42−24+x=72
tính bằng hai cách
786 x ( 32 + 68 )
2904 x 15 + 2904 x 35
436 x 72 - 436 x 42
194 x ( 87 - 7 )
3332 : ( 4 x 49 )
72 : 9 : 8
( 15 x 24 ) : 6
25 x ( 36 : 9 )
C1:
a. 786 x ( 32 +68)
= 786 x 100
= 78600
b. 2904 x 15 + 2904 x 35
= 43560 + 101640
= 145200
c.436 x 72 - 436 x 42
= 31392 - 18312
= 13080
d.194 x (87-7)
= 194 x 80
=15520
e.3332 : (4x49)
= 3332 : 196
= 17
f. 72 : 9 : 8
= (72 : 9) :8
= 1
g. (15 x 24) : 6
= 360 :6
= 60
m. 25 x(36 :9)
= 25 x 4
= 100
Cách 2:
a.786 x 32 + 786 x 68
= 25152 + 53448
= 78600
b. 2904 x ( 15 + 35)
= 2904 x 50
= 145200
c.436 x (72 -42)
= 436 x 30
= 13080
d.194 x 87 - 194 x7
= 16878 - 1358
= 15520
e. 3332 : (4 x 49)
= 3332 : 4 : 49
= 833 : 49 = 17
f. 72 : 9 :8
= 72 : (9 x8)
= 72 : 72
=1
g. (15 x 24) :6
= 15 x (24 :6)
= 15 x 4
= 60
m. 25 x (36 :9)
= ( 25 x36 ):9
= 900 : 9
=100
3/6 x 8/12 x 15/20 x 24/30 x 35/42 x 48/56 x 63/72 x 80/90
Tính nhanh
rút gọn thành
1/2 x 2/3 x 3/4 x 4/5 x 5/6 x 6/7 x 7/8 x 8/9
1x2x3x4x5x6x7x8
__________________
2x3x4x5x6x7x8x9
gạch các số giống nhau ở tử và mẫu và bằng 1/9
2023 x 14 + 2023 x 83 +97
78 x 31 + 78 x 24 + 78 x 17 + 78 x 22 x 72
371 x 69 + 371 x 14 + 629 x 83
91 x 51 + 49 x 163 - 49 x 72
3 x 12 x 17 + 4 x 9 x 81 + 2 x 6 x 6
42 x 17 + 58 x 83 x 42 x 83 + 42 x 83 + 58 x 17
tính bằng cách hợp lý nhất
`@` `\text {Ans}`
`\downarrow`
`2023 \times 14 + 2023 \times 83+97`
`= 2023 \times (14+83) + 97`
`= 2023 \times 97 + 97`
`= 196231 +97`
`= 196328`
`78 \times 31+78 \times 24+78 \times 17+78 \times 22 \times 72`
`= 78 \times (31+24+17+22 \times 72)`
`= 78 \times (31+24+17+1584)`
`= 78 \times 1656`
`= 129168`
`371 \times 69+371 \times 14+629 \times 83`
`= 371 \times (69+14) + 629 \times 83`
`= 371 \times 83 + 629 \times 83`
`= 83 \times (371+629)`
`= 83 \times 1000`
`= 83000`
`91 \times 51+49 \times 163-49 \times 72`
`= 91 \times 51 + 49 \times (163-72)`
`= 91 \times 51+49 \times 91`
`= 91 \times (51+49)`
`= 91 \times 100`
`= 9100`
`3 \times 12 \times 17 + 4 \times 9 \times 81 + 2 \times 6 \times 6`
`= 9 \times 4 \times 17 + 4 \times 9 \times 81 + 4 \times 9 \times 2`
`= 9 \times 4 \times (17+81+2)`
`= 36 \times 100`
`= 3600`
`42 \times 17 + 58 \times 83 \times 42 \times 83 + 42 \times 83 + 17`
`= 17 \times (42+58) + 42 \times 83 \times (58 \times 83 +1)`
`= 17 \times 100 + 3486 \times 4815`
`= 1700 + 16785090`
`= 16786790`
VIẾT SỐ THÍCH HỢP VÀO Ô TRỐNG: a, 5 x ... / 6 x ... = 60/... = .../18 b, 84/96 = 42/ ... = .../24 = 7/ ... c, 12 : ... / 16 : ... = .../8 = 3/... d, 126/72 = 21/... = .../4
GIÚP EM HỨA SẼ TICK Ạ
b: 84/96=42/48=21/24=7/8
d: 126/72=21/12=7/4
b: =2376-376+3425-42
=2000+3383
=5383
c: =3145-145+246+4246+2347-347
=3000+2000+4492
=9492
e: =(72-72):A=0
\(\left(\dfrac{1}{12}+\dfrac{1}{20}+\dfrac{1}{30}+\dfrac{1}{42}+\dfrac{1}{56}+\dfrac{1}{72}+\dfrac{1}{90}\right)-x=\dfrac{-19}{24}\)
