3 : 7 =  3 7 ;  4∶9 =  4 9 ; 23∶6 =  23 6

25 : 100 =  25 100 ; 100∶33 =  100 33 ; 10∶31 =  10 31

a: =7-2+5=10

a.
(5/11 + 6/11 ) + ( 1/4 +3/4) + ( 6/25 + 9/25)
= 11/11 + 4/4 + 15/25
= 1 +1 + 3/5
= 2+3/5 = 13/5
b.
( 37/100 + 163/100) + (1/8 + 3/8 ) + 19/4 + 1/2
=  200/100 + 4/8 + ( 19/4 + 2/4)
=    2 + 1/2 + 21/4
=  31/4

\(=\dfrac{1}{4}-\dfrac{1}{5}+\dfrac{13}{4}+\dfrac{3}{4}-\dfrac{1}{20}=4+\left(\dfrac{1}{4}-\dfrac{1}{5}-\dfrac{1}{20}\right)=4+0=4\)

=4

ok

\(\frac{9}{100}=>\frac{13}{100}=>\frac{14}{100}=>\frac{15}{100}=>\frac{16}{100}=>\frac{17}{100}=>\frac{20}{100}\)

\(=>\frac{20}{100}=>\frac{24}{100}=>\frac{25}{100}=>\frac{29}{100}=>\frac{31}{100}=>\frac{36}{100}=>\frac{37}{100}=>\frac{67}{100}\)

\(\frac{93}{100}=>\frac{100}{99}=>\frac{100}{94}=>\frac{100}{92}=>\frac{100}{91}=>\frac{100}{89}\)

9/100  13/100  14/100  15/100  16/100  17/100  20/100  24/100  25/100  29/100  31/100  36/100  37/100  67/100  93/100  100/99  100/94  100/92  100/91  100/89.

\(\dfrac{2}{9}+\dfrac{3}{9}=\dfrac{5}{9}\)
\(\dfrac{3}{15}+\dfrac{5}{5}=\dfrac{1}{5}+\dfrac{5}{5}=\dfrac{6}{5}\)
\(\dfrac{4}{25}+\dfrac{3}{100}=\dfrac{16}{100}+\dfrac{3}{100}=\dfrac{19}{100}\)
\(\dfrac{4}{9}+\dfrac{3}{2}=\dfrac{8}{18}+\dfrac{27}{18}=\dfrac{35}{18}\)

`2/9 +3/9=(2+3)/9=5/9`

`3/15 + 5/5 = 3/15 + 15/15 = 18/15`

`4/25 + 3/100= 16/100 + 3/100= 19/100`

`4/9 + 3/2= 8/18+ 27/18= 35/18`

=1 chúc bạn học tốt

bạn giải chi tiết ra cho mk với

\(\frac{\left(3\times5^2\right)^{50}\times2^{100}}{\left(2^2\times5^2\right)^{50}\times\left(3^2\right)^{25}}\)=\(\frac{3^{50}\times5^{100}\times2^{100}}{2^{100}\times5^{100}\times3^{50}}\)=\(\frac{1\times1\times1}{1\times1\times1}\)=1

cau1 :120-(100+x)=25

100+x=120-25

100+x=95

x=-5

cau2: 5(x+23)+6=96

5(x+23)+6=96

5(x+23)=90

x+23=18

x=-5

cau3: 100-(25+x)=40

25+x=100-40

25+x=60

x=35

cau4: 35-9(x+2)=45

9(x+2)=-10

x+2=-10/9

x=-28/9

cau 4 cua ban ghi gi minh ko  hieu

\(\dfrac{75^{50}.2^{100}}{100^{50}.9^{25}}=\dfrac{\left(25.3\right)^{50}.2^{100}}{\left(25.4\right)^{50}.\left(3^2\right)^{25}}=\dfrac{25^{50}.3^{50}.2^{100}}{25^{50}.4^{50}.3^{50}}=\dfrac{25^{50}.3^{50}.2^{100}}{25^{50}.\left(2^{2^{ }}\right)^{50}.3^{50}}=\dfrac{25^{50}.3^{50}.2^{100}}{25^{50}.2^{100}.3^{50}}=1\)