfrac{5}{20}+\dfrac{18}{11}-25\%-\left(\dfrac{18}{11}-\dfrac{4}{9}\right)\)
\(=\dfrac{5}{20}+\dfrac{18}{11}-\dfrac{1}{4}-\dfrac{18}{11}+\dfrac{4}{9}\)
\(=\left(\dfrac{5}{20}-\dfrac{1}{4}\right)+\left(\dfrac{18}{11}-\dfrac{18}{11}\right)+\dfrac{4}{9}\)
\(=0+0+\dfrac{4}{9}=\dfrac{4}{9}\)
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(0,25)10.410 + \(\sqrt{5^2-3^2}\)
= (0,25 .4)10 + \(\sqrt{25-9}\)
= 110 + \(\sqrt{16}\)
= 1 + 4
= 5
\(\dfrac{5}{20}\) + \(\dfrac{18}{11}\) - 25% - ( \(\dfrac{18}{11}\) - \(\dfrac{4}{9}\))
= 25% + \(\dfrac{18}{11}\) - 25% - \(\dfrac{18}{11}\) + \(\dfrac{4}{9}\)
= ( 25% - 25%) + ( \(\dfrac{18}{11}\) - \(\dfrac{18}{11}\)) + \(\dfrac{4}{9}\)
= 0 + 0 + \(\dfrac{4}{9}\)
= \(\dfrac{4}{9}\)
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1/ (left(-dfrac{2}{3}right)^2 x dfrac{-9}{8} - 25% x dfrac{-16}{5} 2/ -1dfrac{2}{5} x 75% + dfrac{-7}{5} x 25% 3/ -2dfrac{3}{7} x (-125%) + dfrac{-17}{7} x 25% 4/ (-2)^3 x (dfrac{3}{4} x 0.25) : (2dfrac{1}{4} - 1dfrac{1}{6})
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1/ (\(\left(-\dfrac{2}{3}\right)\)\(^2\) x \(\dfrac{-9}{8}\) - 25% x \(\dfrac{-16}{5}\)
2/ -1\(\dfrac{2}{5}\) x 75% + \(\dfrac{-7}{5}\) x 25%
3/ -2\(\dfrac{3}{7}\) x (-125%) + \(\dfrac{-17}{7}\) x 25%
4/ (-2)\(^3\) x (\(\dfrac{3}{4}\) x 0.25) : (2\(\dfrac{1}{4}\) - 1\(\dfrac{1}{6}\))
1) Ta có: \(\left(-\dfrac{2}{3}\right)^2\cdot\dfrac{-9}{8}-25\%\cdot\dfrac{-16}{5}\)
\(=\dfrac{4}{9}\cdot\dfrac{-9}{8}-\dfrac{1}{4}\cdot\dfrac{-16}{5}\)
\(=\dfrac{-1}{2}+\dfrac{4}{5}\)
\(=\dfrac{-5}{10}+\dfrac{8}{10}=\dfrac{3}{10}\)
2) Ta có: \(-1\dfrac{2}{5}\cdot75\%+\dfrac{-7}{5}\cdot25\%\)
\(=\dfrac{-7}{5}\cdot\dfrac{3}{4}+\dfrac{-7}{5}\cdot\dfrac{1}{4}\)
\(=\dfrac{-7}{5}\left(\dfrac{3}{4}+\dfrac{1}{4}\right)=-\dfrac{7}{5}\)
3) Ta có: \(-2\dfrac{3}{7}\cdot\left(-125\%\right)+\dfrac{-17}{7}\cdot25\%\)
\(=\dfrac{-17}{7}\cdot\dfrac{-5}{4}+\dfrac{-17}{7}\cdot\dfrac{1}{4}\)
\(=\dfrac{-17}{7}\cdot\left(\dfrac{-5}{4}+\dfrac{1}{4}\right)\)
\(=\dfrac{17}{7}\)
4) Ta có: \(\left(-2\right)^3\cdot\left(\dfrac{3}{4}\cdot0.25\right):\left(2\dfrac{1}{4}-1\dfrac{1}{6}\right)\)
\(=\left(-8\right)\cdot\left(\dfrac{3}{4}\cdot\dfrac{1}{4}\right):\left(\dfrac{9}{4}-\dfrac{7}{6}\right)\)
\(=\left(-8\right)\cdot\dfrac{3}{16}:\dfrac{54-28}{24}\)
\(=\dfrac{-3}{2}\cdot\dfrac{24}{26}\)
\(=\dfrac{-72}{52}=\dfrac{-18}{13}\)
