\(\dfrac{3}{4}+\dfrac{2}{5}x4chia\dfrac{8}{3}\)
mình không có dấu chia mong mn thông cảm
Sos mn ơi
Tìm Y
\(\dfrac{11}{4}-y-\dfrac{2}{5}=\dfrac{1}{3}\). \(\dfrac{5}{3}x\left(\dfrac{3}{4}-y:\dfrac{2}{5}\right)=\dfrac{5}{8}\)
\(\dfrac{3}{2}xy-\dfrac{3}{4}xy+y=\dfrac{4}{5}\)
Câu đầu em xem lại đề bài sao có hai dấu bằng.
Câu 2:
\(\dfrac{3}{2}\) \(\times\)y - \(\dfrac{3}{4}\) \(\times\)y + y = \(\dfrac{4}{5}\)
y \(\times\) ( \(\dfrac{3}{2}\) - \(\dfrac{3}{4}\) + 1) = \(\dfrac{4}{5}\)
y \(\times\) (\(\dfrac{6}{4}\) - \(\dfrac{3}{4}\) + \(\dfrac{4}{4}\)) = \(\dfrac{4}{5}\)
y \(\times\) \(\dfrac{7}{4}\) = \(\dfrac{4}{5}\)
y = \(\dfrac{4}{5}\): \(\dfrac{7}{4}\)
y = \(\dfrac{16}{35}\)
điền dấu < = > vào chỗ chấm
a)\(\dfrac{2}{3}\)+\(\dfrac{1}{4}\)+\(\dfrac{5}{6}\)...\(\dfrac{7}{4}\)
b)\(\dfrac{4}{5}\)+\(\dfrac{2}{3}\)*2-\(\dfrac{1}{5}\)...\(\dfrac{1}{2}\)
c)\(\dfrac{1}{2}\)+\(\dfrac{1}{4}\)+\(\dfrac{1}{8}\)+\(\dfrac{1}{16}\)...\(\dfrac{15}{16}\)
d)\(\dfrac{1515:101}{2525:101}\)...\(\dfrac{3}{5}\)
(Bạn nào biết thì giải giúp mình nhé, lưu ý dấu "." là dấu nhân)
Tìm x, biết:
a) -\(\dfrac{5}{6}\) - x = \(\dfrac{2}{3}\)
b) \(\dfrac{2}{3}\)x + \(\dfrac{1}{2}\) = \(\dfrac{1}{10}\)
c) \(\dfrac{2}{9}\) - \(\dfrac{7}{8}\) . x = \(\dfrac{1}{3}\)
d) \(\dfrac{4}{5}\) + \(\dfrac{5}{7}\) : x = \(\dfrac{1}{6}\)
e) (\(\dfrac{2}{5}\) - \(1\dfrac{2}{3}\)) : x - \(\dfrac{3}{5}\) = \(\dfrac{2}{5}\)
f) 1 - (-\(\dfrac{3}{4}\) + x) . \(2\dfrac{2}{3}\) = 0
Lời giải:
a.
$x=\frac{-5}{6}-\frac{2}{3}=\frac{-3}{2}$
b.
$\frac{2}{3}x=\frac{1}{10}-\frac{1}{2}=\frac{-2}{5}$
$x=\frac{-2}{5}: \frac{2}{3}=\frac{-3}{5}$
c.
$\frac{7}{8}x=\frac{2}{9}-\frac{1}{3}=\frac{-1}{9}$
$x=\frac{-1}{9}: \frac{7}{8}=\frac{-8}{63}$
d.
$\frac{5}{7}: x=\frac{1}{6}-\frac{4}{5}=\frac{-19}{30}$
$x=\frac{5}{7}: \frac{-19}{30}=\frac{-150}{133}$
e.
$(\frac{2}{5}-1\frac{2}{3}):x=\frac{2}{5}+\frac{3}{5}=1$
$\frac{-19}{15}: x=1$
$x=\frac{-19}{15}:1 =\frac{-19}{15}$
f.
