Em xem lại đề nha

=x(x-2)-9y(y-1)

=(x-2)(y-1)(x-9y)

1) \(x\left(4x+1\right)\)

2) \(3\left(x-3y\right)\)

3) \(\left(2x+1\right)\left(2x+1+2\right)=\left(2x+1\right)\left(2x+3\right)\)

2) \(x^4-5x^2+4\)

\(=x^4-x^2-4x^2+4\)

\(=x^2\left(x^2-1\right)-4\left(x^2-1\right)\)

\(=\left(x^2-1\right)\left(x^2-4\right)\)

\(=\left(x-1\right)\left(x+1\right)\left(x-2\right)\left(x+2\right)\)

a: =(2x-3y)^2-4(2x-3y)

=(2x-3y)(2x-3y-4)

b: =3x^2+21x-x-7

=(x+7)(3x-1)

c: =(3x-1)^4+2(3x-1)^2+1

=[(3x-1)^2+1]^2

d: =2x^3-2x^2-x^2+x+x-1

=(x-1)(2x^2-x+1)

a,\(x^2-y^2+2x+1=\left(x^2-2x+1\right)-y^2=\left(x+1\right)^2-y^2=\left(x+1-y\right)\left(x+1+y\right)\)b

\(4x^2-17xy+13y^2=\left(4x^2-4xy\right)+\left(13y^2-13xy\right)=4x\left(x-y\right)-13y\left(x-y\right)\)\(=\left(4x-13y\right)\left(x-y\right)\)

Nếu thấy đúng thì tick nha bạn,cảm ơn.

\(=4x^2-4xy-13xy+13y^2=4x\left(x-y\right)-13y\left(x-y\right)=\left(4x-13y\right)\left(x-y\right)\)

\(4x^2-17xy+13y^2=\left(4x^2-4xy\right)+\left(13y^2-13xy\right)=4x\left(x-y\right)+13y\left(x-y\right)=\left(4x+13y\right)\left(x-y\right)\)

\(4x^2-17xy+13y^2\\ =4x^2-4xy-13xy+13y^2\\ =4x\left(x-y\right)-13y\left(x-y\right) \\ =\left(x-y\right)\left(4x-13y\right)\)

a) Ta có: \(x^2-2xy+y^2-2x+2y\)

\(=\left(x-y\right)^2-2\left(x-y\right)\)

\(=\left(x-y\right)\left(x-y-2\right)\)

b) Ta có: \(x^2-4x+4-x^2y+2xy\)

\(=\left(x-2\right)^2-xy\left(x-2\right)\)

\(=\left(x-2\right)\left(x-2-xy\right)\)

c) Ta có: \(ax^2-3axy-x^2+6xy-9y^2\)

\(=ax\left(x-3y\right)-\left(x^2-6xy+9y^2\right)\)

\(=ax\left(x-3y\right)-\left(x-3y\right)^2\)

\(=\left(x-3y\right)\left(ax-x+3y\right)\)

d) Ta có: \(2a^2x-5a^2y-4x^2+30xy-25y^2\)

\(=a^2\left(2x-5y\right)-\left(4x^2-30xy+25y^2\right)\)

\(=a^2\left(2x-5y\right)-\left(2x-5y\right)^2\)

\(=\left(2x-5y\right)\left(a^2-2x+5y\right)\)