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Tính \(A=\left(0.25\right)^{-1}.\left(\dfrac{1}{4}\right)^{-2}.\left(\dfrac{4}{3}\right)^{-2}.\left(\dfrac{5}{4}\right)^{-1}.\left(\dfrac{2}{3}\right)^{-3}\)
Ta có: \(A=\left(0,25\right)^{-1}.\dfrac{1}{4}^{-2}.\dfrac{4}{3}^{-2}.\dfrac{5}{4}^{-1}.\dfrac{2}{3}^{-3}\)
--> A= \(\left(\dfrac{\dfrac{1}{1}}{4}\right).\left(\dfrac{\dfrac{1}{1}}{4^2}\right).\left(\dfrac{\dfrac{1}{4^2}}{3^2}\right).\left(\dfrac{\dfrac{1}{5}}{4}\right).\left(\dfrac{\dfrac{1}{2^3}}{3^3}\right)\)
--> A= 4.42. \(\dfrac{3^2}{4^2}\).\(\dfrac{4}{5}\) . \(\dfrac{3^3}{2^3}\)
--> A= \(\dfrac{4.4^2.3^2.3^3}{4^{2.}.5.2^3}=\dfrac{2.3^5}{5}=\dfrac{2.243}{5}\)
--> A= 97,2
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\(A=\left(0,25\right)^{-1}.\left(\dfrac{1}{4}\right)^{-2}.\left(\dfrac{4}{3}\right)^{-2}.\left(\dfrac{5}{4}\right)^{-1}.\left(\dfrac{2}{3}\right)^{-3}\)
\(A=\left[\left(\dfrac{1}{4}\right)^{-1}.\left(\dfrac{5}{4}\right)^{-1}\right]\left[\left(\dfrac{1}{4}\right)^{-2}.\left(\dfrac{4}{3}\right)^{-2}\right].\left(\dfrac{2}{3}\right)^{-3}\)
\(A=\left(\dfrac{5}{16}\right)^{-1}.\left(\dfrac{1}{3}\right)^{-2}.\left(\dfrac{2}{3}\right)^{-3}\)
\(A=\dfrac{16}{5}.9.\dfrac{27}{8}\)
\(A=\dfrac{2.9.27}{5}=\dfrac{486}{5}=97,2\)
#chucbanhoctotnhe 
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thực hiện phép tính
a. \(\dfrac{11}{21}+\dfrac{-2}{7}+\dfrac{10}{21}+\left(-1\dfrac{1}{5}\right)+\dfrac{-5}{7}\)
\(b.\left(0.25\right)^5.\left(-5\dfrac{5}{9}\right).\left(-4\right)^5\)
\(c.\dfrac{3}{22}.19\dfrac{1}{7}+\dfrac{3}{22}.2\dfrac{6}{7}-\sqrt{36}\)
a: \(=\dfrac{11}{21}+\dfrac{10}{21}+\dfrac{-2}{7}+\dfrac{-5}{7}-\dfrac{6}{5}=\dfrac{-6}{5}\)
b: \(=\left[0.25\cdot\left(-4\right)\right]^5\cdot\left(-\dfrac{50}{9}\right)\)
=50/9
c: \(=\dfrac{3}{22}\left(19+\dfrac{1}{7}+2+\dfrac{6}{7}\right)-6\)
\(=\dfrac{3}{22}\cdot22-6=3-6=-3\)
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Bài 1: Thực hiện phép tính:
Aleft(-dfrac{1}{125}right)^{11}:left(dfrac{1}{5}right)^{32}
B1+dfrac{1}{3}+left(dfrac{1}{3}right)^2+....+left(dfrac{1}{3}right)^{2018}
Cdfrac{16^3cdot3^{10}+120cdot6^9}{4^6cdot3^{12}+6^{11}}
Dleft(dfrac{0.4-dfrac{2}{9}+dfrac{2}{11}}{1.4-dfrac{7}{9}+dfrac{7}{11}}-dfrac{dfrac{1}{3}-0.25+dfrac{1}{5}}{1dfrac{1}{6}-0.875+0.7}right):dfrac{2017}{2018}
Edfrac{1}{2}+dfrac{1}{6}+dfrac{1}{12}+dfrac{1}{20}+dfrac{1}{30}+dfrac{1}{42}+dfrac{1}{56}+dfrac{1}{72}
Gdfrac{left(dfra...
