3^x+15=42
tìm số nguyên x biết:
a)x/-3=-15/-5
b)x/9=-7/63
c)x+3/15=-1/3
d)42/-54=-7/x
a: =>x/-3=3
hay x=-9
b: =>x/9=-1/9
hay x=-1
c: =>x+1/5=-1/3
hay x=-8/15
d: =>-7/x=-7/9
hay x=9
a, \(\dfrac{x}{-3}=3\Leftrightarrow x=-9\)
b, \(\dfrac{x}{9}=-\dfrac{1}{9}\Rightarrow x=-1\)
c, \(\dfrac{x+3}{15}=-\dfrac{6}{15}\Rightarrow x=-9\)
d, \(\dfrac{42}{-54}=-\dfrac{42}{6x}\Rightarrow6x=54\Leftrightarrow x=9\)
(3.x-15).17=42
`#3107.101107`
`(3x - 15) . 17 = 42`
`\Rightarrow 3x - 15 =` $\dfrac{42}{17}$
`\Rightarrow 3x =` $\dfrac{42}{17} + 15$
`\Rightarrow 3x =` $\dfrac{297}{17}$
`\Rightarrow x =` $\dfrac{297}{17} \div 3$
$\Rightarrow x = \dfrac{99}{17}$
Vậy, $x = \dfrac{99}{17}.$
a) 42-x=5
b) 15.(x+4)=75
c) 27+3x=9^8.9^7
d) x+18=12
e) 2x-15=-19
f) 36 :(x^3-12)=-3
g)x+15=35
h) 2x-13=3^2
a) 42 - x = 5
x = 42 - 5
x = 37
b) 15.(x + 4) = 75
x + 4 = 75 : 15
x + 4 = 5
x = 5 - 4
x = 1
d) x + 18 = 12
x = 12 - 18
x = -6
e) 2x - 15 = -19
2x = (-19) + 15
2x = -4
x = -4 : 2
x = -2
f) 36 : (x^3 - 12) = -3
x^3 - 12 = 36 : (-3)
x^3 - 12 = -12
x^3 = 0
=> x = 0
g)x + 15 = 35
x = 35 - 15
x = 20
h) 2x - 13 = 3^2
2x - 13 = 9
2x = 9 + 13
2x = 22
x = 22 : 2
x = 11
a) 42-x=5
x=42-5
x= 37
b)15*(x+4)=75
x+4=75:15
x+4=5
x =5-4
x = 1
a) 42 - x = 5
x = 42 - 5
x = 37
b) 15.(x + 4) = 75
x + 4 = 75 : 15
x + 4 = 5
x = 5 - 4
x = 1
d) x + 18 = 12
x = 12 - 18
x = -6
e) 2x - 15 = -19
2x = (-19) + 15
2x = -4
x = -4 : 2
x = -2
f) 36 : (x^3 - 12) = -3
x^3 - 12 = 36 : (-3)
x^3 - 12 = -12
x^3 = 0
=> x = 0
g)x + 15 = 35
x = 35 - 15
x = 20
h) 2x - 13 = 3^2
2x - 13 = 9
2x = 9 + 13
2x = 22
x = 22 : 2
x = 11
Bài 3. Tìm x. x/36 = 3/4 ; x/7 = 56/49 ; 15/27 = 5/x ; 3/7 = 42/x
x-42= -15+27:3^2
x-42=-15+27:9
x-42=-15+3
x-42=-12
x=-12+42
x=30
Vậy x=30
X-42= -15+27÷3^2
x-42= -15+27÷3^2
x-42= -15+27÷9
x-42= -15+3
x-42= -12
x= -12+42
x= 42-12
x= 30
Chúc bạn học tốt!
X - 42 = - 15 + 27 : 32
X - 42 = - 15 + 27 : 9
X - 42 = - 15 + 3
X - 42 = - 12
X = ( - 12 ) + 42
X = 30
X -42=-15+27:32
=> x -42= -15 +27 :9
=> x-42 = -15 +3
=> x-42= -12
=>x= 42+-12
=> x=30
Tìm stn x biết
[3 (42-x )+15]÷5=2^3×3
<=> 126 - 3x + 15 = 8 x 3 x 5
<=> 3x = 126 + 15 - 8 x 3 x 5
<=> 3x = 21
<=> x = 7
[3 (42-X )+15]÷5=2^3×3
[3 (42-x )+15]÷5=8×3
[3 (42-x )+15]÷5=24
3 (42-x )+15=24×5
3 (42-x )+15=120
3 (42-x )=120-15
3 (42-x )=105
42-x=105÷3
42-x=35
x=42-35
x=7
4 giờ 15 phút x 3 +1 giờ 42 phút x 2
Tìm x, biết:
a) x + 99:3 = 55
b) (x - 25): 15=20
c) (3.x - 15).7 = 42
d) (8x - 16)(x-5)=0
e) x.(x+1)=2+4+6+8+10+...+2500
a, \(x\) + 99: 3 = 55
\(x\) + 33 = 55
\(x\) = 55 - 33
\(x\) = 22
b, (\(x\) - 25):15 = 20
\(x\) - 25 = 20 x 15
\(x\) - 25 = 300
\(x\) = 300 + 25
\(x\) = 325
c, (3\(x\) - 15).7 = 42
3\(x\) - 15 = 42:7
3\(x\) - 15 = 6
3\(x\) = 6 + 15
3\(x\) = 21
\(x\) = 21: 3
\(x\) = 7
d, (8\(x\) - 16).(\(x\) -5) = 0
\(\left[{}\begin{matrix}8x-16=0\\x-5=0\end{matrix}\right.\)
\(\left[{}\begin{matrix}8x=16\\x=5\end{matrix}\right.\)
\(\left[{}\begin{matrix}x=16:8\\x=5\end{matrix}\right.\)
\(\left[{}\begin{matrix}x=2\\x=5\end{matrix}\right.\)
Vậy \(x\) \(\in\) {2; 5}
(x-18)-42=(23-43)-(70+x)
(-x-15) ^2 -19=(-3) ^2 .5
giúp mik với
x - 18 - 42 = 23 - 43 - 70 - x
\(\rightarrow\) 2x = -30
\(\rightarrow\) x = -15
\(\left(-\left(x+15\right)\right)^2\) - 19 = \(3^2\) .5
\(\rightarrow\)\(x^2+30x+225\) - 19 = 45
\(\rightarrow x^2+30x+161=0\)
\(\rightarrow x^2+23x+7x+161=0\)
\(\rightarrow x\left(x+23\right)+7\left(x+23\right)=0\)
\(\rightarrow\left(x+7\right)\left(x+23\right)=0\)
\(\rightarrow\) x = -7 hoặc x = -23