Tim gia tri nguyen x,y
(x+1)^2 + 8y^2 = 42
tim gia tri x nguyen de bieu thuc (3x2-4x+x-1)/(3x+2) co gia tri nguyen
tim gia tri x nguyen de bieu thuc (3x3-4x2+x+1)/(x-4) co gia tri nguyen
tim cac gia tri nguyen cua x de gia tri bieu thuc y=2x^2+1/2x-1 la so nguyen
bai 1:Tim x,y,z \(\varepsilon\)Z ,sao cho :|x-y|+|y-z|+|z-x|+|z-t|+|t-x|=2003
bai 2:Cho bieu thuc:E=\(\frac{5-x}{x-2}\)tim gia tri nguyen cua x de
a) E co gia tri nguyen
b)E co gia tri nho nhat
Tim gia tri nguyen cua x de bieu thuc 42-x/x-15 co gia tri nho nhat
\(Tacó\) \(\frac{42-x}{x-15}=\frac{57-x-15}{x-15}\) =\(\frac{57}{x-15}-1\) suy ra x-15 thuộc ước 57 ......
tim gia tri nguyen cua x de bieu thuc:x^2+7/x+1 cung nhan gia tri la so nguyen
Đề bài có sai không bạn?
de bai sai hay sao ay
Bài lớp 8 hay sao ấy
1.Tim cac chu so x va y de so 1x8y2 chia het cho 36
2.tim cac gia tri nguyen cua n de phan so A=3.n+2/n-1 co gia tri la so nguyen
3.tim cac chu so x y thoa man
(x-2)^2.(x-3)^2=4
4.tim so tu nhien x biet
(x-5):3/100=20.x/100 +5
tim cac gia tri nguyen cua x de y nhan gia tri nguyen,biet :y=5x+9/x+3
Ta có : y = \(\dfrac{5x+9}{x+3}\)
Để y nhận giá trị nguyên thì: 5x + 9 \(⋮\) x + 3
=> 5. ( x + 3 ) + 9 - 15 \(⋮\) x + 3
=> 5. ( x + 3 ) - 6 \(⋮\) x + 3
=> 6 \(⋮\) x + 3 ( vì 5. ( x + 3 ) \(⋮\) x + 3 )
=> x + 3 \(\inƯ\left(6\right)=\left\{-6;-3;-2;-1;1;2;3;6\right\}\)
=> \(x\in\left\{-9;-6;-5;-4;-2;-1;0;3\right\}\)
Vậy : \(x\in\left\{-9;-6;-5;-4;-2;-1;0;3\right\}\) thì y nhận giá trị nguyên.
tim cac gia tri nguyen cua x de y nhan gia tri nguyen,biet :y=5x+9/x+3
\(y=\frac{5x+9}{x+3}=\frac{5x+15-6}{x+3}=\frac{5\left(x+3\right)-6}{x+3}=5-\frac{6}{x+3}\)
y nguyên khi \(\frac{6}{x+3}\) nguyên <=> 6 chia hết cho x+3
<=>\(x+3\inƯ\left(6\right)=\){-6;-3;-2;-1;1;2;3;6}
<=> \(x\in\){-9;-6;-5;-4;-2;-1;0;3}
bai1 :P=x+2/x+3-5/(x+3)(x-2)+1/2-x
a,Tim dkxd cua P
b,Rut gon bieu thuc P
c,tim x de P=-3/4
d,tim gia tri nguyen cua x de P cung co gia tri nguyen
e,tinh gia tri bieu thuc P khi x^2-9=0