Ta có:
\(\left(\dfrac{1}{12}+\dfrac{1}{20}+\dfrac{1}{30}+\dfrac{1}{42}+\dfrac{1}{56}+\dfrac{1}{72}+\dfrac{1}{90}\right)-x=\dfrac{-19}{24}\)
\(\left(\dfrac{1}{3.4}+\dfrac{1}{4.5}+\dfrac{1}{5.6}+\dfrac{1}{6.7}+\dfrac{1}{7.8}+\dfrac{1}{8.9}+\dfrac{1}{9.10}\right)-x=\dfrac{-19}{24}\)\(\left(\dfrac{4-3}{3.4}+\dfrac{5-4}{4.5}+\dfrac{6-5}{5.6}+\dfrac{7-6}{6.7}+\dfrac{8-7}{7.8}+\dfrac{9-8}{8.9}+\dfrac{10-9}{9.10}\right)-x=\dfrac{-19}{24}\)
\(\left(\dfrac{1}{3}-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{6}+\dfrac{1}{6}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{8}+\dfrac{1}{8}-\dfrac{1}{9}+\dfrac{1}{9}-\dfrac{1}{10}\right)-x=\dfrac{-19}{24}\)\(\left(\dfrac{1}{3}-\dfrac{1}{10}\right)-x=\dfrac{-19}{24}\)
\(\dfrac{7}{30}-x=\dfrac{-19}{24}\)
\(x=\dfrac{7}{30}-\dfrac{-19}{24}\)
\(x=\dfrac{41}{40}\)
\(\left(\dfrac{1}{12}+\dfrac{1}{20}+\dfrac{1}{30}+\dfrac{1}{42}+\dfrac{1}{56}+\dfrac{1}{72}+\dfrac{1}{90}\right)-x=\dfrac{-19}{24}\)
\(\Leftrightarrow\left(\dfrac{1}{3.4}+\dfrac{1}{4.5}+\dfrac{1}{5.6}+\dfrac{1}{6.7}+\dfrac{1}{7.8}+\dfrac{1}{8.9}+\dfrac{1}{9.10}\right)-x=\dfrac{-19}{24}\)
\(\Leftrightarrow\left(\dfrac{1}{3}-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{6}+...+\dfrac{1}{8}-\dfrac{1}{9}+\dfrac{1}{9}-\dfrac{1}{10}\right)-x=\dfrac{-19}{24}\)
\(\Leftrightarrow\left(\dfrac{1}{3}-\dfrac{1}{10}\right)-x=\dfrac{-19}{24}\)
\(\Leftrightarrow\dfrac{7}{30}-x=\dfrac{-19}{24}\)
\(\Rightarrow x=\dfrac{7}{30}-\dfrac{-19}{24}\)
\(\Rightarrow x=\dfrac{41}{40}\)
( 1/3.4 +1/4.5+ 1/5.6+ 1/6.7+1/7.8+1/8.9+1/9.10)-x=-19/24
(1/3-1/4+1/4-1/5+1/5-1/6+1/6-1/7+1/7-1/8+1/8-1/9+1/9-1/10)-x=-19/24
(1/3-1/10)-x=-19/24
7/30-x=-19/24
x=7/30-(-19)/24
x=41/40
nếu dung tick cho mình nhá
g)18 . (-24) + 35 . 42 -18 . 76 + 35 . (-142)
h) 104 : (-13) - [ 56 - 220 : ( -4 )]
i)1010: {2500:[ 550 - (4 . 53 - 23 . 25) ]}
j) (72 + 32 . 42 )+(-145 ) + 45 -20230 + 12023
a, 18.(-24) + 35.42 - 18.76 + 35.(-142)
= [ 18.(-24) - 18.76] + (35.42 + 35(-142)]
= -18.[ 24 + 76] - 35.( 142 - 42)
= -18.100 - 35. 100
= - 100.(18 + 35)
= - 100. 53
= - 5300
h, 104 : (-13) - [56 - 220 : (-4)]
= 104 : (-13) - [ 56 + 55]
= -8 - 111
= - 119
j; 1010 : {2500 : [550 - (4.53 - 23.25)]}
= 1010 : {2500 : [550 - (212 - 575)]}
= 1010 : {2500 : [550 + 363]
= 1010 : { 2500 : 913}
= 1010 : \(\dfrac{2500}{913}\)
= 1010 x \(\dfrac{913}{2500}\)
= 368,852
Tìm ƯCLN của
a, 54 , 42 , và 48
b, 24 , 36 , 72
c, 180 , 168
d, 48 , 72
UCLN(54,42,48)=6;UCLN(24,36,72)=12
UCLN(180,168)=12;UCLN(48,72)=24
xrminhmk...
Viết sô thích hợp vào chỗ chấm điểm
A) 3/4=3*4/4*4=…\……
2/7=2*.../7*3=…\…
24/42=24:6/42:…=…\…
B) 2/3=6/…
18/24=6/…
2/7=8/…=…\35
3/5=…/20
32/24=…/3
48/72=…/9=2/…=…/24
A) 12/16
2*3; 6/21
42:6; 4/7
B) 6/9
6/8
8/28=10/35
12/20
4/3
6/9=2/3=16/28