\(25+\left(x-5\right)=-13-\left(15-123\right)\\ 25+x-5=-13-\left(-108\right)\\ 20+x=95\\ x=95-20=75\)

tham khảo

25+ (x-5)=-13-(15-123)

25+ (x-5)=13-15+123

25+ (x-5)=95

x-5=75-25

x=70+5

x=75

a) \(5\left(x-7\right)=0\)

\(\Rightarrow x-7=0\)

\(\Rightarrow x=7\)

b) \(25\left(x-4\right)=0\)

\(\Rightarrow x-4=0\)

\(\Rightarrow x=4\)

c) \(\left(34-2x\right)\left(2x-6\right)=0\)

\(\Rightarrow\left[{}\begin{matrix}34-2x=0\\2x-6=0\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}2x=34\\2x=6\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=17\\x=3\end{matrix}\right.\)

d) \(\left(2019-x\right)\left(3x-12\right)=0\)

\(\Rightarrow\left[{}\begin{matrix}2019-x=0\\3x-12=0\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=2019\\3x=12\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=2019\\x=\dfrac{12}{3}=4\end{matrix}\right.\)

e) \(57\left(9x-27\right)=0\)

\(\Rightarrow9x-27=0\)

\(\Rightarrow9\left(x-3\right)=0\)

\(\Rightarrow x-3=0\)

\(\Rightarrow x=3\)

a) 5.(x-7)=0⇔x-7=0⇔x=7

b) 25(x-4)=0⇔x-4=0⇔x=4

c) (34-2x).(2x-6)=0

⇔ 34-2x=0 hoặc 2x-6=0

⇔2x=34 hoặc 2x=6

⇔ x=17 hoặc x=3

d) (2019-x).(3x-12)=0

⇔ 2019-x=0 hoặc 3x-12=0

⇔ x=2019 hoặc x=4

e) 57.(9x-27)=0

⇔ 9x-27=0

⇔ x=3

f) 25+(15-x)=30

⇔ 15-x=5

⇔ x=10

g) 43-(24-x)=20

⇔ 24-x=23

⇔ x=1

h) 2.(x-5)-17=25

⇔ 2(x-5)=42

⇔x-5=21

⇔ x=26

i) 3(x+7)-15=27

⇔ 3(x+7)=42

⇔ x+7=14

⇔ x=7

j) 15+4(x-2)=95

⇔ 4(x-2)=80

⇔ x-2=20

⇔ x=22

k) 20-(x+14)=5

⇔ x+14=15

⇔ x=1

l) 14+3(5-x)=27

⇔ 3(5-x)=13

⇔ 5-x=13/3

⇔ x=5-13/3

⇔ x=2/3

a)2-x=17-(-5)

2-x=17+5

2-x=22

x=2-20

x=-20

b)x-12=-9-15

x-12=-24

x=(-24)+12

x=-12

c)11-(15+11)=x-(25-9)

11-26=x-16

-15=x-16

x=-15+16

x=1

d)x-25=(7-x)-(25+7)

x-25=(7-x)-32

2x-25=7-32

2x-25=-25

2x=(-25)+25

2x=0

x=0:2

x=0

tick cho mk nha bạn

a)2-x=17-(-5)

2-x=17+5

2-x=22

x=2-20

x=-20

b)x-12=-9-15

x-12=-24

x=(-24)+12

x=-12

c)11-(15+11)=x-(25-9)

11-26=x-16

-15=x-16

x=-15+16

x=1

d)x-25=(7-x)-(25+7)

x-25=(7-x)-32

2x-25=7-32

2x-25=-25

2x=(-25)+25

2x=0

x=0:2

x=0

a)2-x=17-(-5)

2-x=17+5

2-x=22

x=2-20

x=-20

b)x-12=-9-15

x-12=-24

x=(-24)+12

x=-12

c)11-(15+11)=x-(25-9)

