\(a)P=\left(\dfrac{x^2+2}{x^3-1}+\dfrac{x+1}{x^2+x+1}+\dfrac{1}{1-x}\right).\left(\dfrac{x^2}{x+1}+1\right).\left(x\ne1;x\ne-1\right).\\ P=\dfrac{x^2+2+x^2-1-x^2-x-1}{\left(x-1\right)\left(x^2+x+1\right)}.\dfrac{x^2+x+1}{x+1}.\\ P=\dfrac{x^2-x}{x-1}.\dfrac{1}{x+1}.\\ P=\dfrac{x\left(x-1\right)}{x-1}.\dfrac{1}{x+1}.\\ P=x.\dfrac{1}{x+1}.\\ P=\dfrac{x}{x+1}.\)

\(P=\dfrac{1}{4}.\Rightarrow\dfrac{x}{x+1}=\dfrac{1}{4}.\\ \Leftrightarrow4x-x-1=0.\\ \Leftrightarrow3x-1=0.\\ \Leftrightarrow x=\dfrac{1}{3}\left(TM\right).\)

1.A. Ta thấy để hàm số xác định thì x-m\(\ne\)0 hay x\(\ne\)m mà vì x\(\in\)(0,1) nên để x\(\ne\)m thì m\(\notin\)(0,1)=>m>=1 hoặc m<=0

2A để A giao B khác 0 thì 2m-1<=m+3 hay m<=4

3C.A giao B =A khi \(\left\{{}\begin{matrix}m< =-1\\m+5>=3\end{matrix}\right.\)\(\Leftrightarrow\left\{{}\begin{matrix}m< =1\\m>=-2\end{matrix}\right.\)

\(U=IR=1,2\cdot10=12V\)

Chọn C

Câu B : 125 độ nha 

Câu b nha bạn

Chọn B

\(2,C\\ 1,C\\ 8,B\)

Câu 1: C

Câu 2: C

Câu 8: B

Câu 11: A

Câu 12: C

21 bought (for)

22 spent

23 listening

24 to go

25 reading

26 cleaned

27 went

28 is playing

29 lived

30 received

31 talk

32 met

33 to go

34 stay

35 collecting

36 playing

37 will see

38 play

39 to go

40 to eat

\(3x-2\sqrt{3x-2}=1\left(đk:x\ge\dfrac{2}{3}\right)\)

\(\Leftrightarrow2\sqrt{3x-2}=3x-1\)

\(\Leftrightarrow4\left(3x-2\right)=9x^2-6x+1\)

\(\Leftrightarrow9x^2-18x+9=0\)

\(\Leftrightarrow9\left(x-1\right)^2=0\Leftrightarrow x=1\left(tm\right)\)