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Bài 1: Thực hiện phép tính:
\(A=\left(-\dfrac{1}{125}\right)^{11}:\left(\dfrac{1}{5}\right)^{32}\)
\(B=1+\dfrac{1}{3}+\left(\dfrac{1}{3}\right)^2+....+\left(\dfrac{1}{3}\right)^{2018}\)
\(C=\dfrac{16^3\cdot3^{10}+120\cdot6^9}{4^6\cdot3^{12}+6^{11}}\)
\(D=\left(\dfrac{0.4-\dfrac{2}{9}+\dfrac{2}{11}}{1.4-\dfrac{7}{9}+\dfrac{7}{11}}-\dfrac{\dfrac{1}{3}-0.25+\dfrac{1}{5}}{1\dfrac{1}{6}-0.875+0.7}\right):\dfrac{2017}{2018}\)
\(E=\dfrac{1}{2}+\dfrac{1}{6}+\dfrac{1}{12}+\dfrac{1}{20}+\dfrac{1}{30}+\dfrac{1}{42}+\dfrac{1}{56}+\dfrac{1}{72}\)
\(G=\dfrac{\left(\dfrac{2}{5}\right)^7\cdot5^7+\left(2\dfrac{1}{4}\right)^3:\left(\dfrac{3}{16}\right)^3}{512+2^7\cdot5^2}:\dfrac{\left(\dfrac{1}{2}\right)^0}{\left(-1\right)^{2017}}\)
Mn ơi giúp e với ........ Em đang cần gấp giúp e với nha!!
Thank you mn nhiều nhiều.....
Bài 1:
a: \(A=\left(-\dfrac{1}{5}\right)^{33}:\left(-\dfrac{1}{5}\right)^{32}=\dfrac{-1}{5}\)
c: \(C=\dfrac{2^{12}\cdot3^{10}+3^9\cdot2^9\cdot2^3\cdot3\cdot5}{2^{12}\cdot3^{12}+2^{11}\cdot3^{11}}\)
\(=\dfrac{2^{12}\cdot3^{10}\left(1+5\right)}{2^{11}\cdot3^{11}\cdot7}=\dfrac{2}{3}\cdot\dfrac{6}{7}=\dfrac{12}{21}=\dfrac{4}{7}\)
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Tính:
a) \(\sqrt{\dfrac{9}{16}}-\dfrac{5}{6}+\dfrac{3}{2}\) b) \(\left(\dfrac{1}{9}+\dfrac{2}{3}\right)^2-\dfrac{5}{3}:\sqrt{25}\)
c)\(\dfrac{5}{11}.\left(-\dfrac{3}{7}\right)+\dfrac{5}{11}.\left(\dfrac{-5}{7}\right)+\left(-\dfrac{8}{7}\right).\dfrac{6}{11}\)
d) \(\dfrac{2^8.2^{18}}{8^5.4^6}\)
a: \(=\dfrac{3}{4}-\dfrac{5}{6}+\dfrac{3}{2}=\dfrac{9-10+18}{12}=\dfrac{17}{12}\)
b: \(=\left(\dfrac{1}{9}+\dfrac{6}{9}\right)^2-\dfrac{1}{3}=\dfrac{49}{81}-\dfrac{27}{81}=\dfrac{22}{81}\)
c; \(=\dfrac{5}{11}\left(-\dfrac{3}{7}-\dfrac{5}{7}\right)+\dfrac{-8}{7}\cdot\dfrac{6}{11}=\dfrac{-8}{7}\left(\dfrac{5}{11}+\dfrac{6}{11}\right)=-\dfrac{8}{7}\)
d: \(=\dfrac{2^{26}}{2^{15}\cdot2^{12}}=\dfrac{1}{2}\)
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Tính giá trị của biểu thức:Adfrac{-3}{7}.dfrac{5}{9}+dfrac{4}{9}.dfrac{-3}{7}+left(-2022right)^0B0,75-left(2dfrac{1}{3}+0,75right)+3^2.left(-dfrac{1}{9}right)C2dfrac{6}{7}.left[left(dfrac{-7}{5}-dfrac{3}{2}:dfrac{-5}{-4}right)+left(dfrac{3}{2}right)^2right]Ddfrac{2}{7}+dfrac{5}{7}.left(dfrac{3}{5}-0,25right).left(-2right)^2+35%E1dfrac{13}{15}.0,75-left(dfrac{11}{20}+25%right):1dfrac{2}{5}Fdfrac{dfrac{5}{3}-dfrac{5}{7}+dfrac{5}{9}}{dfrac{10}{3}-dfrac{10}{7}+dfrac{10}{9}}
