tìm x:
x : 10 x 100 = 10000
Câu 10. Tìm X:
X : 0,5 + X : 0,125 = 9,78
tìm x:
x : 33 = \(\dfrac{9}{66}\) \(\dfrac{4}{5}\) x \(x\) = \(\dfrac{10}{11}\) :\(\dfrac{3}{4}\)
\(x:33=\dfrac{9}{66}\)
\(x=\dfrac{9}{66}\times33\)
\(x=\dfrac{9}{2}\)
\(\dfrac{4}{5}\times x=\dfrac{10}{11}:\dfrac{3}{4}\)
\(\dfrac{4}{5}\times x=\dfrac{40}{33}\)
\(x=\dfrac{40}{33}:\dfrac{4}{5}\)
\(x=\dfrac{50}{33}\)
#Đạt Đang Bận Thở
tìm x:
X:1/3=1/2+1/3 (X:2/3):2/5=7/10
x : 1/3 = 1/2 +1/3
=>x:1/3=5/6
=>x=5/6 x 1/3
=>x=5/18
(x:2/3):2/5=7/10
=>x:2/3=7/10 x 2/5
=>x:2/3=7/25
=>x=7/25x2/3
=>x=14/75
CHÚC BẠN HỌC TỐT
tìm x:
X:1/3=1/2+1/3 (X:2/3):2/5=7/10
x:1/3=1/2+1/3
x:1/3=5/6
x =5/6.1/3
x =5/18
(x:2/3):2/5=7/10
x:2/3 =7/10.2/5
x:2/3 =7/25
x:2/3 =7/25.2/3
x:2/3 =14/75
Tính nhanh:
a, 1000 : 100 = ?
b, 75 x 100 = ?
c, 900 x 10 = ?
d, 8 x 100 : 10 : 10 x 10000 = ?
`a, 1000 : 100 = 10`
`b, 75 xx 100 = 7500`
`c, 900 xx 10 = 9000`
`d, 8 xx 100 : 10 : 10 xx 10000 = 80000`
\(a,1000:100=10\\ b,75\times100=7500\\ c,900\times10=9000\\ d,8\times100:10:10\times10000\\ =800:10:10\times10000=8\times10000=80000\)
a)\(1000:100=10\)
b)\(75\times100=7500\)
c)\(900\times10=9000\)
d)\(8\times100:10:10\times10000=8\times10000=80000\)
X:X+4/X+5=17/100
a) Tìm x:
x . 3,5 + x . 12,5 = 396,8
b) Tính bằng cách hợp lí nhất:
20,11 : 0,1 + 20,11: 10 -20,11 : (2,1 : 21)
a)x . 3,5 + x . 12,5 = 396,8
x (3,5+12,5) =396,8
x. 16 =396,8
x = 396,8 :16
x= 24,8
b) 20,11 : 0,1 + 20,11: 10 -20,11 : (2,1 : 21) =2,011
Bài 1 :Phân tích đa thức sau thành nhân tử
(12x2+6x)(y+z)+(12x2+6x)(y-z)
Bài 2:tìm x:
x(x-6)+10(x-6)=0
1.
\(\left(12x^2+6x\right)\left(y+z\right)+\left(12x^2+6x\right)\left(y-z\right)\\ =\left(12x^2+6x\right)\left(y+z+y-z\right)\\ =2y\left(12x^2+6x\right)\\ =2y.6x\left(2x+1\right)\\ =12xy\left(2x+1\right)\)
2.
\(x\left(x-6\right)+10\left(x-6\right)=0\\ \Leftrightarrow\left(x-6\right)\left(x+10\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=6\\x=-10\end{matrix}\right.\)
Vậy \(x\in\left\{6;-10\right\}\) là nghiệm của pt
Bài 1:
Ta có: \(\left(12x^2+6x\right)\left(y+z\right)+\left(12x^2+6x\right)\left(y-z\right)\)
\(=\left(12x^2+6x\right)\left(y+z+y-z\right)\)
\(=6x\left(2x+1\right)\cdot2y\)
\(=12xy\left(2x+1\right)\)
Bài 2:
Ta có: \(x\left(x-6\right)+10\left(x-6\right)=0\)
\(\Leftrightarrow\left(x-6\right)\left(x+10\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=6\\x=-10\end{matrix}\right.\)
Tính:
10*10=
100*100=
1000*1000=
10000*10000=
100000*100000=
1000000*1000000=
10000000*10000000=
\(10\cdot10=100\)
\(100\cdot100=10000\)
Tính:
10*10=100
100*100=10000
1000*1000=1000000
10000*10000=100000000
100000*100000=10000000000
1000000*1000000=1000000000000
10000000000*10000000000=100000000000000000000