a) \(100+98+96+...+2-97-95-93-...-3\)

= \(100+98+\left(96-97\right)+\left(94-95\right)+...+\left(2-3\right)\)

= \(100+98-95\) = \(103\)

b) \(2-4-6+8+10-12-14+16+...-102+104\)

= \(\left(2-4\right)+\left(-6+8\right)+\left(10-12\right)+\left(-14+16\right)+...+\left(-102+104\right)\)

= \(-2+2-2+2-2+...+2\) = \(0\)

c) \(1+2-3-4+5+6-7-8+9+10-11-12+...-111-112+113+114\)

= \(\left(1+2\right)-\left(3+4\right)+\left(5+6\right)-\left(7+8\right)+...\left(113+114\right)\)

= \(3-7+11-15+19-23+...+219-223+227\)

= \(\left(3-7\right)+\left(11-15\right)+\left(19-23\right)+...+\left(219-223\right)+227\)

= \(-4-4-4-4-...-4+227\)

= \(54\left(-4\right)+227\) = \(-216+227\) = \(11\)

1: =72/90+65/90=137/90

2: =24/56-77/56=-53/56

3: =-7/10+4/5=1/10

4: =15/100-4/100=11/100

5: =4/6-5/6=-1/6

6: =10/40-15/40-76/40=-81/40

7: =-9/10+7/18

=-81/90+35/90=-46/90=-23/45

8: =27/90-55/90=-28/90=-14/45

9: =36/60-50/60-35/60=-49/60

10: =-4/9+5/6-3/8

=-32/72+60/72-27/72

=1/72

\(1,\dfrac{4}{5}+\dfrac{13}{18}=\dfrac{72}{90}+\dfrac{65}{90}=\dfrac{137}{90}\)

\(2,\dfrac{3}{7}-\dfrac{11}{8}=\dfrac{24}{56}-\dfrac{77}{56}=\dfrac{-53}{56}\)

\(3,-\dfrac{7}{10}-\left(-\dfrac{4}{5}\right)=-\dfrac{7}{10}-\left(-\dfrac{8}{10}\right)=\dfrac{1}{10}\)

\(4,\dfrac{3}{20}-\dfrac{1}{25}=\dfrac{75}{500}-\dfrac{20}{500}=\dfrac{55}{500}=\dfrac{11}{100}\)

\(5,\dfrac{2}{3}-\dfrac{5}{6}=\dfrac{12}{18}-\dfrac{15}{18}=-\dfrac{3}{18}=-\dfrac{1}{6}\)

\(6,\dfrac{1}{4}+\left(-\dfrac{3}{8}\right)-\dfrac{19}{10}=\dfrac{8}{32}+\left(-\dfrac{12}{32}\right)-\dfrac{19}{10}=-\dfrac{4}{32}-\dfrac{19}{10}\)

\(=-\dfrac{1}{8}-\dfrac{19}{10}=-\dfrac{10}{80}-\dfrac{152}{80}=-\dfrac{162}{80}=-\dfrac{81}{40}\)

\(7,-\dfrac{9}{10}-\left(-\dfrac{7}{18}\right)=-\dfrac{162}{180}-\left(-\dfrac{70}{180}\right)=-\dfrac{92}{180}=-\dfrac{23}{45}\)

\(8,\dfrac{3}{10}-\dfrac{11}{18}=\dfrac{54}{180}-\dfrac{110}{180}=-\dfrac{56}{180}=-\dfrac{14}{45}\)

\(9,\dfrac{3}{5}-\dfrac{5}{6}+\left(-\dfrac{7}{12}\right)=\dfrac{18}{30}-\dfrac{25}{30}+\left(-\dfrac{7}{12}\right)=-\dfrac{7}{30}+\left(-\dfrac{7}{12}\right)\)

\(=-\dfrac{84}{360}+\left(-\dfrac{210}{360}\right)=-\dfrac{294}{360}=-\dfrac{49}{60}\)

\(10,-\dfrac{4}{9}-\dfrac{-5}{6}-\dfrac{3}{8}=-\dfrac{24}{54}-\dfrac{-45}{54}-\dfrac{3}{8}\)

\(=\dfrac{21}{54}-\dfrac{3}{8}=\dfrac{7}{18}-\dfrac{3}{8}=\dfrac{56}{144}-\dfrac{54}{144}=\dfrac{2}{144}=\dfrac{1}{72}\)

`@mt`

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Câu dễ vậy bạn cần hỏi

Hờ, bài toán này mà mình cứ ngồi tính tổng như thật -,-

\(\text{1 + 2 - 3 - 4 + 5 + 6 - 7 - 8 + 9 + 10 - 11 - 12 + ... - 111 - 112 + 113 + 114}\)\(=1+\left(2-3-4+5\right)+\left(6-7-8+9\right)+\left(10-11-12+13\right)+...+\left(110-111-112+113\right)+114\)\(=1+114=115\)

Lớp 5: chương trình nâng cao nhé các bạn! ko có số âm nhé!

a: B=(1+2-3-4)+(5+6-7-8)+...+(109+110-111-112)+227

=(-4)+(-4)+...+(-4)+227

=-112+227=115

b: =>(15x+364):x=41

=>15x+364=41x

=>-26x=-364

=>x=14

Bài 1:

B = 1+2-3-4 + 5 + 6-7-8 + 9+10-11-12+...+110-111-112+113+114

B = 1 + (-5) + 5 + 9 + (-13)+...+ (-113) + 113 + 114

B = 1 + 114

B = 115

Bài 2:

697 : [(15x+364) : x ] = 17

(15x+364) . 1/x = 697 : 17

(15x+364) . 1/x = 41

15x. 1/x + 364.1/x = 41

15 + 364/x = 41

364/ x = 41-15

364/x = 26

x = 364 : 26

x = 14

Ta sẽ nhóm 4 số với nhau

B=(1+2-3-4)+(5+6-7-8)+(9+10-11-12)+...+(109+110-111-112)+113+114

B=-4+(-4)+(-4)+...+(-4)+113+114 (Có 28 thừa số -4)

B=-4*28+113+114

Giải tiếp bên dưới hồi nãy ấn nhầm:

B=-112+113+114

B=115

Bài 2

697:[(15X+364):X]=17

(15X+364)x1/X=697:17

(15X+364)x1/X=41

15Xx1/X+364x1/X=41

15+364/X=41

364/X=41-15

364/X=26

X=364/26

X=14