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Tính giá trị của biểu thức:
\(A=\dfrac{-3}{7}.\dfrac{5}{9}+\dfrac{4}{9}.\dfrac{-3}{7}+\left(-2022\right)^0\)
\(B=0,75-\left(2\dfrac{1}{3}+0,75\right)+3^2.\left(-\dfrac{1}{9}\right)\)
\(C=2\dfrac{6}{7}.\left[\left(\dfrac{-7}{5}-\dfrac{3}{2}:\dfrac{-5}{-4}\right)+\left(\dfrac{3}{2}\right)^2\right]\)
\(D=\dfrac{2}{7}+\dfrac{5}{7}.\left(\dfrac{3}{5}-0,25\right).\left(-2\right)^2+35\%\)
\(E=1\dfrac{13}{15}.0,75-\left(\dfrac{11}{20}+25\%\right):1\dfrac{2}{5}\)
\(F=\dfrac{\dfrac{5}{3}-\dfrac{5}{7}+\dfrac{5}{9}}{\dfrac{10}{3}-\dfrac{10}{7}+\dfrac{10}{9}}\)
tính
a,\(6\dfrac{4}{5}-\left(1\dfrac{2}{3}+3\dfrac{4}{5}\right)\)
b,\(7\dfrac{5}{9}-\left(2\dfrac{3}{4}+3\dfrac{5}{9}\right)\)
c,\(6\dfrac{7}{7}-\left(1\dfrac{3}{4}+2\dfrac{5}{7}\right)\)
a: \(=6+\dfrac{4}{5}-1-\dfrac{2}{3}-3-\dfrac{4}{5}\)
\(=2-\dfrac{2}{3}=\dfrac{4}{3}\)
b: \(=7+\dfrac{5}{9}-2-\dfrac{3}{4}-3-\dfrac{5}{9}=2-\dfrac{3}{4}=\dfrac{5}{4}\)
c: =6+7/7-1-3/4-2-5/7
=3+2/7-3/4
=84/28+8/28-21/28
=84/28-13/28
=71/28
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Tìm x liên quan đến lũy thừa:
1, \(\left(3x-\dfrac{1}{5}\right)^2=\left(\dfrac{-3}{25}\right)^2\)
2, \(\left(2x-\dfrac{1}{3}\right)^2=\left(\dfrac{-2}{9}\right)^2\)
3, \(\left(\dfrac{1}{3}-x\right)^2=\dfrac{9}{25}\)
4, \(\left(5-x\right)^2=25\)
1: \(\left(3x-\dfrac{1}{5}\right)^2=\left(-\dfrac{3}{25}\right)^2\)
=>3x-1/5=3/25 hoặc 3x-1/5=-3/25
=>3x=8/25 hoặc 3x=2/25
=>x=8/75 hoặc x=2/75
2: \(\left(2x-\dfrac{1}{3}\right)^2=\left(-\dfrac{2}{9}\right)^2\)
=>2x-1/3=2/9 hoặc 2x-1/3=-2/9
=>2x=5/9 hoặc 2x=1/9
=>x=5/18 hoặc x=1/18
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\(a,\left(\dfrac{4}{9}+\dfrac{1}{3}\right)^2\)
\(b,\left(\dfrac{1}{2}-\dfrac{3}{5}\right)^3\)
c,\(\left(\dfrac{-10}{3}\right)^5.\left(\dfrac{-6}{4}\right)^4\)
\(\left(\dfrac{3}{4}\right)^3:\left(\dfrac{3}{4}\right)^2:\left(\dfrac{-3}{2}\right)^3\)
a: \(\left(\dfrac{4}{9}+\dfrac{1}{3}\right)^2=\dfrac{49}{81}\)
b: \(\left(\dfrac{1}{2}-\dfrac{3}{5}\right)^3=-\dfrac{1}{1000}\)
c: \(\left(-\dfrac{10}{3}\right)^5\cdot\left(-\dfrac{6}{4}\right)^4=-\dfrac{6250}{3}\)
d: \(\left(\dfrac{3}{4}\right)^3:\left(\dfrac{3}{4}\right)^2:\left(-\dfrac{3}{2}\right)^3=-\dfrac{2}{9}\)
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