$(-\frac{3}{4}+x).2\frac{2}{3}=1$
$\frac{-3}{4}+x=1: 2\frac{2}{3}=\frac{3}{8}$
$x=\frac{3}{8}+\frac{3}{4}=\frac{9}{8}$
\(\text{\dfrac{3}{4}+ x ×}\dfrac{3}{2}=2\)
MN giải gúp mình với. Cảm ơn
Bài3:Tìm x
a,\(\dfrac{x}{7}\)=\(\dfrac{6}{12}\) b,\(\dfrac{-5}{x}\)=\(\dfrac{20}{28}\) c,\(\dfrac{x-2}{8}\)=\(\dfrac{3}{4}\) d,\(\dfrac{x}{-5}\)=\(\dfrac{-5}{x}\)
các ban giúp mình nha, cảm ơn các bạn
\(a,\dfrac{x}{7}=\dfrac{6}{12}\\ x\cdot12=7\cdot6=42\\ x=42:12\\ x=\dfrac{7}{2}\\ b,\dfrac{-5}{x}=\dfrac{20}{28}\\ x\cdot20=\left(-5\right)\cdot28=-140\\ x=\left(-140\right):20\\ x=-7\\ c,\dfrac{x-2}{8}=\dfrac{3}{4}\\ \left(x-2\right)4=8\cdot3=24\\ x-2=24:4\\ x-2=6\\ x=6+2\\ x=8\\ d,\dfrac{x}{-5}=\dfrac{-5}{x}\\ x^2=\left(-5\right)\cdot\left(-5\right)=25\\ x=5\)
cho M=\(\dfrac{1}{2}\cdot\dfrac{3}{4}\cdot\dfrac{5}{6}\cdot...\cdot\dfrac{99}{100}\)
N=\(\dfrac{2}{3}\cdot\dfrac{4}{5}\cdot\dfrac{6}{7}\cdot...\cdot\dfrac{100}{101}\)
chứng minh rằng: M<\(\dfrac{1}{10}\)
Em cần gấp câu trả lời cho bài toán này, mong đc mn giúp đỡ (nếu được xin trả lời trước 12h ngày 10/5 giúp em ạ). Cảm ơn mn.
Giúp mình với
a,\(\dfrac{-8}{9}\)-(\(\dfrac{6}{5}\)-\(\dfrac{8}{9}\))
b, \(\dfrac{-4}{9}\)+\(\sqrt{\dfrac{9}{16}}\)-\(\dfrac{4}{5}\).\(\dfrac{-1^2}{2}\)+25%
c,\(\dfrac{2}{3}\)+(\(\dfrac{-3}{4}\)).\(\dfrac{4}{9}\)
d,16\(\dfrac{3}{4}\) - (-\(\dfrac{6}{5}\)) - 28\(\dfrac{3}{4}\):(-\(\dfrac{6}{5}\))
a: \(=\dfrac{-8}{9}-\dfrac{6}{5}+\dfrac{8}{9}=-\dfrac{6}{5}\)
c: \(=\dfrac{2}{3}-\dfrac{1}{3}=\dfrac{1}{3}\)
6. Điền dấu >; <; = vào chỗ chấm:
\(\dfrac{5}{15}\) ...............\(\dfrac{12}{8}\)
\(\dfrac{5}{15}\) ............... \(\dfrac{3}{9}\)
\(\dfrac{5}{15}\) ................ \(\dfrac{5}{8}\)
Giúp mình nhanh với ạ, làm đúng mình tick cho ạ
Điền dấu thích hợp (>,<,=) vào chỗ trống.
a,\(\dfrac{-3}{5}+\dfrac{-11}{5}...\dfrac{-7}{3}+\dfrac{4}{7}\)
b,\(\dfrac{-7}{11}+\dfrac{-15}{11}...\dfrac{-4}{3}+\dfrac{-7}{5}\)
Giúp mk nha :>>. Mk cảm ơn.