tim gtnn cua x(x+1)(x+2)(x+3)
tim GTNN cua /x+1/+/x+2/+/x+3/+/x+4/+2016
Tim GTNN cua biểu thức : A=|x-1|+|x-2|+|x-3|
tim gtnn cua x^4+3.x^2+1
x^4+3x^2+1>=1
Dấu = xảy ra khi x=0
tim GTNN cua bt sau
A=(x-1)(x+2)(x+3)(x+6)
A=[(x-1)(x+6)][(x+2)(x+3)]
=(x2+5x-6)(x2+5x+6)
=(x2+5x)2-36
Ta thấy (x2+5x)2 >=0 nên (x2+5x)2-36 >=-36
Vậy GTNN của A là -36
voi x > 1/2
tim gtnn cua D=x/3 + 5/2x-1
tim GTNN cua M=\x-\(\dfrac{2}{3}\)/+1-x
tim gtnn cua bt A
A= \((x-1)^4+(x-3)^4+6(x-1)^2\left(x-3\right)^2\)
tim GTNN cua A= x^2-3/(x-2)^2
\(A=\frac{x^2-3}{\left(x-2\right)^2}=\frac{-3x^2+12x-12+4x^2-12x+9}{\left(x-2\right)^2}\)
\(=-3+\frac{4x^2-12x+9}{\left(x-2\right)^2}=-3+\frac{\left(2x-3\right)^2}{\left(x-2\right)^2}\ge-3\)
Vậy GTNN là - 3 đạt được khi x = 1,5
1, tim GTLN cua A=13/(x+5)^2+7
2, tim GTNN cua B=|x+2017|+(y+3)^2+2017
3, cho a-1/2=b+3/4=c-5/6 va 5a-3b-4c=46. Tim a,b,c.