11-26=x-16

-15=x-16

x=-15+16

x=1

d)x-25=(7-x)-(25+7)

x-25=(7-x)-32

2x-25=7-32

2x-25=-25

2x=(-25)+25

2x=0

x=0:2

x=0

a, 11 - ( 15 + 11 ) = x - ( 25 - 9 )

11-15-11=x-25+9

-15=x-16

x=1

b, 2 - x = 17 - ( - 5 )

2-x=22

x=-20

c, x - 12 = ( - 9 ) - 15

x-12=-24

x=-12

d, 9 - 25 = ( 7 - x ) - ( 25 + 7 )

(7-x)-32=-16

7-x=16

x=-9

#H

\(x\) \(\times\) \(\dfrac{4}{5}\) = 15

\(x\)         = 15 : \(\dfrac{4}{5}\)

\(x\)         = \(\dfrac{75}{4}\) 

\(\dfrac{12}{25}\) \(\times\) \(x\) = \(\dfrac{4}{10}\)

          \(x\) = \(\dfrac{4}{10}\) : \(\dfrac{12}{25}\)

          \(x\) = \(\dfrac{5}{6}\) 

\(\dfrac{6}{5}\): \(x\) = \(\dfrac{1}{3}\)\(x\) : \(\dfrac{2}{7}\) = \(\dfrac{3}{5}\) (xem lại đề bài)

\(25:x^5-16=3^{15}:3^{13}\)

=>\(25:x^5-16=3^2=9\)

=>\(25:x^5=25\)

=>\(x^5=1\)

=>x=1

d) x-5/1990 + x+5/1980 + x-25/1970=x-1990/5 + x-1980/15

 \(\Leftrightarrow\left(\frac{x-5}{1990}-1\right)+\left(\frac{x-15}{1980}-1\right)+\left(\frac{x-25}{1970}-1\right)=\left(\frac{x-1990}{5}-1\right)+\left(\frac{x-1980}{15}-1\right)+\left(\frac{x-1970}{25}-1\right)\)

\(\Leftrightarrow\frac{x-1995}{1990}+\frac{x-1995}{1980}+\frac{x-1995}{1970}=\frac{x-1995}{5}+\frac{x-1995}{15}+\frac{x-1995}{25}\).

\(\Leftrightarrow\frac{x-1995}{1990}+\frac{x-1995}{1980}+\frac{x-1995}{1970}-\frac{x-1995}{5}+\frac{x-1995}{15}+\frac{x-1995}{25}=0\)

\(\Leftrightarrow\left(x-1995\right)\left(\frac{1}{1990}+\frac{1}{1980}+\frac{1}{1970}-\frac{1}{5}+\frac{1}{15}+\frac{1}{25}\right)=0\)

\(\Leftrightarrow x-1995=0\).Do \(\frac{1}{1990}+\frac{1}{1980}+\frac{1}{1970}-\frac{1}{5}+\frac{1}{15}+\frac{1}{25}\ne0\)

\(\Leftrightarrow x=1995\)

P/s : Mấy câu trên cậu lấy máy tình cầm tay ra mà tính cũng ok mà :))

Giải cho cậu câu cuối : 

\(11-\left(-15+11\right)=x-\left(25-9\right)\)

\(11-\left(-4\right)=x-16\)

\(15=x-16\)

\(x=15+16\)

\(\Rightarrow x=31\)

tại vì tớ ko biết cách trình bày

Ok :)) Vậy làm hết cho cậu nhá :v

1/    \(-x-17=-31\)

       \(-x=-31+17\)

        \(-x=-14\)

         \(\Rightarrow x=14\)

2/    \(-15-x=-5\)

         \(x=-15-\left(-5\right)\)

        \(\Rightarrow x=-10\)

3/     \(\left(-3\right)-x=-15\)

         \(x=\left(-3\right)-\left(-15\right)\)

         \(\Rightarrow x=12\)

4/      \(x+\left(-31\right)=-45\)

         \(x=-45-\left(-31\right)\)

         \(\Rightarrow x=-14\)

5/  tớ làm trước đó rồi :))

=>5(3x-1)=10

=>3x-1=2

hay x=1